[{"_1":2,"_352":-5,"_353":-5},"loaderData",{"_3":4,"_31":32},"root",{"_5":6,"_28":29,"_30":-5},"registerModalConfig",{"_7":8,"_15":16},"blockedConfig",{"_9":10,"_15":16,"_17":18,"_21":22,"_24":25},"answerQuestion",{"_11":12,"_13":14},"subtitle","Crie sua conta gratuita e utilize todos os nossos recursos de questões disponiveis","title","Para responder, cadastre-se gratuitamente","customBlockedUI",true,"defaultRegister",{"_11":19,"_13":20},"Crie sua conta gratuita e utilize todos os nossos recursos disponíveis","Cadastre-se gratuitamente","imageSearch",{"_11":19,"_13":23},"Para buscar por imagem, cadastre-se gratuitamente","questionAnswer",{"_11":26,"_13":27},"Crie sua conta gratuita e utilize todos os nossos recursos disponíveis para responder","Para ver a resposta, cadastre-se gratuitamente","url","https://prouniversitario.com/exercicios/925917e9-523c-4125-a1a5-7da1752b3908","user","pages/questions/show/index",{"_33":34,"_35":36,"_37":36,"_38":39,"_107":108,"_183":184,"_52":254,"_324":325,"_348":349,"_350":351},"comments",[],"hasVideoHash",false,"isAiGenerated","question",{"_40":41,"_42":43,"_44":45,"_46":47,"_78":79,"_101":43,"_102":103,"_104":105,"_106":16},"correctOptionId","262af94d-5709-43cc-889d-3e0c729778f3","difficulty","","id","925917e9-523c-4125-a1a5-7da1752b3908","metadata",{"_48":49,"_74":75,"_76":77},"pd",{"_50":51,"_52":53,"_54":55,"_62":63,"_64":65,"_66":16,"_67":68,"_69":16,"_70":71,"_72":73},"area","Outros","tags",[],"subjects",[56],{"_44":57,"_58":59,"_60":61},669639,"name","Termodinâmica","alias","termodinamica","materialId","126135960","answerCount",1,"isIndexable","mainSubject",{"_44":57,"_58":59,"_60":61},"isIndexableSEO","materialFormat","Text","studentDegreeLevel","Graduate","source","PD","externalId","126136369","options",[80,86,90,93,97],{"_44":81,"_82":83,"_84":85},"8096f746-e02d-4492-b6cb-2eedca80be99","label","A","text","

Fazer o furo de passagem da tubulação com a serra copo

",{"_44":87,"_82":88,"_84":89},"f0a9d3e0-b238-4af0-9c89-c861cb4951be","B","

Agilizar o serviço

",{"_44":41,"_82":91,"_84":92},"C","

Fazer os furos para fixação do suporte da condensadora

",{"_44":94,"_82":95,"_84":96},"5d797441-b7d1-4a64-8330-aa0c364799e4","D","

N.d.a

",{"_44":98,"_82":99,"_84":100},"cdce46c7-f13f-4245-8cee-c39dad4c5006","E","

Fazer os furos para fixação do suporte da evaporadora

","solution_explanation","statement","

Qual a função principal de uma parafusadeira na instalação de um ar condicionado split?

