[{"_1":2,"_190":-5,"_191":-5},"loaderData",{"_3":4,"_6":7},"root",{"_5":-5},"user","pages/questions/show/index",{"_8":9,"_10":11,"_44":45,"_46":47,"_65":180,"_181":182},"comments",[],"question",{"_12":13,"_14":13,"_15":16,"_17":18,"_41":13,"_42":43},"correctOptionId","","difficulty","id","df54ca19-f635-49af-8510-739200edb8bc","options",[19,25,29,33,37],{"_15":20,"_21":22,"_23":24},"b45220aa-f5cd-4c09-8175-c9127d83531e","label","A","text","0",{"_15":26,"_21":27,"_23":28},"15dc8cac-33d2-4db4-9359-f7a07f72529b","B","1",{"_15":30,"_21":31,"_23":32},"7ac64fe6-371f-4912-bba2-a8cdafad0ecb","C","-1",{"_15":34,"_21":35,"_23":36},"08cdbdf4-8f57-456f-8265-80053634ea66","D","-2",{"_15":38,"_21":39,"_23":40},"6fbc848c-0775-439f-9604-bbec7fa76dd3","E","-3","solution_explanation","statement","(Fatec) Considere os polinômios P = x^2 + x - 2, Q = x^2 + 4x - 5 e S. Sabendo-se que P.Q = (x - 1)^2 . S, conclui-se que o valor de S(-2) é:","relatedVideos",[],"similarQuestions",[48,106,123,143,163],{"_12":13,"_14":13,"_15":49,"_17":50,"_41":13,"_42":64,"_65":66},"0b6f4c25-a5b8-4e25-8a27-f76b5729b64e",[51,53,55,58,61],{"_15":52,"_21":22,"_23":24},"3b01fd8f-e84b-4147-9feb-3ec5370c763b",{"_15":54,"_21":27,"_23":28},"b0be23fe-9158-4197-9b80-e7eb41af9c70",{"_15":56,"_21":31,"_23":57},"b8eed276-b85e-4c19-b7a9-8f92bb43f3ca","2",{"_15":59,"_21":35,"_23":60},"0a08415b-67cf-4f3c-a504-651527fbefcd","3",{"_15":62,"_21":39,"_23":63},"2c0050aa-0652-472e-8fd6-254c6aaa4f44","5","Para que o polinômio 26x^{3} + 4x^{2} - 2mx + (m - 1) seja divisível por x - 3, o valor da raiz quadrada do módulo de m deve ser igual a","tags",[67,90,98],{"_15":68,"_69":70,"_71":72,"_73":74,"_75":76,"_77":78,"_79":78,"_80":81,"_88":89},"460c64fa-d231-4570-b316-17533b8b28f8","name","Pré-cálculo","alias","pre-calculo","tag_group_id","c1ce2cf2-b217-4cc7-8182-81c56bd3522d","parent_id","b34d4581-a7e7-4d5d-be00-abe3d9a69032","created_at","2025-05-28T00:13:52.643631+00:00","updated_at","metadata",{"_82":83,"_84":85,"_86":87},"childrenCount",4,"content_count",0,"question_count",3555,"slug","pre-calculo-2",{"_15":91,"_69":92,"_71":93,"_73":74,"_75":-5,"_77":94,"_79":94,"_80":95,"_88":93},"9772e958-72c6-4499-ad47-877cf94d670d","Exatas","exatas","2025-04-29T01:56:45.284172+00:00",{"_82":96,"_84":85,"_86":97},18,135489,{"_15":76,"_69":99,"_71":100,"_73":74,"_75":91,"_77":101,"_79":101,"_80":102,"_88":105},"Matemática","matematica","2025-04-29T02:19:12.828432+00:00",{"_82":103,"_84":85,"_86":104},8,40655,"matematica-10",{"_12":13,"_14":13,"_15":107,"_17":108,"_41":13,"_42":121,"_65":122},"66bd27e3-ce98-4b83-a244-55e758adf328",[109,112,115,118],{"_15":110,"_21":22,"_23":111},"6a31809c-23f4-49f8-93ad-40c26d3192d1","4",{"_15":113,"_21":27,"_23":114},"9f7de9bd-67be-4d06-93a7-4723f7a4ea04","8",{"_15":116,"_21":31,"_23":117},"525dd39a-67b7-432a-b2ff-adeb035c0443","10",{"_15":119,"_21":35,"_23":120},"550c6bc7-56c0-4be3-8330-9480fc55da2f","25","As