[{"_1":2,"_188":-5,"_189":-5},"loaderData",{"_3":4,"_8":9},"root",{"_5":6,"_7":-5},"url","https://prouniversitario.com/exercicios/c6cd0818-cf81-414d-bfaf-8ef1afad60db","user","pages/questions/show/index",{"_10":11,"_12":13,"_38":39,"_40":41,"_63":178,"_179":180},"comments",[],"question",{"_14":15,"_16":15,"_17":18,"_19":20,"_35":15,"_36":37},"correctOptionId","","difficulty","id","c6cd0818-cf81-414d-bfaf-8ef1afad60db","options",[21,27,31],{"_17":22,"_23":24,"_25":26},"946df006-2b67-4316-aee1-969b41a2d958","label","A","text","{-1, 2}",{"_17":28,"_23":29,"_25":30},"c059e80f-5fb8-44f6-b0b0-7568cf36474e","B","{-2, 1}",{"_17":32,"_23":33,"_25":34},"41cd6ef7-4bf2-4da3-b58d-41412712a5e4","C","{0, 3}","solution_explanation","statement","Resolva a equação \\arctan(????^2−2????) = \\frac{\\pi}{4}. Justifique a resolução.

Encontrar as soluções da equação dada.
Justificar a resolução.","relatedVideos",[],"similarQuestions",[42,104,121,141,161],{"_14":15,"_16":15,"_17":43,"_19":44,"_35":15,"_36":62,"_63":64},"0b6f4c25-a5b8-4e25-8a27-f76b5729b64e",[45,48,51,54,58],{"_17":46,"_23":24,"_25":47},"3b01fd8f-e84b-4147-9feb-3ec5370c763b","0",{"_17":49,"_23":29,"_25":50},"b0be23fe-9158-4197-9b80-e7eb41af9c70","1",{"_17":52,"_23":33,"_25":53},"b8eed276-b85e-4c19-b7a9-8f92bb43f3ca","2",{"_17":55,"_23":56,"_25":57},"0a08415b-67cf-4f3c-a504-651527fbefcd","D","3",{"_17":59,"_23":60,"_25":61},"2c0050aa-0652-472e-8fd6-254c6aaa4f44","E","5","Para que o polinômio 26x^{3} + 4x^{2} - 2mx + (m - 1) seja divisível por x - 3, o valor da raiz quadrada do módulo de m deve ser igual a","tags",[65,88,96],{"_17":66,"_67":68,"_69":70,"_71":72,"_73":74,"_75":76,"_77":76,"_78":79,"_86":87},"460c64fa-d231-4570-b316-17533b8b28f8","name","Pré-cálculo","alias","pre-calculo","tag_group_id","c1ce2cf2-b217-4cc7-8182-81c56bd3522d","parent_id","b34d4581-a7e7-4d5d-be00-abe3d9a69032","created_at","2025-05-28T00:13:52.643631+00:00","updated_at","metadata",{"_80":81,"_82":83,"_84":85},"childrenCount",4,"content_count",0,"question_count",3555,"slug","pre-calculo-2",{"_17":89,"_67":90,"_69":91,"_71":72,"_73":-5,"_75":92,"_77":92,"_78":93,"_86":91},"9772e958-72c6-4499-ad47-877cf94d670d","Exatas","exatas","2025-04-29T01:56:45.284172+00:00",{"_80":94,"_82":83,"_84":95},18,135489,{"_17":74,"_67":97,"_69":98,"_71":72,"_73":89,"_75":99,"_77":99,"_78":100,"_86":103},"Matemática","matematica","2025-04-29T02:19:12.828432+00:00",{"_80":101,"_82":83,"_84":102},8,40655,"matematica-10",{"_14":15,"_16":15,"_17":105,"_19":106,"_35":15,"_36":119,"_63":120},"66bd27e3-ce98-4b83-a244-55e758adf328",[107,110,113,116],{"_17":108,"_23":24,"_25":109},"6a31809c-23f4-49f8-93ad-40c26d3192d1","4",{"_17":111,"_23":29,"_25":112},"9f7de9bd-67be-4d06-93a7-4723f7a4ea04","8",{"_17":114,"_23":33,"_25":115},"525dd39a-67b7-432a-b2ff-adeb035c0443","10",{"_17":117,"_23":56,"_25":118},"550c6bc7-56c0-4be3-8330-9480fc55da2f","25","As