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A eficiência teórica mais alta que uma certa máquina pode atingir é de 30 \\%. Se esta máquina utiliza a atmosfera, que está a uma temperatura de 300 \\text{ K}, no seu reservatório frio, a temperatura do reservatório quente vai ser:

","status","pending_classification","hasRelatedVideo","relatedVideos",[122],{"_123":124,"_142":143,"_50":158,"_177":178,"_195":159},"content",{"_43":125,"_54":126,"_127":-5,"_128":129,"_130":131,"_132":-5,"_45":133,"_136":137,"_138":137,"_139":-5,"_140":141},"162087be-594f-460e-bbdd-a339ac2f10ad","Calor Latente - Parte 1","description","content_type_id","1051eee7-c62e-4b2c-9900-77a29fcec080","resource_id","f2b62fc2-7079-40e7-a5b5-c4a9769b205d","user_id",{"_134":135},"external_id","3659","created_at","2025-08-20T12:27:41.608438+00:00","updated_at","content_group_id","slug","calor-latente-parte-1","prometheusData",{"_144":145,"_151":152,"_153":154,"_155":156,"_28":157},"provider",{"_43":146,"_147":148,"_149":150},"06f120be-2194-4548-8336-7ba44ffbae14","key","grupo_q_proteus","kind","proteus","reference","bf8aacba-3de9-4b10-961c-47ada80dfe8c","state","completed","thumbnail_url","https://proteus.grupoq.io/videos/bf8aacba-3de9-4b10-961c-47ada80dfe8c/thumbnailsthumb.0000000.jpg","https://proteus.grupoq.io/videos/bf8aacba-3de9-4b10-961c-47ada80dfe8c/levels.m3u8",[159],{"_43":160,"_54":161,"_56":162,"_163":164,"_165":166,"_136":167,"_138":167,"_45":168,"_140":162,"_175":176},"96193fa0-9495-45b2-81cc-b547604354af","Física Térmica - Termologia","fisica-termica-termologia","tag_group_id","c1ce2cf2-b217-4cc7-8182-81c56bd3522d","parent_id","c8ab2a95-fd84-4d6f-ade0-835d34ba00f9","2025-04-29T03:44:27.560682+00:00",{"_169":170,"_171":172,"_173":174},"childrenCount",10,"content_count",0,"question_count",8575,"children",[],"video",{"_43":131,"_13":126,"_127":-5,"_179":180,"_181":182,"_28":-5,"_183":-5,"_144":182,"_184":185,"_155":-5,"_186":-5,"_187":-5,"_188":-5,"_189":-5,"_45":190,"_191":172,"_192":-5,"_117":193,"_136":194,"_138":194},"duration",17,"source_type","prometheus","iframe_url","provider_video_id","748a4adb-ad8f-4c5f-88a9-bc522d3b4246","format","quality","file_path","file_size",{"_134":135},"views_count","last_played_at","draft","2025-08-19T11:56:22.11908+00:00","tag","similarQuestions",[198,228,246],{"_40":199,"_42":41,"_43":200,"_90":201,"_114":216,"_115":217,"_50":218},"112831da-be9c-458e-94cb-e8292d0dba12","3c0b9441-b878-4896-8bac-fa4ca61e3f13",[202,205,208,211,214],{"_43":203,"_94":95,"_96":204},"265bd71a-6749-41f5-b291-67efd646ca64","y'' + 2y' - 3y = 0",{"_43":206,"_94":100,"_96":207},"6d3c3a1d-8e80-4ff3-b97a-d5b5bca91940","6y'' - y' - y = 0",{"_43":209,"_94":104,"_96":210},"4168ac67-64fd-46ed-a69c-a01dbfcde7ea","y'' - 2y' + y = 0",{"_43":212,"_94":108,"_96":213},"cc7bc8df-6995-4264-ac5a-32ea9b4ed7db","9y'' + 6y' + y = 0",{"_43":199,"_94":112,"_96":215},"y'' - 2y' + 6y = 0","Somente em y''−2y'+6y=0 o polinômio característico r²−2r+6=0 tem Δ<0, gerando raízes complexas conjugadas (1±i√5) e, portanto, solução em termos de exponencial modulando seno e cosseno. Nos demais itens (a–d) o discriminante é ≥0, produzindo raízes reais (distintas ou repetidas).","

Resolva as seguintes EDOs determinando a solução geral e, quando houver condições iniciais do PVI, a solução particular.

