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S aumenta e U permanece constante

",{"_44":86,"_81":87,"_83":88},"6a76dd63-037e-411d-bc63-9178fe622b9b","B","

S permanece constante e U aumenta

",{"_44":41,"_81":90,"_83":91},"C","

S aumenta e U aumenta

",{"_44":93,"_81":94,"_83":95},"b1e386e1-618d-4a58-be12-b748e1c48908","D","

S diminui e U aumenta

","solution_explanation","statement","

Considerando um sistema de partículas em uma vasilha, se a temperatura do sistema é aumentada, qual é o efeito esperado sobre a entropia S e a energia interna U do sistema?

","status","pending_classification","hasRelatedVideo","relatedVideos",[104],{"_105":106,"_124":125,"_51":140,"_159":160,"_177":141},"content",{"_44":107,"_57":108,"_109":-5,"_110":111,"_112":113,"_114":-5,"_46":115,"_118":119,"_120":119,"_121":-5,"_122":123},"162087be-594f-460e-bbdd-a339ac2f10ad","Calor Latente - Parte 1","description","content_type_id","1051eee7-c62e-4b2c-9900-77a29fcec080","resource_id","f2b62fc2-7079-40e7-a5b5-c4a9769b205d","user_id",{"_116":117},"external_id","3659","created_at","2025-08-20T12:27:41.608438+00:00","updated_at","content_group_id","slug","calor-latente-parte-1","prometheusData",{"_126":127,"_133":134,"_135":136,"_137":138,"_28":139},"provider",{"_44":128,"_129":130,"_131":132},"06f120be-2194-4548-8336-7ba44ffbae14","key","grupo_q_proteus","kind","proteus","reference","bf8aacba-3de9-4b10-961c-47ada80dfe8c","state","completed","thumbnail_url","https://proteus.grupoq.io/videos/bf8aacba-3de9-4b10-961c-47ada80dfe8c/thumbnailsthumb.0000000.jpg","https://proteus.grupoq.io/videos/bf8aacba-3de9-4b10-961c-47ada80dfe8c/levels.m3u8",[141],{"_44":142,"_57":143,"_59":144,"_145":146,"_147":148,"_118":149,"_120":149,"_46":150,"_122":144,"_157":158},"96193fa0-9495-45b2-81cc-b547604354af","Física Térmica - Termologia","fisica-termica-termologia","tag_group_id","c1ce2cf2-b217-4cc7-8182-81c56bd3522d","parent_id","c8ab2a95-fd84-4d6f-ade0-835d34ba00f9","2025-04-29T03:44:27.560682+00:00",{"_151":152,"_153":154,"_155":156},"childrenCount",10,"content_count",0,"question_count",8575,"children",[],"video",{"_44":113,"_13":108,"_109":-5,"_161":162,"_163":164,"_28":-5,"_165":-5,"_126":164,"_166":167,"_137":-5,"_168":-5,"_169":-5,"_170":-5,"_171":-5,"_46":172,"_173":154,"_174":-5,"_99":175,"_118":176,"_120":176},"duration",17,"source_type","prometheus","iframe_url","provider_video_id","748a4adb-ad8f-4c5f-88a9-bc522d3b4246","format","quality","file_path","file_size",{"_116":117},"views_count","last_played_at","draft","2025-08-19T11:56:22.11908+00:00","tag","similarQuestions",[180,211,229],{"_40":181,"_42":43,"_44":182,"_77":183,"_96":199,"_97":200,"_51":201},"112831da-be9c-458e-94cb-e8292d0dba12","3c0b9441-b878-4896-8bac-fa4ca61e3f13",[184,187,190,193,196],{"_44":185,"_81":82,"_83":186},"265bd71a-6749-41f5-b291-67efd646ca64","y'' + 2y' - 3y = 0",{"_44":188,"_81":87,"_83":189},"6d3c3a1d-8e80-4ff3-b97a-d5b5bca91940","6y'' - y' - y = 0",{"_44":191,"_81":90,"_83":192},"4168ac67-64fd-46ed-a69c-a01dbfcde7ea","y'' - 2y' + y = 0",{"_44":194,"_81":94,"_83":195},"cc7bc8df-6995-4264-ac5a-32ea9b4ed7db","9y'' + 6y' + y = 0",{"_44":181,"_81":197,"_83":198},"E","y'' - 2y' + 6y = 0","Somente em y''−2y'+6y=0 o polinômio característico r²−2r+6=0 tem Δ<0, gerando raízes complexas conjugadas (1±i√5) e, portanto, solução em termos de exponencial modulando seno e cosseno. Nos demais itens (a–d) o discriminante é ≥0, produzindo raízes reais (distintas ou repetidas).","

Resolva as seguintes EDOs determinando a solução geral e, quando houver condições iniciais do PVI, a solução particular.

