[{"_1":2,"_259":-5,"_260":-5},"loaderData",{"_3":4,"_8":9},"root",{"_5":6,"_7":-5},"url","https://prouniversitario.com/exercicios/e6561caf-6df9-403d-bd27-44eb12e56311","user","pages/questions/show/index",{"_10":11,"_12":13,"_24":25,"_26":27,"_54":231,"_232":233},"comments",[],"question",{"_14":15,"_16":15,"_17":18,"_19":20,"_21":15,"_22":23},"correctOptionId","","difficulty","id","e6561caf-6df9-403d-bd27-44eb12e56311","options",[],"solution_explanation","statement","

Um aço carbono 1035 é resfriado lentamente desde 940^{\text{°C}} até a temperatura de 725^{\text{°C}}.

a) Esboce a microestrutura do aço a 725^{\text{°C}}.

b) Calcule a proporção em peso de perlita presente no aço.

Justifique sua resposta na área quadriculada.

","relatedVideos",[],"similarQuestions",[28,157,174,191,211],{"_14":15,"_16":15,"_17":29,"_19":30,"_21":15,"_22":53,"_54":55},"3c0b9441-b878-4896-8bac-fa4ca61e3f13",[31,37,41,45,49],{"_17":32,"_33":34,"_35":36},"265bd71a-6749-41f5-b291-67efd646ca64","label","A","text","y'' + 2y' - 3y = 0",{"_17":38,"_33":39,"_35":40},"6d3c3a1d-8e80-4ff3-b97a-d5b5bca91940","B","6y'' - y' - y = 0",{"_17":42,"_33":43,"_35":44},"4168ac67-64fd-46ed-a69c-a01dbfcde7ea","C","y'' - 2y' + y = 0",{"_17":46,"_33":47,"_35":48},"cc7bc8df-6995-4264-ac5a-32ea9b4ed7db","D","9y'' + 6y' + y = 0",{"_17":50,"_33":51,"_35":52},"112831da-be9c-458e-94cb-e8292d0dba12","E","y'' - 2y' + 6y = 0","

Resolva as seguintes EDOs determinando a solução geral e, quando houver condições iniciais do PVI, a solução particular.

(a) y'' + 2y' - 3y = 0

(b) 6y'' - y' - y = 0

(d) 9y'' + 6y' + y = 0

(e) y'' - 2y' + 6y = 0

(f) 4y'' + 9y = 0

(g) 6y'' - 5y' + y = 0; \\, y(0) = 4; \\, y'(0) = 0

(h) y'' + 4y' + 4y = 0; \\, y(-1) = 2; \\, y'(-1) = 1

(i) y'' + y = 0; \\, y\bigg(\\frac{\\pi}{3}\\bigg) = 2; \\, y'\\bigg(\\frac{\\pi}{3}\\bigg) = -4

(j) y'' - 2y' - 3y = 3e^{2t}

(k) y'' + 9y = t^2 e^{3t} + 6

(l) 2y'' + 3y' + y = t^2 + 3 \\sin(t)