","status","pending_classification","hasRelatedVideo","relatedVideos",[109],{"_110":111,"_129":130,"_52":145,"_164":165,"_182":146},"content",{"_44":112,"_58":113,"_114":-5,"_115":116,"_117":118,"_119":-5,"_46":120,"_123":124,"_125":124,"_126":-5,"_127":128},"162087be-594f-460e-bbdd-a339ac2f10ad","Calor Latente - Parte 1","description","content_type_id","1051eee7-c62e-4b2c-9900-77a29fcec080","resource_id","f2b62fc2-7079-40e7-a5b5-c4a9769b205d","user_id",{"_121":122},"external_id","3659","created_at","2025-08-20T12:27:41.608438+00:00","updated_at","content_group_id","slug","calor-latente-parte-1","prometheusData",{"_131":132,"_138":139,"_140":141,"_142":143,"_28":144},"provider",{"_44":133,"_134":135,"_136":137},"06f120be-2194-4548-8336-7ba44ffbae14","key","grupo_q_proteus","kind","proteus","reference","bf8aacba-3de9-4b10-961c-47ada80dfe8c","state","completed","thumbnail_url","https://proteus.grupoq.io/videos/bf8aacba-3de9-4b10-961c-47ada80dfe8c/thumbnailsthumb.0000000.jpg","https://proteus.grupoq.io/videos/bf8aacba-3de9-4b10-961c-47ada80dfe8c/levels.m3u8",[146],{"_44":147,"_58":148,"_60":149,"_150":151,"_152":153,"_123":154,"_125":154,"_46":155,"_127":149,"_162":163},"96193fa0-9495-45b2-81cc-b547604354af","Física Térmica - Termologia","fisica-termica-termologia","tag_group_id","c1ce2cf2-b217-4cc7-8182-81c56bd3522d","parent_id","c8ab2a95-fd84-4d6f-ade0-835d34ba00f9","2025-04-29T03:44:27.560682+00:00",{"_156":157,"_158":159,"_160":161},"childrenCount",10,"content_count",0,"question_count",8575,"children",[],"video",{"_44":118,"_13":113,"_114":-5,"_166":167,"_168":169,"_28":-5,"_170":-5,"_131":169,"_171":172,"_142":-5,"_173":-5,"_174":-5,"_175":-5,"_176":-5,"_46":177,"_178":159,"_179":-5,"_104":180,"_123":181,"_125":181},"duration",17,"source_type","prometheus","iframe_url","provider_video_id","748a4adb-ad8f-4c5f-88a9-bc522d3b4246","format","quality","file_path","file_size",{"_121":122},"views_count","last_played_at","draft","2025-08-19T11:56:22.11908+00:00","tag","similarQuestions",[185,215,233],{"_40":186,"_42":43,"_44":187,"_78":188,"_101":203,"_102":204,"_52":205},"112831da-be9c-458e-94cb-e8292d0dba12","3c0b9441-b878-4896-8bac-fa4ca61e3f13",[189,192,195,198,201],{"_44":190,"_82":83,"_84":191},"265bd71a-6749-41f5-b291-67efd646ca64","y'' + 2y' - 3y = 0",{"_44":193,"_82":88,"_84":194},"6d3c3a1d-8e80-4ff3-b97a-d5b5bca91940","6y'' - y' - y = 0",{"_44":196,"_82":91,"_84":197},"4168ac67-64fd-46ed-a69c-a01dbfcde7ea","y'' - 2y' + y = 0",{"_44":199,"_82":95,"_84":200},"cc7bc8df-6995-4264-ac5a-32ea9b4ed7db","9y'' + 6y' + y = 0",{"_44":186,"_82":99,"_84":202},"y'' - 2y' + 6y = 0","Somente em y''−2y'+6y=0 o polinômio característico r²−2r+6=0 tem Δ<0, gerando raízes complexas conjugadas (1±i√5) e, portanto, solução em termos de exponencial modulando seno e cosseno. Nos demais itens (a–d) o discriminante é ≥0, produzindo raízes reais (distintas ou repetidas).","

Resolva as seguintes EDOs determinando a solução geral e, quando houver condições iniciais do PVI, a solução particular.

(a) y'' + 2y' - 3y = 0

(b) 6y'' - y' - y = 0

(d) 9y'' + 6y' + y = 0

(e) y'' - 2y' + 6y = 0

(f) 4y'' + 9y = 0

(g) 6y'' - 5y' + y = 0; \\, y(0) = 4; \\, y'(0) = 0

(h) y'' + 4y' + 4y = 0; \\, y(-1) = 2; \\, y'(-1) = 1

(i) y'' + y = 0; \\, y\bigg(\\frac{\\pi}{3}\\bigg) = 2; \\, y'\\bigg(\\frac{\\pi}{3}\\bigg) = -4

(j) y'' - 2y' - 3y = 3e^{2t}

(k) y'' + 9y = t^2 e^{3t} + 6

(l) 2y'' + 3y' + y = t^2 + 3 \\sin(t)

