[{"_1":2,"_192":-5,"_193":-5},"loaderData",{"_3":4,"_6":7},"root",{"_5":-5},"user","pages/questions/show/index",{"_8":9,"_10":11,"_44":45,"_46":47,"_67":182,"_183":184},"comments",[],"question",{"_12":13,"_14":13,"_15":16,"_17":18,"_41":13,"_42":43},"correctOptionId","","difficulty","id","e5e32072-b11d-4da5-8da4-93732c9ddf91","options",[19,25,29,33,37],{"_15":20,"_21":22,"_23":24},"9d645706-df37-4e08-871b-03e6ff15b7ba","label","A","text","6xy^5 + 2x^4 \text{sen}(y) \text{cos}(y)",{"_15":26,"_21":27,"_23":28},"2b076260-6f6d-43c2-8039-7f074e16b491","B","3x^3 y^5 + 2x^4 \text{sen}(y)",{"_15":30,"_21":31,"_23":32},"9351835f-6165-4dab-862c-f5fc81057ebd","C","6x^2 y^6 + 4x^3 \text{sen}^2(y)",{"_15":34,"_21":35,"_23":36},"ef28a45e-e22e-4ed8-8139-aeb163205066","D","3x^2 y^6 + 4x^3 \text{sen}^2(y)",{"_15":38,"_21":39,"_23":40},"5a8d5119-a5ce-4009-a2a6-3ab37eb7e86e","E","6x^3 y^5 + 4x^3 \text{sen}^2(y)","solution_explanation","statement","

Utilizando a regra da cadeia, podemos afirmar que o valor de \u0002w se w = T(s) + s^2 r = xy^2 e s = x^2 \text{sen}(y) é igual a:

","relatedVideos",[],"similarQuestions",[48,108,125,145,165],{"_12":13,"_14":13,"_15":49,"_17":50,"_41":13,"_42":66,"_67":68},"0b6f4c25-a5b8-4e25-8a27-f76b5729b64e",[51,54,57,60,63],{"_15":52,"_21":22,"_23":53},"3b01fd8f-e84b-4147-9feb-3ec5370c763b","0",{"_15":55,"_21":27,"_23":56},"b0be23fe-9158-4197-9b80-e7eb41af9c70","1",{"_15":58,"_21":31,"_23":59},"b8eed276-b85e-4c19-b7a9-8f92bb43f3ca","2",{"_15":61,"_21":35,"_23":62},"0a08415b-67cf-4f3c-a504-651527fbefcd","3",{"_15":64,"_21":39,"_23":65},"2c0050aa-0652-472e-8fd6-254c6aaa4f44","5","Para que o polinômio 26x^{3} + 4x^{2} - 2mx + (m - 1) seja divisível por x - 3, o valor da raiz quadrada do módulo de m deve ser igual a","tags",[69,92,100],{"_15":70,"_71":72,"_73":74,"_75":76,"_77":78,"_79":80,"_81":80,"_82":83,"_90":91},"460c64fa-d231-4570-b316-17533b8b28f8","name","Pré-cálculo","alias","pre-calculo","tag_group_id","c1ce2cf2-b217-4cc7-8182-81c56bd3522d","parent_id","b34d4581-a7e7-4d5d-be00-abe3d9a69032","created_at","2025-05-28T00:13:52.643631+00:00","updated_at","metadata",{"_84":85,"_86":87,"_88":89},"childrenCount",4,"content_count",0,"question_count",3555,"slug","pre-calculo-2",{"_15":93,"_71":94,"_73":95,"_75":76,"_77":-5,"_79":96,"_81":96,"_82":97,"_90":95},"9772e958-72c6-4499-ad47-877cf94d670d","Exatas","exatas","2025-04-29T01:56:45.284172+00:00",{"_84":98,"_86":87,"_88":99},18,135489,{"_15":78,"_71":101,"_73":102,"_75":76,"_77":93,"_79":103,"_81":103,"_82":104,"_90":107},"Matemática","matematica","2025-04-29T02:19:12.828432+00:00",{"_84":105,"_86":87,"_88":106},8,40655,"matematica-10",{"_12":13,"_14":13,"_15":109,"_17":110,"_41":13,"_42":123,"_67":124},"66bd27e3-ce98-4b83-a244-55e758adf328",[111,114,117,120],{"_15":112,"_21":22,"_23":113},"6a31809c-23f4-49f8-93ad-40c26d3192d1","4",{"_15":115,"_21":27,"_23":116},"9f7de9bd-67be-4d06-93a7-4723f7a4ea04","8",{"_15":118,"_21":31,"_23":119},"525dd39a-67b7-432a-b2ff-adeb035c0443","10",{"_15":121,"_21":35,"_23":122},"550c6bc7-56c0-4be3-8330-9480fc55da2f","25","As raízes positivas da equação 4x^2 - 10x + 9 = 0 são as medidas das bases de um trapézio isósceles cuja altura é a soma dessas mesmas raízes. A área desse trapézio é",[69,92,100],{"_12":13,"_14":13,"_15":126,"_17":127,"_41":13,"_42":143,"_67":144},"80b083f3-eaf0-437e-af93-22ab13ad2012",[128,131,134,137,140],{"_15":129,"_21":22,"_23":130},"61b623c6-6a42-40da-b145-6dae697ac80c","2222x + 252-",{"_15":132,"_21":27,"_23":133},"642e358a-93cb-493b-bccb-c32933c5fd40","2444x + 252+",{"_15":135,"_21":31,"_23":136},"d4094d52-329a-4785-8270-238a3c7afd9c","444x + 252-",{"_15":138,"_21":35,"_23":139},"0eaec174-6ab6-488b-8580-43ef0050f4dc","222x + 252+",{"_15":141,"_21":39,"_23":142},"98319542-cbbc-4f6d-aae8-77cac9dfa27b","2444x + 252- -","Na divisão do polinômio 4x^3 - 26x^2 + 8x - 10 pelo divisor 2x^2 - 3x + 2, o resto multiplicado por 2 é",[69,92,100],{"_12":13,"_14":13,"_15":146,"_17":147,"_41":13,"_42":163,"_67":164},"a30fdb2c-b621-49bc-a88f-6d9d8be3119a",[148,151,154,157,160],{"_15":149,"_21":22,"_23":150},"5308af1d-e65c-40cd-94ce-61ce2ef1190c","1 e 2",{"_15":152,"_21":27,"_23":153},"995abf5e-986f-4655-a951-701cd6d2b5cc","1 e 2-",{"_15":155,"_21":31,"_23":156},"bd1c8c10-4c28-4a79-b759-f687c00376e5","1- e 3",{"_15":158,"_21":35,"_23":159},"2dcb4dec-5ad1-4cfe-946a-6c2df3c3b02e","1- e 3-",{"_15":161,"_21":39,"_23":162},"5752cc33-b93d-4f7e-adc4-5a8d1bf618fc","1 e 3","Considere o polinômio 3x^{2} + 2x + bx + c, tal que P(1) = 2 e P(2) = 6. Assim, os valores de b e c são, respectivamente,",[69,92,100],{"_12":13,"_14":13,"_15":166,"_17":167,"_41":13,"_42":180,"_67":181},"bcba27c1-092c-4a9f-b7c8-d7d3cf1ca51f",[168,171,174,177],{"_15":169,"_21":22,"_23":170},"6c1a2c64-f2b8-4883-ac05-22f20d7d44db","n é par e m é par.",{"_15":172,"_21":27,"_23":173},"7a9615d0-bd4c-45f9-89e9-dff76c754eb7","n é ímpar e m é ímpar.",{"_15":175,"_21":31,"_23":176},"c5c15099-db49-484a-a311-12511039c191","n é par e m é ímpar.",{"_15":178,"_21":35,"_23":179},"b8372ae9-4099-4195-89fd-b6940f742c68","n é ímpar e m é par.","Considere o polinômio n mp(x) = x^2 + x + 1, em que n e m são números inteiros. Se o resto da divisão de p(x) por x + 1 é igual a 3, então",[69,92,100],[69,92,100],"tagsTree",[185],{"_15":93,"_71":94,"_73":95,"_75":76,"_77":-5,"_79":96,"_81":96,"_82":97,"_90":95,"_186":187},"children",[188],{"_15":78,"_71":101,"_73":102,"_75":76,"_77":93,"_79":103,"_81":103,"_82":104,"_90":107,"_186":189},[190],{"_15":70,"_71":72,"_73":74,"_75":76,"_77":78,"_79":80,"_81":80,"_82":83,"_90":91,"_186":191},[],"actionData","errors"]

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