(m) y'' + y' - 2y = 2t; \\, y(0) = 0; \\, y'(0) = 1

(n) y'' - 2y' + y = te^t + 4; \\, y(0) = 1; \\, y'(0) = 1

(o) y'' + 4y = 3 \\sin(2t); \\, y(0) = 2; \\, y'(0) = -1

","tags",[56,78,88,98,105,112,120,128,134,139,145,152],{"_17":57,"_58":59,"_60":61,"_62":63,"_64":65,"_66":67,"_68":67,"_69":70,"_77":61},"6516bbbd-f2a3-4710-8382-702240b17836","name","Mecânica na Engenharia de Petróleo","alias","mecanica-na-engenharia-de-petroleo","tag_group_id","c1ce2cf2-b217-4cc7-8182-81c56bd3522d","parent_id","b787e438-0ab3-454c-ab43-5d3d14c2720d","created_at","2025-04-29T03:44:35.328997+00:00","updated_at","metadata",{"_71":72,"_73":74,"_75":76},"childrenCount",4,"content_count",0,"question_count",12302,"slug",{"_17":79,"_58":80,"_60":81,"_62":63,"_64":82,"_66":83,"_68":83,"_69":84,"_77":87},"6b6faf95-0e3a-4f58-abc8-e1444c48041d","Termodinâmica","termodinamica","92339f4f-ed20-4f4c-ad85-0c3de7e04ae0","2025-04-29T03:44:27.560682+00:00",{"_71":85,"_73":74,"_75":86},2,11846,"termodinamica-3",{"_17":89,"_58":90,"_60":91,"_62":63,"_64":92,"_66":93,"_68":93,"_69":94,"_77":97},"861ad829-750d-4a44-9569-2f18b430b4df","Engenharia Mecatrônica","engenharia-mecatronica","eb9315c5-bd04-4116-aa46-02c4fde320c0","2025-04-29T02:19:12.828432+00:00",{"_71":95,"_73":74,"_75":96},5,30614,"engenharia-mecatronica-1",{"_17":99,"_58":100,"_60":101,"_62":63,"_64":89,"_66":67,"_68":67,"_69":102,"_77":104},"88fe96b3-2a17-4198-90d5-ddda3d6f5d45","Mecânica","mecanica",{"_71":95,"_73":74,"_75":103},25741,"mecanica-3",{"_17":82,"_58":106,"_60":107,"_62":63,"_64":92,"_66":93,"_68":93,"_69":108,"_77":111},"Engenharia Mecânica","engenharia-mecanica",{"_71":109,"_73":74,"_75":110},11,36318,"engenharia-mecanica-2",{"_17":113,"_58":114,"_60":115,"_62":63,"_64":116,"_66":83,"_68":83,"_69":117,"_77":115},"96193fa0-9495-45b2-81cc-b547604354af","Física Térmica - Termologia","fisica-termica-termologia","c8ab2a95-fd84-4d6f-ade0-835d34ba00f9",{"_71":118,"_73":74,"_75":119},10,8575,{"_17":121,"_58":122,"_60":123,"_62":63,"_64":-5,"_66":124,"_68":124,"_69":125,"_77":123},"9772e958-72c6-4499-ad47-877cf94d670d","Exatas","exatas","2025-04-29T01:56:45.284172+00:00",{"_71":126,"_73":74,"_75":127},18,135489,{"_17":129,"_58":80,"_60":81,"_62":63,"_64":57,"_66":130,"_68":130,"_69":131,"_77":133},"b21374de-aae5-4a4a-9bf3-0420e731797e","2025-04-29T04:00:14.680867+00:00",{"_71":74,"_73":74,"_75":132},8597,"termodinamica-5",{"_17":65,"_58":135,"_60":136,"_62":63,"_64":92,"_66":93,"_68":93,"_69":137,"_77":138},"Engenharia de Petróleo","engenharia-de-petroleo",{"_71":95,"_73":74,"_75":76},"engenharia-de-petroleo-1",{"_17":116,"_58":140,"_60":141,"_62":63,"_64":121,"_66":93,"_68":93,"_69":142,"_77":144},"Física","fisica",{"_71":109,"_73":74,"_75":143},13777,"fisica-4",{"_17":92,"_58":146,"_60":147,"_62":63,"_64":-5,"_66":148,"_68":148,"_69":149,"_77":147},"Engenharia","engenharia","2025-04-29T01:55:38.635246+00:00",{"_71":150,"_73":74,"_75":151},29,351586,{"_17":153,"_58":80,"_60":81,"_62":63,"_64":99,"_66":154,"_68":154,"_69":155,"_77":156},"f5967cbe-d751-4b40-81f2-04eb5dead2a9","2025-04-29T04:00:13.215003+00:00",{"_71":74,"_73":74,"_75":132},"termodinamica-4",{"_14":15,"_16":15,"_17":158,"_19":159,"_21":15,"_22":172,"_54":173},"4a3f20e5-655d-4a84-bbdf-aa3b0de4581a",[160,163,166,169],{"_17":161,"_33":34,"_35":162},"8dee6a5e-57a3-4743-8b5a-da9b8c54fb32","Verdadero, verdadero, verdadero, verdadero.",{"_17":164,"_33":39,"_35":165},"ca0a9b0d-3004-478e-9ca9-bafa5243aca9","Verdadero, verdadero, falso, verdadero.",{"_17":167,"_33":43,"_35":168},"68712800-8b4b-46af-9cdf-3f83e4032c30","Verdadero, falso, verdadero, falso.",{"_17":170,"_33":47,"_35":171},"1f5e395b-c362-4503-8261-dcfcae96b1ce","Falso, verdadero, verdadeiro, verdadeiro.","

Divide el polinomio p(x) = 3x^4 + 4x^3 + x^2 entre el polinomio q(x) = 2+x. Como el polinomio divisor, q(x), es de grado 2, debemos encontrar dos polinomios, un polinomio cociente (c(x)) y un polinomio resto (r(x)) de grado 1 o 0, tales que p(x) = q(x) * c(x) + r(x).

El polinomio p(x) es de grado 4.

El polinomio q(x) es de grado 1.

El polinomio cociente c(x) es de grado 2.

El polinomio resto r(x) es de grado 1 o 0.

",[56,78,88,98,105,112,120,128,134,139,145,152],{"_14":15,"_16":15,"_17":175,"_19":176,"_21":15,"_22":189,"_54":190},"93a32dd4-5fc6-4ccb-a76f-4724bf113742",[177,180,183,186],{"_17":178,"_33":34,"_35":179},"13e3f476-a0a5-421f-b47e-0969e8e9a7e0","

Verdadeiro, verdadeiro, falso

",{"_17":181,"_33":39,"_35":182},"c9a20855-d84b-4860-8b35-9784818282cf","

Falso, verdadeiro, verdadeiro

",{"_17":184,"_33":43,"_35":185},"6831a9b9-c9a4-4a76-bd7a-2ce98bfea875","

Verdadeiro, falso, verdadeiro

",{"_17":187,"_33":47,"_35":188},"3c98539b-1af9-4d44-aecd-c266754a2075","

Falso, falso, falso

","

Qual é a idade da madeira na qual 85,5\\% do C-14 se decompos?