(a) y'' + 2y' - 3y = 0

(b) 6y'' - y' - y = 0

(d) 9y'' + 6y' + y = 0

(e) y'' - 2y' + 6y = 0

(f) 4y'' + 9y = 0

(g) 6y'' - 5y' + y = 0; \\, y(0) = 4; \\, y'(0) = 0

(h) y'' + 4y' + 4y = 0; \\, y(-1) = 2; \\, y'(-1) = 1

(i) y'' + y = 0; \\, y\bigg(\\frac{\\pi}{3}\\bigg) = 2; \\, y'\\bigg(\\frac{\\pi}{3}\\bigg) = -4

(j) y'' - 2y' - 3y = 3e^{2t}

(k) y'' + 9y = t^2 e^{3t} + 6

(l) 2y'' + 3y' + y = t^2 + 3 \\sin(t)

(m) y'' + y' - 2y = 2t; \\, y(0) = 0; \\, y'(0) = 1

(n) y'' - 2y' + y = te^t + 4; \\, y(0) = 1; \\, y'(0) = 1

(o) y'' + 4y = 3 \\sin(2t); \\, y(0) = 2; \\, y'(0) = -1

",[202],{"_44":203,"_57":204,"_59":205,"_145":146,"_147":206,"_118":207,"_120":207,"_46":208,"_122":205},"6516bbbd-f2a3-4710-8382-702240b17836","Mecânica na Engenharia de Petróleo","mecanica-na-engenharia-de-petroleo","b787e438-0ab3-454c-ab43-5d3d14c2720d","2025-04-29T03:44:35.328997+00:00",{"_151":209,"_153":154,"_155":210},4,12302,{"_40":212,"_42":43,"_44":213,"_77":214,"_96":226,"_97":227,"_51":228},"6831a9b9-c9a4-4a76-bd7a-2ce98bfea875","93a32dd4-5fc6-4ccb-a76f-4724bf113742",[215,218,221,223],{"_44":216,"_81":82,"_83":217},"13e3f476-a0a5-421f-b47e-0969e8e9a7e0","

Verdadeiro, verdadeiro, falso

",{"_44":219,"_81":87,"_83":220},"c9a20855-d84b-4860-8b35-9784818282cf","

Falso, verdadeiro, verdadeiro

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Verdadeiro, falso, verdadeiro

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Falso, falso, falso

","85,5 % decomposto → 14,5 % restante.\nN/N0 = 0,145 ⇒ t = ln(1/0,145)/(ln2/5730) ≈ 1,6×10⁴ anos.\nItens prováveis: (1) resta 14,5 % do C-14 (V); (2) idade ≈ 1,2×10⁴ anos ou 3 meias-vidas (F); (3) t½ do C-14 = 5730 anos (V). Sequência: V-F-V, correspondendo à alternativa c.","

Qual é a idade da madeira na qual 85,5\\% do C-14 se decompos?