raízes positivas da equação 4x^2 - 10x + 9 = 0 são as medidas das bases de um trapézio isósceles cuja altura é a soma dessas mesmas raízes. A área desse trapézio é",[65,88,96],{"_14":15,"_16":15,"_17":122,"_19":123,"_35":15,"_36":139,"_63":140},"80b083f3-eaf0-437e-af93-22ab13ad2012",[124,127,130,133,136],{"_17":125,"_23":24,"_25":126},"61b623c6-6a42-40da-b145-6dae697ac80c","2222x + 252-",{"_17":128,"_23":29,"_25":129},"642e358a-93cb-493b-bccb-c32933c5fd40","2444x + 252+",{"_17":131,"_23":33,"_25":132},"d4094d52-329a-4785-8270-238a3c7afd9c","444x + 252-",{"_17":134,"_23":56,"_25":135},"0eaec174-6ab6-488b-8580-43ef0050f4dc","222x + 252+",{"_17":137,"_23":60,"_25":138},"98319542-cbbc-4f6d-aae8-77cac9dfa27b","2444x + 252- -","Na divisão do polinômio 4x^3 - 26x^2 + 8x - 10 pelo divisor 2x^2 - 3x + 2, o resto multiplicado por 2 é",[65,88,96],{"_14":15,"_16":15,"_17":142,"_19":143,"_35":15,"_36":159,"_63":160},"a30fdb2c-b621-49bc-a88f-6d9d8be3119a",[144,147,150,153,156],{"_17":145,"_23":24,"_25":146},"5308af1d-e65c-40cd-94ce-61ce2ef1190c","1 e 2",{"_17":148,"_23":29,"_25":149},"995abf5e-986f-4655-a951-701cd6d2b5cc","1 e 2-",{"_17":151,"_23":33,"_25":152},"bd1c8c10-4c28-4a79-b759-f687c00376e5","1- e 3",{"_17":154,"_23":56,"_25":155},"2dcb4dec-5ad1-4cfe-946a-6c2df3c3b02e","1- e 3-",{"_17":157,"_23":60,"_25":158},"5752cc33-b93d-4f7e-adc4-5a8d1bf618fc","1 e 3","Considere o polinômio 3x^{2} + 2x + bx + c, tal que P(1) = 2 e P(2) = 6. Assim, os valores de b e c são, respectivamente,",[65,88,96],{"_14":15,"_16":15,"_17":162,"_19":163,"_35":15,"_36":176,"_63":177},"bcba27c1-092c-4a9f-b7c8-d7d3cf1ca51f",[164,167,170,173],{"_17":165,"_23":24,"_25":166},"6c1a2c64-f2b8-4883-ac05-22f20d7d44db","n é par e m é par.",{"_17":168,"_23":29,"_25":169},"7a9615d0-bd4c-45f9-89e9-dff76c754eb7","n é ímpar e m é ímpar.",{"_17":171,"_23":33,"_25":172},"c5c15099-db49-484a-a311-12511039c191","n é par e m é ímpar.",{"_17":174,"_23":56,"_25":175},"b8372ae9-4099-4195-89fd-b6940f742c68","n é ímpar e m é par.","Considere o polinômio n mp(x) = x^2 + x + 1, em que n e m são números inteiros. Se o resto da divisão de p(x) por x + 1 é igual a 3, então",[65,88,96],[65,88,96],"tagsTree",[181],{"_17":89,"_67":90,"_69":91,"_71":72,"_73":-5,"_75":92,"_77":92,"_78":93,"_86":91,"_182":183},"children",[184],{"_17":74,"_67":97,"_69":98,"_71":72,"_73":89,"_75":99,"_77":99,"_78":100,"_86":103,"_182":185},[186],{"_17":66,"_67":68,"_69":70,"_71":72,"_73":74,"_75":76,"_77":76,"_78":79,"_86":87,"_182":187},[],"actionData","errors"]

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