(m) y'' + y' - 2y = 2t; \\, y(0) = 0; \\, y'(0) = 1

(n) y'' - 2y' + y = te^t + 4; \\, y(0) = 1; \\, y'(0) = 1

(o) y'' + 4y = 3 \\sin(2t); \\, y(0) = 2; \\, y'(0) = -1

",[206],{"_44":207,"_58":208,"_60":209,"_150":151,"_152":210,"_123":211,"_125":211,"_46":212,"_127":209},"6516bbbd-f2a3-4710-8382-702240b17836","Mecânica na Engenharia de Petróleo","mecanica-na-engenharia-de-petroleo","b787e438-0ab3-454c-ab43-5d3d14c2720d","2025-04-29T03:44:35.328997+00:00",{"_156":213,"_158":159,"_160":214},4,12302,{"_40":216,"_42":43,"_44":217,"_78":218,"_101":230,"_102":231,"_52":232},"6831a9b9-c9a4-4a76-bd7a-2ce98bfea875","93a32dd4-5fc6-4ccb-a76f-4724bf113742",[219,222,225,227],{"_44":220,"_82":83,"_84":221},"13e3f476-a0a5-421f-b47e-0969e8e9a7e0","

Verdadeiro, verdadeiro, falso

",{"_44":223,"_82":88,"_84":224},"c9a20855-d84b-4860-8b35-9784818282cf","

Falso, verdadeiro, verdadeiro

",{"_44":216,"_82":91,"_84":226},"

Verdadeiro, falso, verdadeiro

",{"_44":228,"_82":95,"_84":229},"3c98539b-1af9-4d44-aecd-c266754a2075","

Falso, falso, falso

","85,5 % decomposto → 14,5 % restante.\nN/N0 = 0,145 ⇒ t = ln(1/0,145)/(ln2/5730) ≈ 1,6×10⁴ anos.\nItens prováveis: (1) resta 14,5 % do C-14 (V); (2) idade ≈ 1,2×10⁴ anos ou 3 meias-vidas (F); (3) t½ do C-14 = 5730 anos (V). Sequência: V-F-V, correspondendo à alternativa c.","

Qual é a idade da madeira na qual 85,5\\% do C-14 se decompos?

