[{"_1":2,"_186":-5,"_187":-5},"loaderData",{"_3":4,"_6":7},"root",{"_5":-5},"user","pages/questions/show/index",{"_8":9,"_10":11,"_36":37,"_38":39,"_61":176,"_177":178},"comments",[],"question",{"_12":13,"_14":13,"_15":16,"_17":18,"_33":13,"_34":35},"correctOptionId","","difficulty","id","d8b47970-d088-419e-907b-1f7b9e519dff","options",[19,25,29],{"_15":20,"_21":22,"_23":24},"f694f000-ca82-4ad5-9533-59e2fd1071dd","label","A","text","x = 0, 2; x = 0 (triple root), 3, -3",{"_15":26,"_21":27,"_23":28},"c1815609-121e-48d4-ae44-9026bf836260","B","x = 0, 2; x = 0 (double root), 3, -3",{"_15":30,"_21":31,"_23":32},"c5195121-ec4a-4fa7-9f83-984c4315941f","C","x = 0, 2; x = 0 (triple root), 3","solution_explanation","statement","

Find the roots of the following polynomials: x(x^{2} – 4x + 4) = 0 and f_{2}(x) = x^{5} – 9x^{3}

","relatedVideos",[],"similarQuestions",[40,102,119,139,159],{"_12":13,"_14":13,"_15":41,"_17":42,"_33":13,"_34":60,"_61":62},"0b6f4c25-a5b8-4e25-8a27-f76b5729b64e",[43,46,49,52,56],{"_15":44,"_21":22,"_23":45},"3b01fd8f-e84b-4147-9feb-3ec5370c763b","0",{"_15":47,"_21":27,"_23":48},"b0be23fe-9158-4197-9b80-e7eb41af9c70","1",{"_15":50,"_21":31,"_23":51},"b8eed276-b85e-4c19-b7a9-8f92bb43f3ca","2",{"_15":53,"_21":54,"_23":55},"0a08415b-67cf-4f3c-a504-651527fbefcd","D","3",{"_15":57,"_21":58,"_23":59},"2c0050aa-0652-472e-8fd6-254c6aaa4f44","E","5","Para que o polinômio 26x^{3} + 4x^{2} - 2mx + (m - 1) seja divisível por x - 3, o valor da raiz quadrada do módulo de m deve ser igual a","tags",[63,86,94],{"_15":64,"_65":66,"_67":68,"_69":70,"_71":72,"_73":74,"_75":74,"_76":77,"_84":85},"460c64fa-d231-4570-b316-17533b8b28f8","name","Pré-cálculo","alias","pre-calculo","tag_group_id","c1ce2cf2-b217-4cc7-8182-81c56bd3522d","parent_id","b34d4581-a7e7-4d5d-be00-abe3d9a69032","created_at","2025-05-28T00:13:52.643631+00:00","updated_at","metadata",{"_78":79,"_80":81,"_82":83},"childrenCount",4,"content_count",0,"question_count",3555,"slug","pre-calculo-2",{"_15":87,"_65":88,"_67":89,"_69":70,"_71":-5,"_73":90,"_75":90,"_76":91,"_84":89},"9772e958-72c6-4499-ad47-877cf94d670d","Exatas","exatas","2025-04-29T01:56:45.284172+00:00",{"_78":92,"_80":81,"_82":93},18,135489,{"_15":72,"_65":95,"_67":96,"_69":70,"_71":87,"_73":97,"_75":97,"_76":98,"_84":101},"Matemática","matematica","2025-04-29T02:19:12.828432+00:00",{"_78":99,"_80":81,"_82":100},8,40655,"matematica-10",{"_12":13,"_14":13,"_15":103,"_17":104,"_33":13,"_34":117,"_61":118},"66bd27e3-ce98-4b83-a244-55e758adf328",[105,108,111,114],{"_15":106,"_21":22,"_23":107},"6a31809c-23f4-49f8-93ad-40c26d3192d1","4",{"_15":109,"_21":27,"_23":110},"9f7de9bd-67be-4d06-93a7-4723f7a4ea04","8",{"_15":112,"_21":31,"_23":113},"525dd39a-67b7-432a-b2ff-adeb035c0443","10",{"_15":115,"_21":54,"_23":116},"550c6bc7-56c0-4be3-8330-9480fc55da2f","25","As