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3y = 0",{"_43":201,"_81":87,"_83":202},"6d3c3a1d-8e80-4ff3-b97a-d5b5bca91940","6y'' - y' - y = 0",{"_43":204,"_81":91,"_83":205},"4168ac67-64fd-46ed-a69c-a01dbfcde7ea","y'' - 2y' + y = 0",{"_43":207,"_81":208,"_83":209},"cc7bc8df-6995-4264-ac5a-32ea9b4ed7db","D","9y'' + 6y' + y = 0",{"_43":194,"_81":211,"_83":212},"E","y'' - 2y' + 6y = 0","Somente em y''−2y'+6y=0 o polinômio característico r²−2r+6=0 tem Δ<0, gerando raízes complexas conjugadas (1±i√5) e, portanto, solução em termos de exponencial modulando seno e cosseno. Nos demais itens (a–d) o discriminante é ≥0, produzindo raízes reais (distintas ou repetidas).","

Resolva as seguintes EDOs determinando a solução geral e, quando houver condições iniciais do PVI, a solução particular.

(a) y'' + 2y' - 3y = 0

(b) 6y'' - y' - y = 0

(d) 9y'' + 6y' + y = 0

(e) y'' - 2y' + 6y = 0

(f) 4y'' + 9y = 0

(g) 6y'' - 5y' + y = 0; \\, y(0) = 4; \\, y'(0) = 0

(h) y'' + 4y' + 4y = 0; \\, y(-1) = 2; \\, y'(-1) = 1

(i) y'' + y = 0; \\, y\bigg(\\frac{\\pi}{3}\\bigg) = 2; \\, y'\\bigg(\\frac{\\pi}{3}\\bigg) = -4

(j) y'' - 2y' - 3y = 3e^{2t}

(k) y'' + 9y = t^2 e^{3t} + 6

(l) 2y'' + 3y' + y = t^2 + 3 \\sin(t)

(m) y'' + y' - 2y = 2t; \\, y(0) = 0; \\, y'(0) = 1

(n) y'' - 2y' + y = te^t + 4; \\, y(0) = 1; \\, y'(0) = 1

(o) y'' + 4y = 3 \\sin(2t); \\, y(0) = 2; \\, y'(0) = -1

",[216],{"_43":217,"_57":218,"_59":219,"_142":143,"_144":220,"_115":221,"_117":221,"_45":222,"_119":219},"6516bbbd-f2a3-4710-8382-702240b17836","Mecânica na Engenharia de Petróleo","mecanica-na-engenharia-de-petroleo","b787e438-0ab3-454c-ab43-5d3d14c2720d","2025-04-29T03:44:35.328997+00:00",{"_147":223,"_149":150,"_151":224},4,12302,{"_40":226,"_42":41,"_43":227,"_77":228,"_93":240,"_94":241,"_51":242},"6831a9b9-c9a4-4a76-bd7a-2ce98bfea875","93a32dd4-5fc6-4ccb-a76f-4724bf113742",[229,232,235,237],{"_43":230,"_81":82,"_83":231},"13e3f476-a0a5-421f-b47e-0969e8e9a7e0","

Verdadeiro, verdadeiro, falso

",{"_43":233,"_81":87,"_83":234},"c9a20855-d84b-4860-8b35-9784818282cf","

Falso, verdadeiro, verdadeiro

",{"_43":226,"_81":91,"_83":236},"

Verdadeiro, falso, verdadeiro

",{"_43":238,"_81":208,"_83":239},"3c98539b-1af9-4d44-aecd-c266754a2075","

Falso, falso, falso

","85,5 % decomposto → 14,5 % restante.\nN/N0 = 0,145 ⇒ t = ln(1/0,145)/(ln2/5730) ≈ 1,6×10⁴ anos.\nItens prováveis: (1) resta 14,5 % do C-14 (V); (2) idade ≈ 1,2×10⁴ anos ou 3 meias-vidas (F); (3) t½ do C-14 = 5730 anos (V). Sequência: V-F-V, correspondendo à alternativa c.","

Qual é a idade da madeira na qual 85,5\\% do C-14 se decompos?