",[56,78,88,98,105,112,120,128,134,139,145,152],{"_14":15,"_16":15,"_17":192,"_19":193,"_21":15,"_22":209,"_54":210},"996628fc-4ac3-4821-86bd-839f86a97a6d",[194,197,200,203,206],{"_17":195,"_33":34,"_35":196},"5ad09994-6dcb-4c66-87ae-ec00e9b439b7","5 + 3x < 2x + 4",{"_17":198,"_33":39,"_35":199},"b3ae9948-890b-4807-b801-1e1888cb0c10","3 + 4x \\leq 8x + 6",{"_17":201,"_33":43,"_35":202},"d2964603-f26c-4be6-99ae-d174678f104c","5 + 4x > 3x + 2",{"_17":204,"_33":47,"_35":205},"88c48b1a-ce37-4eae-a900-a4fb4bd581d9","1 + 3x \\geq 5x + 7",{"_17":207,"_33":51,"_35":208},"155e0bb0-6c7f-4d9c-96e5-d1cdb97c632b","4(3 + 2x) < -(6x + 8)","Resolver las siguientes inecuaciones y representar la solución en la recta real:",[56,78,88,98,105,112,120,128,134,139,145,152],{"_14":15,"_16":15,"_17":212,"_19":213,"_21":15,"_22":229,"_54":230},"c478a46c-46a8-4942-ae14-2e79def3dda2",[214,217,220,223,226],{"_17":215,"_33":34,"_35":216},"a5a16a42-3e58-4c76-80f2-c291aa2d8e49","Sim",{"_17":218,"_33":39,"_35":219},"5e6d0254-696c-4da0-b572-82e3a19f433e","Não",{"_17":221,"_33":43,"_35":222},"3ce109b1-6cdb-4b4d-8816-a6af4d74bed0","Indeterminado",{"_17":224,"_33":47,"_35":225},"35403f68-a880-429d-97f4-db507c58de38","Todos",{"_17":227,"_33":51,"_35":228},"2e06d948-d37e-4350-afc7-ced04941bcaf","Nenhum","Emplea la regla de Ruffini para dictaminar si los siguientes números son o no raíces de los polinomios citados:
a) ????3 de ????4????5
b) ????2 de ????2????????2
c) ????1 de 2????????1
d) ????1 de 2????2????",[56,78,88,98,105,112,120,128,134,139,145,152],[56,78,88,98,105,112,120,128,134,139,145,152],"tagsTree",[234,241],{"_17":121,"_58":122,"_60":123,"_62":63,"_64":-5,"_66":124,"_68":124,"_69":125,"_77":123,"_235":236},"children",[237],{"_17":116,"_58":140,"_60":141,"_62":63,"_64":121,"_66":93,"_68":93,"_69":142,"_77":144,"_235":238},[239],{"_17":113,"_58":114,"_60":115,"_62":63,"_64":116,"_66":83,"_68":83,"_69":117,"_77":115,"_235":240},[],{"_17":92,"_58":146,"_60":147,"_62":63,"_64":-5,"_66":148,"_68":148,"_69":149,"_77":147,"_235":242},[243,249,253],{"_17":89,"_58":90,"_60":91,"_62":63,"_64":92,"_66":93,"_68":93,"_69":94,"_77":97,"_235":244},[245],{"_17":99,"_58":100,"_60":101,"_62":63,"_64":89,"_66":67,"_68":67,"_69":102,"_77":104,"_235":246},[247],{"_17":153,"_58":80,"_60":81,"_62":63,"_64":99,"_66":154,"_68":154,"_69":155,"_77":156,"_235":248},[],{"_17":82,"_58":106,"_60":107,"_62":63,"_64":92,"_66":93,"_68":93,"_69":108,"_77":111,"_235":250},[251],{"_17":79,"_58":80,"_60":81,"_62":63,"_64":82,"_66":83,"_68":83,"_69":84,"_77":87,"_235":252},[],{"_17":65,"_58":135,"_60":136,"_62":63,"_64":92,"_66":93,"_68":93,"_69":137,"_77":138,"_235":254},[255],{"_17":57,"_58":59,"_60":61,"_62":63,"_64":65,"_66":67,"_68":67,"_69":70,"_77":61,"_235":256},[257],{"_17":129,"_58":80,"_60":81,"_62":63,"_64":57,"_66":130,"_68":130,"_69":131,"_77":133,"_235":258},[],"actionData","errors"]

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