raízes positivas da equação 4x^2 - 10x + 9 = 0 são as medidas das bases de um trapézio isósceles cuja altura é a soma dessas mesmas raízes. A área desse trapézio é",[63,86,94],{"_12":13,"_14":13,"_15":120,"_17":121,"_33":13,"_34":137,"_61":138},"80b083f3-eaf0-437e-af93-22ab13ad2012",[122,125,128,131,134],{"_15":123,"_21":22,"_23":124},"61b623c6-6a42-40da-b145-6dae697ac80c","2222x + 252-",{"_15":126,"_21":27,"_23":127},"642e358a-93cb-493b-bccb-c32933c5fd40","2444x + 252+",{"_15":129,"_21":31,"_23":130},"d4094d52-329a-4785-8270-238a3c7afd9c","444x + 252-",{"_15":132,"_21":54,"_23":133},"0eaec174-6ab6-488b-8580-43ef0050f4dc","222x + 252+",{"_15":135,"_21":58,"_23":136},"98319542-cbbc-4f6d-aae8-77cac9dfa27b","2444x + 252- -","Na divisão do polinômio 4x^3 - 26x^2 + 8x - 10 pelo divisor 2x^2 - 3x + 2, o resto multiplicado por 2 é",[63,86,94],{"_12":13,"_14":13,"_15":140,"_17":141,"_33":13,"_34":157,"_61":158},"a30fdb2c-b621-49bc-a88f-6d9d8be3119a",[142,145,148,151,154],{"_15":143,"_21":22,"_23":144},"5308af1d-e65c-40cd-94ce-61ce2ef1190c","1 e 2",{"_15":146,"_21":27,"_23":147},"995abf5e-986f-4655-a951-701cd6d2b5cc","1 e 2-",{"_15":149,"_21":31,"_23":150},"bd1c8c10-4c28-4a79-b759-f687c00376e5","1- e 3",{"_15":152,"_21":54,"_23":153},"2dcb4dec-5ad1-4cfe-946a-6c2df3c3b02e","1- e 3-",{"_15":155,"_21":58,"_23":156},"5752cc33-b93d-4f7e-adc4-5a8d1bf618fc","1 e 3","Considere o polinômio 3x^{2} + 2x + bx + c, tal que P(1) = 2 e P(2) = 6. Assim, os valores de b e c são, respectivamente,",[63,86,94],{"_12":13,"_14":13,"_15":160,"_17":161,"_33":13,"_34":174,"_61":175},"bcba27c1-092c-4a9f-b7c8-d7d3cf1ca51f",[162,165,168,171],{"_15":163,"_21":22,"_23":164},"6c1a2c64-f2b8-4883-ac05-22f20d7d44db","n é par e m é par.",{"_15":166,"_21":27,"_23":167},"7a9615d0-bd4c-45f9-89e9-dff76c754eb7","n é ímpar e m é ímpar.",{"_15":169,"_21":31,"_23":170},"c5c15099-db49-484a-a311-12511039c191","n é par e m é ímpar.",{"_15":172,"_21":54,"_23":173},"b8372ae9-4099-4195-89fd-b6940f742c68","n é ímpar e m é par.","Considere o polinômio n mp(x) = x^2 + x + 1, em que n e m são números inteiros. Se o resto da divisão de p(x) por x + 1 é igual a 3, então",[63,86,94],[63,86,94],"tagsTree",[179],{"_15":87,"_65":88,"_67":89,"_69":70,"_71":-5,"_73":90,"_75":90,"_76":91,"_84":89,"_180":181},"children",[182],{"_15":72,"_65":95,"_67":96,"_69":70,"_71":87,"_73":97,"_75":97,"_76":98,"_84":101,"_180":183},[184],{"_15":64,"_65":66,"_67":68,"_69":70,"_71":72,"_73":74,"_75":74,"_76":77,"_84":85,"_180":185},[],"actionData","errors"]

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