",[216],{"_40":244,"_42":41,"_43":245,"_77":246,"_93":261,"_94":262,"_51":263},"3ce109b1-6cdb-4b4d-8816-a6af4d74bed0","c478a46c-46a8-4942-ae14-2e79def3dda2",[247,250,253,255,258],{"_43":248,"_81":82,"_83":249},"a5a16a42-3e58-4c76-80f2-c291aa2d8e49","Sim",{"_43":251,"_81":87,"_83":252},"5e6d0254-696c-4da0-b572-82e3a19f433e","Não",{"_43":244,"_81":91,"_83":254},"Indeterminado",{"_43":256,"_81":208,"_83":257},"35403f68-a880-429d-97f4-db507c58de38","Todos",{"_43":259,"_81":211,"_83":260},"2e06d948-d37e-4350-afc7-ced04941bcaf","Nenhum","Os polinômios e números fornecidos estão corrompidos (símbolos “????”), impossibilitando aplicar Ruffini e concluir se são raízes. Sem dados completos, o problema é indeterminado.","Emplea la regla de Ruffini para dictaminar si los siguientes números son o no raíces de los polinomios citados:
a) ????3 de ????4????5
b) ????2 de ????2????????2
c) ????1 de 2????????1
d) ????1 de 2????2????",[216],[216,265,274,280,284,285,286,294,299,307,308,313,319],{"_43":266,"_57":267,"_59":268,"_142":143,"_144":269,"_115":159,"_117":159,"_45":270,"_119":273},"861ad829-750d-4a44-9569-2f18b430b4df","Engenharia Mecatrônica","engenharia-mecatronica","eb9315c5-bd04-4116-aa46-02c4fde320c0",{"_147":271,"_149":150,"_151":272},5,30614,"engenharia-mecatronica-1",{"_43":275,"_57":58,"_59":60,"_142":143,"_144":276,"_115":277,"_117":277,"_45":278,"_119":279},"8850e507-a691-4d45-a7c7-16221e9c5af2","88fe96b3-2a17-4198-90d5-ddda3d6f5d45","2025-04-29T04:00:13.215003+00:00",{"_147":150,"_149":150,"_151":169},"resistencia-dos-materiais-6",{"_43":276,"_57":157,"_59":158,"_142":143,"_144":266,"_115":221,"_117":221,"_45":281,"_119":283},{"_147":271,"_149":150,"_151":282},25741,"mecanica-3",{"_43":139,"_57":140,"_59":141,"_142":143,"_144":-5,"_115":145,"_117":145,"_45":146,"_119":141},{"_43":166,"_57":58,"_59":60,"_142":143,"_144":156,"_115":167,"_117":167,"_45":168,"_119":170},{"_43":287,"_57":288,"_59":289,"_142":143,"_144":269,"_115":159,"_117":159,"_45":290,"_119":293},"b6e37f32-f8e5-4025-bf0f-69ffc00fb331","Engenharia Civil","engenharia-civil",{"_147":291,"_149":150,"_151":292},21,45865,"engenharia-civil-3",{"_43":220,"_57":295,"_59":296,"_142":143,"_144":269,"_115":159,"_117":159,"_45":297,"_119":298},"Engenharia de Petróleo","engenharia-de-petroleo",{"_147":271,"_149":150,"_151":224},"engenharia-de-petroleo-1",{"_43":300,"_57":301,"_59":302,"_142":143,"_144":287,"_115":303,"_117":303,"_45":304,"_119":306},"c5bf57d4-c3d8-4365-b53e-085fa14a3a95","Estruturas","estruturas","2025-04-29T03:44:32.303369+00:00",{"_147":271,"_149":150,"_151":305},8852,"estruturas-1",{"_43":156,"_57":157,"_59":158,"_142":143,"_144":139,"_115":159,"_117":159,"_45":160,"_119":163},{"_43":309,"_57":58,"_59":60,"_142":143,"_144":217,"_115":310,"_117":310,"_45":311,"_119":312},"d1e4567b-f68a-49e1-b3e5-3888343d7871","2025-04-29T04:00:14.680867+00:00",{"_147":150,"_149":150,"_151":169},"resistencia-dos-materiais-7",{"_43":314,"_57":315,"_59":60,"_142":143,"_144":300,"_115":316,"_117":316,"_45":317,"_119":318},"da8d2ecf-e949-4afc-966f-98b4b367fac1","Resistencia dos Materiais","2025-04-29T04:00:06.9766+00:00",{"_147":150,"_149":150,"_151":169},"resistencia-dos-materiais-5",{"_43":269,"_57":320,"_59":321,"_142":143,"_144":-5,"_115":322,"_117":322,"_45":323,"_119":321},"Engenharia","engenharia","2025-04-29T01:55:38.635246+00:00",{"_147":324,"_149":150,"_151":325},29,351586,"tagsTree",[138,328],{"_43":269,"_57":320,"_59":321,"_142":143,"_144":-5,"_115":322,"_117":322,"_45":323,"_119":321,"_153":329},[330,336,342],{"_43":266,"_57":267,"_59":268,"_142":143,"_144":269,"_115":159,"_117":159,"_45":270,"_119":273,"_153":331},[332],{"_43":276,"_57":157,"_59":158,"_142":143,"_144":266,"_115":221,"_117":221,"_45":281,"_119":283,"_153":333},[334],{"_43":275,"_57":58,"_59":60,"_142":143,"_144":276,"_115":277,"_117":277,"_45":278,"_119":279,"_153":335},[],{"_43":287,"_57":288,"_59":289,"_142":143,"_144":269,"_115":159,"_117":159,"_45":290,"_119":293,"_153":337},[338],{"_43":300,"_57":301,"_59":302,"_142":143,"_144":287,"_115":303,"_117":303,"_45":304,"_119":306,"_153":339},[340],{"_43":314,"_57":315,"_59":60,"_142":143,"_144":300,"_115":316,"_117":316,"_45":317,"_119":318,"_153":341},[],{"_43":220,"_57":295,"_59":296,"_142":143,"_144":269,"_115":159,"_117":159,"_45":297,"_119":298,"_153":343},[344],{"_43":217,"_57":218,"_59":219,"_142":143,"_144":220,"_115":221,"_117":221,"_45":222,"_119":219,"_153":345},[346],{"_43":309,"_57":58,"_59":60,"_142":143,"_144":217,"_115":310,"_117":310,"_45":311,"_119":312,"_153":347},[],"videoDislikes",{},"videoLikes",{},"actionData","errors"]

Comentários