",[206],{"_40":234,"_42":43,"_44":235,"_78":236,"_101":251,"_102":252,"_52":253},"3ce109b1-6cdb-4b4d-8816-a6af4d74bed0","c478a46c-46a8-4942-ae14-2e79def3dda2",[237,240,243,245,248],{"_44":238,"_82":83,"_84":239},"a5a16a42-3e58-4c76-80f2-c291aa2d8e49","Sim",{"_44":241,"_82":88,"_84":242},"5e6d0254-696c-4da0-b572-82e3a19f433e","Não",{"_44":234,"_82":91,"_84":244},"Indeterminado",{"_44":246,"_82":95,"_84":247},"35403f68-a880-429d-97f4-db507c58de38","Todos",{"_44":249,"_82":99,"_84":250},"2e06d948-d37e-4350-afc7-ced04941bcaf","Nenhum","Os polinômios e números fornecidos estão corrompidos (símbolos “????”), impossibilitando aplicar Ruffini e concluir se são raízes. Sem dados completos, o problema é indeterminado.","Emplea la regla de Ruffini para dictaminar si los siguientes números son o no raíces de los polinomios citados:
a) ????3 de ????4????5
b) ????2 de ????2????????2
c) ????1 de 2????????1
d) ????1 de 2????2????",[206],[206,255,262,272,279,286,287,295,301,306,312,319],{"_44":256,"_58":59,"_60":61,"_150":151,"_152":257,"_123":154,"_125":154,"_46":258,"_127":261},"6b6faf95-0e3a-4f58-abc8-e1444c48041d","92339f4f-ed20-4f4c-ad85-0c3de7e04ae0",{"_156":259,"_158":159,"_160":260},2,11846,"termodinamica-3",{"_44":263,"_58":264,"_60":265,"_150":151,"_152":266,"_123":267,"_125":267,"_46":268,"_127":271},"861ad829-750d-4a44-9569-2f18b430b4df","Engenharia Mecatrônica","engenharia-mecatronica","eb9315c5-bd04-4116-aa46-02c4fde320c0","2025-04-29T02:19:12.828432+00:00",{"_156":269,"_158":159,"_160":270},5,30614,"engenharia-mecatronica-1",{"_44":273,"_58":274,"_60":275,"_150":151,"_152":263,"_123":211,"_125":211,"_46":276,"_127":278},"88fe96b3-2a17-4198-90d5-ddda3d6f5d45","Mecânica","mecanica",{"_156":269,"_158":159,"_160":277},25741,"mecanica-3",{"_44":257,"_58":280,"_60":281,"_150":151,"_152":266,"_123":267,"_125":267,"_46":282,"_127":285},"Engenharia Mecânica","engenharia-mecanica",{"_156":283,"_158":159,"_160":284},11,36318,"engenharia-mecanica-2",{"_44":147,"_58":148,"_60":149,"_150":151,"_152":153,"_123":154,"_125":154,"_46":155,"_127":149},{"_44":288,"_58":289,"_60":290,"_150":151,"_152":-5,"_123":291,"_125":291,"_46":292,"_127":290},"9772e958-72c6-4499-ad47-877cf94d670d","Exatas","exatas","2025-04-29T01:56:45.284172+00:00",{"_156":293,"_158":159,"_160":294},18,135489,{"_44":296,"_58":59,"_60":61,"_150":151,"_152":207,"_123":297,"_125":297,"_46":298,"_127":300},"b21374de-aae5-4a4a-9bf3-0420e731797e","2025-04-29T04:00:14.680867+00:00",{"_156":159,"_158":159,"_160":299},8597,"termodinamica-5",{"_44":210,"_58":302,"_60":303,"_150":151,"_152":266,"_123":267,"_125":267,"_46":304,"_127":305},"Engenharia de Petróleo","engenharia-de-petroleo",{"_156":269,"_158":159,"_160":214},"engenharia-de-petroleo-1",{"_44":153,"_58":307,"_60":308,"_150":151,"_152":288,"_123":267,"_125":267,"_46":309,"_127":311},"Física","fisica",{"_156":283,"_158":159,"_160":310},13777,"fisica-4",{"_44":266,"_58":313,"_60":314,"_150":151,"_152":-5,"_123":315,"_125":315,"_46":316,"_127":314},"Engenharia","engenharia","2025-04-29T01:55:38.635246+00:00",{"_156":317,"_158":159,"_160":318},29,351586,{"_44":320,"_58":59,"_60":61,"_150":151,"_152":273,"_123":321,"_125":321,"_46":322,"_127":323},"f5967cbe-d751-4b40-81f2-04eb5dead2a9","2025-04-29T04:00:13.215003+00:00",{"_156":159,"_158":159,"_160":299},"termodinamica-4","tagsTree",[326,330],{"_44":288,"_58":289,"_60":290,"_150":151,"_152":-5,"_123":291,"_125":291,"_46":292,"_127":290,"_162":327},[328],{"_44":153,"_58":307,"_60":308,"_150":151,"_152":288,"_123":267,"_125":267,"_46":309,"_127":311,"_162":329},[146],{"_44":266,"_58":313,"_60":314,"_150":151,"_152":-5,"_123":315,"_125":315,"_46":316,"_127":314,"_162":331},[332,338,342],{"_44":263,"_58":264,"_60":265,"_150":151,"_152":266,"_123":267,"_125":267,"_46":268,"_127":271,"_162":333},[334],{"_44":273,"_58":274,"_60":275,"_150":151,"_152":263,"_123":211,"_125":211,"_46":276,"_127":278,"_162":335},[336],{"_44":320,"_58":59,"_60":61,"_150":151,"_152":273,"_123":321,"_125":321,"_46":322,"_127":323,"_162":337},[],{"_44":257,"_58":280,"_60":281,"_150":151,"_152":266,"_123":267,"_125":267,"_46":282,"_127":285,"_162":339},[340],{"_44":256,"_58":59,"_60":61,"_150":151,"_152":257,"_123":154,"_125":154,"_46":258,"_127":261,"_162":341},[],{"_44":210,"_58":302,"_60":303,"_150":151,"_152":266,"_123":267,"_125":267,"_46":304,"_127":305,"_162":343},[344],{"_44":207,"_58":208,"_60":209,"_150":151,"_152":210,"_123":211,"_125":211,"_46":212,"_127":209,"_162":345},[346],{"_44":296,"_58":59,"_60":61,"_150":151,"_152":207,"_123":297,"_125":297,"_46":298,"_127":300,"_162":347},[],"videoDislikes",{},"videoLikes",{},"actionData","errors"]

Comentários