[{"_1":2,"_194":-5,"_195":-5},"loaderData",{"_3":4,"_8":9},"root",{"_5":6,"_7":-5},"url","https://prouniversitario.com/exercicios/cb7c8e24-0a98-4160-a6bf-715237258678","user","pages/questions/show/index",{"_10":11,"_12":13,"_46":47,"_48":49,"_69":184,"_185":186},"comments",[],"question",{"_14":15,"_16":15,"_17":18,"_19":20,"_43":15,"_44":45},"correctOptionId","","difficulty","id","cb7c8e24-0a98-4160-a6bf-715237258678","options",[21,27,31,35,39],{"_17":22,"_23":24,"_25":26},"98bdcab9-8561-4f53-9d93-631a94b3ace2","label","A","text","S = {x ϵ R / x > 5}",{"_17":28,"_23":29,"_25":30},"ff614426-2615-40ee-9b1a-6cc902efac44","B","S = {x ϵ R / 2 < x < 3 ou x < 5}",{"_17":32,"_23":33,"_25":34},"c25aa3ca-e62a-4930-b2ea-2caa634cb62c","C","S = {x ϵ R / x < 3 ou x > 5}",{"_17":36,"_23":37,"_25":38},"019d22ec-9ebc-4a07-8c09-982ea0bf0d1a","D","S = {x ϵ R / 2 < x < 3}",{"_17":40,"_23":41,"_25":42},"9d8c174d-15ca-44bc-aced-b60f74cda133","E","S = {x ϵ R / 2 < x < 3 ou x > 5}","solution_explanation","statement","

O conjunto solução da inequação produto (2x - 10) (x^{2} - 5x + 6) > 0 é:

","relatedVideos",[],"similarQuestions",[50,110,127,147,167],{"_14":15,"_16":15,"_17":51,"_19":52,"_43":15,"_44":68,"_69":70},"0b6f4c25-a5b8-4e25-8a27-f76b5729b64e",[53,56,59,62,65],{"_17":54,"_23":24,"_25":55},"3b01fd8f-e84b-4147-9feb-3ec5370c763b","0",{"_17":57,"_23":29,"_25":58},"b0be23fe-9158-4197-9b80-e7eb41af9c70","1",{"_17":60,"_23":33,"_25":61},"b8eed276-b85e-4c19-b7a9-8f92bb43f3ca","2",{"_17":63,"_23":37,"_25":64},"0a08415b-67cf-4f3c-a504-651527fbefcd","3",{"_17":66,"_23":41,"_25":67},"2c0050aa-0652-472e-8fd6-254c6aaa4f44","5","Para que o polinômio 26x^{3} + 4x^{2} - 2mx + (m - 1) seja divisível por x - 3, o valor da raiz quadrada do módulo de m deve ser igual a","tags",[71,94,102],{"_17":72,"_73":74,"_75":76,"_77":78,"_79":80,"_81":82,"_83":82,"_84":85,"_92":93},"460c64fa-d231-4570-b316-17533b8b28f8","name","Pré-cálculo","alias","pre-calculo","tag_group_id","c1ce2cf2-b217-4cc7-8182-81c56bd3522d","parent_id","b34d4581-a7e7-4d5d-be00-abe3d9a69032","created_at","2025-05-28T00:13:52.643631+00:00","updated_at","metadata",{"_86":87,"_88":89,"_90":91},"childrenCount",4,"content_count",0,"question_count",3555,"slug","pre-calculo-2",{"_17":95,"_73":96,"_75":97,"_77":78,"_79":-5,"_81":98,"_83":98,"_84":99,"_92":97},"9772e958-72c6-4499-ad47-877cf94d670d","Exatas","exatas","2025-04-29T01:56:45.284172+00:00",{"_86":100,"_88":89,"_90":101},18,135489,{"_17":80,"_73":103,"_75":104,"_77":78,"_79":95,"_81":105,"_83":105,"_84":106,"_92":109},"Matemática","matematica","2025-04-29T02:19:12.828432+00:00",{"_86":107,"_88":89,"_90":108},8,40655,"matematica-10",{"_14":15,"_16":15,"_17":111,"_19":112,"_43":15,"_44":125,"_69":126},"66bd27e3-ce98-4b83-a244-55e758adf328",[113,116,119,122],{"_17":114,"_23":24,"_25":115},"6a31809c-23f4-49f8-93ad-40c26d3192d1","4",{"_17":117,"_23":29,"_25":118},"9f7de9bd-67be-4d06-93a7-4723f7a4ea04","8",{"_17":120,"_23":33,"_25":121},"525dd39a-67b7-432a-b2ff-adeb035c0443","10",{"_17":123,"_23":37,"_25":124},"550c6bc7-56c0-4be3-8330-9480fc55da2f","25","As raízes positivas da equação 4x^2 - 10x + 9 = 0 são as medidas das bases de um trapézio isósceles cuja altura é a soma dessas mesmas raízes. A área desse trapézio é",[71,94,102],{"_14":15,"_16":15,"_17":128,"_19":129,"_43":15,"_44":145,"_69":146},"80b083f3-eaf0-437e-af93-22ab13ad2012",[130,133,136,139,142],{"_17":131,"_23":24,"_25":132},"61b623c6-6a42-40da-b145-6dae697ac80c","2222x + 252-",{"_17":134,"_23":29,"_25":135},"642e358a-93cb-493b-bccb-c32933c5fd40","2444x + 252+",{"_17":137,"_23":33,"_25":138},"d4094d52-329a-4785-8270-238a3c7afd9c","444x + 252-",{"_17":140,"_23":37,"_25":141},"0eaec174-6ab6-488b-8580-43ef0050f4dc","222x + 252+",{"_17":143,"_23":41,"_25":144},"98319542-cbbc-4f6d-aae8-77cac9dfa27b","2444x + 252- -","Na divisão do polinômio 4x^3 - 26x^2 + 8x - 10 pelo divisor 2x^2 - 3x + 2, o resto multiplicado por 2 é",[71,94,102],{"_14":15,"_16":15,"_17":148,"_19":149,"_43":15,"_44":165,"_69":166},"a30fdb2c-b621-49bc-a88f-6d9d8be3119a",[150,153,156,159,162],{"_17":151,"_23":24,"_25":152},"5308af1d-e65c-40cd-94ce-61ce2ef1190c","1 e 2",{"_17":154,"_23":29,"_25":155},"995abf5e-986f-4655-a951-701cd6d2b5cc","1 e 2-",{"_17":157,"_23":33,"_25":158},"bd1c8c10-4c28-4a79-b759-f687c00376e5","1- e 3",{"_17":160,"_23":37,"_25":161},"2dcb4dec-5ad1-4cfe-946a-6c2df3c3b02e","1- e 3-",{"_17":163,"_23":41,"_25":164},"5752cc33-b93d-4f7e-adc4-5a8d1bf618fc","1 e 3","Considere o polinômio 3x^{2} + 2x + bx + c, tal que P(1) = 2 e P(2) = 6. Assim, os valores de b e c são, respectivamente,",[71,94,102],{"_14":15,"_16":15,"_17":168,"_19":169,"_43":15,"_44":182,"_69":183},"bcba27c1-092c-4a9f-b7c8-d7d3cf1ca51f",[170,173,176,179],{"_17":171,"_23":24,"_25":172},"6c1a2c64-f2b8-4883-ac05-22f20d7d44db","n é par e m é par.",{"_17":174,"_23":29,"_25":175},"7a9615d0-bd4c-45f9-89e9-dff76c754eb7","n é ímpar e m é ímpar.",{"_17":177,"_23":33,"_25":178},"c5c15099-db49-484a-a311-12511039c191","n é par e m é ímpar.",{"_17":180,"_23":37,"_25":181},"b8372ae9-4099-4195-89fd-b6940f742c68","n é ímpar e m é par.","Considere o polinômio n mp(x) = x^2 + x + 1, em que n e m são números inteiros. Se o resto da divisão de p(x) por x + 1 é igual a 3, então",[71,94,102],[71,94,102],"tagsTree",[187],{"_17":95,"_73":96,"_75":97,"_77":78,"_79":-5,"_81":98,"_83":98,"_84":99,"_92":97,"_188":189},"children",[190],{"_17":80,"_73":103,"_75":104,"_77":78,"_79":95,"_81":105,"_83":105,"_84":106,"_92":109,"_188":191},[192],{"_17":72,"_73":74,"_75":76,"_77":78,"_79":80,"_81":82,"_83":82,"_84":85,"_92":93,"_188":193},[],"actionData","errors"]

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