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a) ????3 de ????4????5
b) ????2 de ????2????????2
c) ????1 de 2????????1
d) ????1 de 2????2????",[202],[202,251,258,268,275,282,283,291,297,302,308,315],{"_44":252,"_57":58,"_59":60,"_145":146,"_147":253,"_118":149,"_120":149,"_46":254,"_122":257},"6b6faf95-0e3a-4f58-abc8-e1444c48041d","92339f4f-ed20-4f4c-ad85-0c3de7e04ae0",{"_151":255,"_153":154,"_155":256},2,11846,"termodinamica-3",{"_44":259,"_57":260,"_59":261,"_145":146,"_147":262,"_118":263,"_120":263,"_46":264,"_122":267},"861ad829-750d-4a44-9569-2f18b430b4df","Engenharia Mecatrônica","engenharia-mecatronica","eb9315c5-bd04-4116-aa46-02c4fde320c0","2025-04-29T02:19:12.828432+00:00",{"_151":265,"_153":154,"_155":266},5,30614,"engenharia-mecatronica-1",{"_44":269,"_57":270,"_59":271,"_145":146,"_147":259,"_118":207,"_120":207,"_46":272,"_122":274},"88fe96b3-2a17-4198-90d5-ddda3d6f5d45","Mecânica","mecanica",{"_151":265,"_153":154,"_155":273},25741,"mecanica-3",{"_44":253,"_57":276,"_59":277,"_145":146,"_147":262,"_118":263,"_120":263,"_46":278,"_122":281},"Engenharia Mecânica","engenharia-mecanica",{"_151":279,"_153":154,"_155":280},11,36318,"engenharia-mecanica-2",{"_44":142,"_57":143,"_59":144,"_145":146,"_147":148,"_118":149,"_120":149,"_46":150,"_122":144},{"_44":284,"_57":285,"_59":286,"_145":146,"_147":-5,"_118":287,"_120":287,"_46":288,"_122":286},"9772e958-72c6-4499-ad47-877cf94d670d","Exatas","exatas","2025-04-29T01:56:45.284172+00:00",{"_151":289,"_153":154,"_155":290},18,135489,{"_44":292,"_57":58,"_59":60,"_145":146,"_147":203,"_118":293,"_120":293,"_46":294,"_122":296},"b21374de-aae5-4a4a-9bf3-0420e731797e","2025-04-29T04:00:14.680867+00:00",{"_151":154,"_153":154,"_155":295},8597,"termodinamica-5",{"_44":206,"_57":298,"_59":299,"_145":146,"_147":262,"_118":263,"_120":263,"_46":300,"_122":301},"Engenharia de Petróleo","engenharia-de-petroleo",{"_151":265,"_153":154,"_155":210},"engenharia-de-petroleo-1",{"_44":148,"_57":303,"_59":304,"_145":146,"_147":284,"_118":263,"_120":263,"_46":305,"_122":307},"Física","fisica",{"_151":279,"_153":154,"_155":306},13777,"fisica-4",{"_44":262,"_57":309,"_59":310,"_145":146,"_147":-5,"_118":311,"_120":311,"_46":312,"_122":310},"Engenharia","engenharia","2025-04-29T01:55:38.635246+00:00",{"_151":313,"_153":154,"_155":314},29,351586,{"_44":316,"_57":58,"_59":60,"_145":146,"_147":269,"_118":317,"_120":317,"_46":318,"_122":319},"f5967cbe-d751-4b40-81f2-04eb5dead2a9","2025-04-29T04:00:13.215003+00:00",{"_151":154,"_153":154,"_155":295},"termodinamica-4","tagsTree",[322,326],{"_44":284,"_57":285,"_59":286,"_145":146,"_147":-5,"_118":287,"_120":287,"_46":288,"_122":286,"_157":323},[324],{"_44":148,"_57":303,"_59":304,"_145":146,"_147":284,"_118":263,"_120":263,"_46":305,"_122":307,"_157":325},[141],{"_44":262,"_57":309,"_59":310,"_145":146,"_147":-5,"_118":311,"_120":311,"_46":312,"_122":310,"_157":327},[328,334,338],{"_44":259,"_57":260,"_59":261,"_145":146,"_147":262,"_118":263,"_120":263,"_46":264,"_122":267,"_157":329},[330],{"_44":269,"_57":270,"_59":271,"_145":146,"_147":259,"_118":207,"_120":207,"_46":272,"_122":274,"_157":331},[332],{"_44":316,"_57":58,"_59":60,"_145":146,"_147":269,"_118":317,"_120":317,"_46":318,"_122":319,"_157":333},[],{"_44":253,"_57":276,"_59":277,"_145":146,"_147":262,"_118":263,"_120":263,"_46":278,"_122":281,"_157":335},[336],{"_44":252,"_57":58,"_59":60,"_145":146,"_147":253,"_118":149,"_120":149,"_46":254,"_122":257,"_157":337},[],{"_44":206,"_57":298,"_59":299,"_145":146,"_147":262,"_118":263,"_120":263,"_46":300,"_122":301,"_157":339},[340],{"_44":203,"_57":204,"_59":205,"_145":146,"_147":206,"_118":207,"_120":207,"_46":208,"_122":205,"_157":341},[342],{"_44":292,"_57":58,"_59":60,"_145":146,"_147":203,"_118":293,"_120":293,"_46":294,"_122":296,"_157":343},[],"videoDislikes",{},"videoLikes",{},"actionData","errors"]

Comentários