raízes positivas da equação 4x^2 - 10x + 9 = 0 são as medidas das bases de um trapézio isósceles cuja altura é a soma dessas mesmas raízes. A área desse trapézio é",[67,90,98],{"_12":13,"_14":13,"_15":124,"_17":125,"_41":13,"_42":141,"_65":142},"80b083f3-eaf0-437e-af93-22ab13ad2012",[126,129,132,135,138],{"_15":127,"_21":22,"_23":128},"61b623c6-6a42-40da-b145-6dae697ac80c","2222x + 252-",{"_15":130,"_21":27,"_23":131},"642e358a-93cb-493b-bccb-c32933c5fd40","2444x + 252+",{"_15":133,"_21":31,"_23":134},"d4094d52-329a-4785-8270-238a3c7afd9c","444x + 252-",{"_15":136,"_21":35,"_23":137},"0eaec174-6ab6-488b-8580-43ef0050f4dc","222x + 252+",{"_15":139,"_21":39,"_23":140},"98319542-cbbc-4f6d-aae8-77cac9dfa27b","2444x + 252- -","Na divisão do polinômio 4x^3 - 26x^2 + 8x - 10 pelo divisor 2x^2 - 3x + 2, o resto multiplicado por 2 é",[67,90,98],{"_12":13,"_14":13,"_15":144,"_17":145,"_41":13,"_42":161,"_65":162},"a30fdb2c-b621-49bc-a88f-6d9d8be3119a",[146,149,152,155,158],{"_15":147,"_21":22,"_23":148},"5308af1d-e65c-40cd-94ce-61ce2ef1190c","1 e 2",{"_15":150,"_21":27,"_23":151},"995abf5e-986f-4655-a951-701cd6d2b5cc","1 e 2-",{"_15":153,"_21":31,"_23":154},"bd1c8c10-4c28-4a79-b759-f687c00376e5","1- e 3",{"_15":156,"_21":35,"_23":157},"2dcb4dec-5ad1-4cfe-946a-6c2df3c3b02e","1- e 3-",{"_15":159,"_21":39,"_23":160},"5752cc33-b93d-4f7e-adc4-5a8d1bf618fc","1 e 3","Considere o polinômio 3x^{2} + 2x + bx + c, tal que P(1) = 2 e P(2) = 6. Assim, os valores de b e c são, respectivamente,",[67,90,98],{"_12":13,"_14":13,"_15":164,"_17":165,"_41":13,"_42":178,"_65":179},"bcba27c1-092c-4a9f-b7c8-d7d3cf1ca51f",[166,169,172,175],{"_15":167,"_21":22,"_23":168},"6c1a2c64-f2b8-4883-ac05-22f20d7d44db","n é par e m é par.",{"_15":170,"_21":27,"_23":171},"7a9615d0-bd4c-45f9-89e9-dff76c754eb7","n é ímpar e m é ímpar.",{"_15":173,"_21":31,"_23":174},"c5c15099-db49-484a-a311-12511039c191","n é par e m é ímpar.",{"_15":176,"_21":35,"_23":177},"b8372ae9-4099-4195-89fd-b6940f742c68","n é ímpar e m é par.","Considere o polinômio n mp(x) = x^2 + x + 1, em que n e m são números inteiros. Se o resto da divisão de p(x) por x + 1 é igual a 3, então",[67,90,98],[67,90,98],"tagsTree",[183],{"_15":91,"_69":92,"_71":93,"_73":74,"_75":-5,"_77":94,"_79":94,"_80":95,"_88":93,"_184":185},"children",[186],{"_15":76,"_69":99,"_71":100,"_73":74,"_75":91,"_77":101,"_79":101,"_80":102,"_88":105,"_184":187},[188],{"_15":68,"_69":70,"_71":72,"_73":74,"_75":76,"_77":78,"_79":78,"_80":81,"_88":89,"_184":189},[],"actionData","errors"]

Aulas em vídeo Em breve

Tópicos Relacionados