(a) y'' + 2y' - 3y = 0

(b) 6y'' - y' - y = 0

(d) 9y'' + 6y' + y = 0

(e) y'' - 2y' + 6y = 0

(f) 4y'' + 9y = 0

(g) 6y'' - 5y' + y = 0; \\, y(0) = 4; \\, y'(0) = 0

(h) y'' + 4y' + 4y = 0; \\, y(-1) = 2; \\, y'(-1) = 1

(i) y'' + y = 0; \\, y\bigg(\\frac{\\pi}{3}\\bigg) = 2; \\, y'\\bigg(\\frac{\\pi}{3}\\bigg) = -4

(j) y'' - 2y' - 3y = 3e^{2t}

(k) y'' + 9y = t^2 e^{3t} + 6

(l) 2y'' + 3y' + y = t^2 + 3 \\sin(t)

(m) y'' + y' - 2y = 2t; \\, y(0) = 0; \\, y'(0) = 1

(n) y'' - 2y' + y = te^t + 4; \\, y(0) = 1; \\, y'(0) = 1

(o) y'' + 4y = 3 \\sin(2t); \\, y(0) = 2; \\, y'(0) = -1

",[219],{"_43":220,"_54":221,"_56":222,"_163":164,"_165":223,"_136":224,"_138":224,"_45":225,"_140":222},"6516bbbd-f2a3-4710-8382-702240b17836","Mecânica na Engenharia de Petróleo","mecanica-na-engenharia-de-petroleo","b787e438-0ab3-454c-ab43-5d3d14c2720d","2025-04-29T03:44:35.328997+00:00",{"_169":226,"_171":172,"_173":227},4,12302,{"_40":229,"_42":41,"_43":230,"_90":231,"_114":243,"_115":244,"_50":245},"6831a9b9-c9a4-4a76-bd7a-2ce98bfea875","93a32dd4-5fc6-4ccb-a76f-4724bf113742",[232,235,238,240],{"_43":233,"_94":95,"_96":234},"13e3f476-a0a5-421f-b47e-0969e8e9a7e0","

Verdadeiro, verdadeiro, falso

",{"_43":236,"_94":100,"_96":237},"c9a20855-d84b-4860-8b35-9784818282cf","

Falso, verdadeiro, verdadeiro

",{"_43":229,"_94":104,"_96":239},"

Verdadeiro, falso, verdadeiro

",{"_43":241,"_94":108,"_96":242},"3c98539b-1af9-4d44-aecd-c266754a2075","

Falso, falso, falso

","85,5 % decomposto → 14,5 % restante.\nN/N0 = 0,145 ⇒ t = ln(1/0,145)/(ln2/5730) ≈ 1,6×10⁴ anos.\nItens prováveis: (1) resta 14,5 % do C-14 (V); (2) idade ≈ 1,2×10⁴ anos ou 3 meias-vidas (F); (3) t½ do C-14 = 5730 anos (V). Sequência: V-F-V, correspondendo à alternativa c.","

Qual é a idade da madeira na qual 85,5\\% do C-14 se decompos?

",[219],{"_40":247,"_42":41,"_43":248,"_90":249,"_114":264,"_115":265,"_50":266},"3ce109b1-6cdb-4b4d-8816-a6af4d74bed0","c478a46c-46a8-4942-ae14-2e79def3dda2",[250,253,256,258,261],{"_43":251,"_94":95,"_96":252},"a5a16a42-3e58-4c76-80f2-c291aa2d8e49","Sim",{"_43":254,"_94":100,"_96":255},"5e6d0254-696c-4da0-b572-82e3a19f433e","Não",{"_43":247,"_94":104,"_96":257},"Indeterminado",{"_43":259,"_94":108,"_96":260},"35403f68-a880-429d-97f4-db507c58de38","Todos",{"_43":262,"_94":112,"_96":263},"2e06d948-d37e-4350-afc7-ced04941bcaf","Nenhum","Os polinômios e números fornecidos estão corrompidos (símbolos “????”), impossibilitando aplicar Ruffini e concluir se são raízes. Sem dados completos, o problema é indeterminado.","Emplea la regla de Ruffini para dictaminar si los siguientes números son o no raíces de los polinomios citados:
a) ????3 de ????4????5
b) ????2 de ????2????????2
c) ????1 de 2????????1
d) ????1 de 2????2????",[219],[219,268,275,285,292,299,300,308,314,319,325,332],{"_43":269,"_54":72,"_56":73,"_163":164,"_165":270,"_136":167,"_138":167,"_45":271,"_140":274},"6b6faf95-0e3a-4f58-abc8-e1444c48041d","92339f4f-ed20-4f4c-ad85-0c3de7e04ae0",{"_169":272,"_171":172,"_173":273},2,11846,"termodinamica-3",{"_43":276,"_54":277,"_56":278,"_163":164,"_165":279,"_136":280,"_138":280,"_45":281,"_140":284},"861ad829-750d-4a44-9569-2f18b430b4df","Engenharia Mecatrônica","engenharia-mecatronica","eb9315c5-bd04-4116-aa46-02c4fde320c0","2025-04-29T02:19:12.828432+00:00",{"_169":282,"_171":172,"_173":283},5,30614,"engenharia-mecatronica-1",{"_43":286,"_54":287,"_56":288,"_163":164,"_165":276,"_136":224,"_138":224,"_45":289,"_140":291},"88fe96b3-2a17-4198-90d5-ddda3d6f5d45","Mecânica","mecanica",{"_169":282,"_171":172,"_173":290},25741,"mecanica-3",{"_43":270,"_54":293,"_56":294,"_163":164,"_165":279,"_136":280,"_138":280,"_45":295,"_140":298},"Engenharia Mecânica","engenharia-mecanica",{"_169":296,"_171":172,"_173":297},11,36318,"engenharia-mecanica-2",{"_43":160,"_54":161,"_56":162,"_163":164,"_165":166,"_136":167,"_138":167,"_45":168,"_140":162},{"_43":301,"_54":302,"_56":303,"_163":164,"_165":-5,"_136":304,"_138":304,"_45":305,"_140":303},"9772e958-72c6-4499-ad47-877cf94d670d","Exatas","exatas","2025-04-29T01:56:45.284172+00:00",{"_169":306,"_171":172,"_173":307},18,135489,{"_43":309,"_54":72,"_56":73,"_163":164,"_165":220,"_136":310,"_138":310,"_45":311,"_140":313},"b21374de-aae5-4a4a-9bf3-0420e731797e","2025-04-29T04:00:14.680867+00:00",{"_169":172,"_171":172,"_173":312},8597,"termodinamica-5",{"_43":223,"_54":315,"_56":316,"_163":164,"_165":279,"_136":280,"_138":280,"_45":317,"_140":318},"Engenharia de Petróleo","engenharia-de-petroleo",{"_169":282,"_171":172,"_173":227},"engenharia-de-petroleo-1",{"_43":166,"_54":320,"_56":321,"_163":164,"_165":301,"_136":280,"_138":280,"_45":322,"_140":324},"Física","fisica",{"_169":296,"_171":172,"_173":323},13777,"fisica-4",{"_43":279,"_54":326,"_56":327,"_163":164,"_165":-5,"_136":328,"_138":328,"_45":329,"_140":327},"Engenharia","engenharia","2025-04-29T01:55:38.635246+00:00",{"_169":330,"_171":172,"_173":331},29,351586,{"_43":333,"_54":72,"_56":73,"_163":164,"_165":286,"_136":334,"_138":334,"_45":335,"_140":336},"f5967cbe-d751-4b40-81f2-04eb5dead2a9","2025-04-29T04:00:13.215003+00:00",{"_169":172,"_171":172,"_173":312},"termodinamica-4","tagsTree",[339,343],{"_43":301,"_54":302,"_56":303,"_163":164,"_165":-5,"_136":304,"_138":304,"_45":305,"_140":303,"_175":340},[341],{"_43":166,"_54":320,"_56":321,"_163":164,"_165":301,"_136":280,"_138":280,"_45":322,"_140":324,"_175":342},[159],{"_43":279,"_54":326,"_56":327,"_163":164,"_165":-5,"_136":328,"_138":328,"_45":329,"_140":327,"_175":344},[345,351,355],{"_43":276,"_54":277,"_56":278,"_163":164,"_165":279,"_136":280,"_138":280,"_45":281,"_140":284,"_175":346},[347],{"_43":286,"_54":287,"_56":288,"_163":164,"_165":276,"_136":224,"_138":224,"_45":289,"_140":291,"_175":348},[349],{"_43":333,"_54":72,"_56":73,"_163":164,"_165":286,"_136":334,"_138":334,"_45":335,"_140":336,"_175":350},[],{"_43":270,"_54":293,"_56":294,"_163":164,"_165":279,"_136":280,"_138":280,"_45":295,"_140":298,"_175":352},[353],{"_43":269,"_54":72,"_56":73,"_163":164,"_165":270,"_136":167,"_138":167,"_45":271,"_140":274,"_175":354},[],{"_43":223,"_54":315,"_56":316,"_163":164,"_165":279,"_136":280,"_138":280,"_45":317,"_140":318,"_175":356},[357],{"_43":220,"_54":221,"_56":222,"_163":164,"_165":223,"_136":224,"_138":224,"_45":225,"_140":222,"_175":358},[359],{"_43":309,"_54":72,"_56":73,"_163":164,"_165":220,"_136":310,"_138":310,"_45":311,"_140":313,"_175":360},[],"videoDislikes",{},"videoLikes",{},"actionData","errors"]

Comentários