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78 K

",{"_43":86,"_81":87,"_83":88},"06cdddf8-7ca3-419d-b4fe-aedef8176970","B","

83 K

",{"_43":90,"_81":91,"_83":92},"b69c0bc7-a9c1-4bbf-8645-3376053158f2","C","

91 K

",{"_43":94,"_81":95,"_83":96},"eb87e537-7e30-4c58-a6e3-9e014d986a8e","D","

97 K

",{"_43":98,"_81":99,"_83":100},"0a1c734e-2306-4259-ba4b-a6c016a9c766","E","

100 K

","solution_explanation","statement","

Uma máquina de Carnot cuja fonte fria está a 290 \text{ K} tem uma eficiência de 40\text{%}. De quanto deve ser elevada a temperatura da fonte quente para que a eficiência aumente para 50\text{%}?

","status","pending_classification","hasRelatedVideo","relatedVideos",[109],{"_110":111,"_129":130,"_51":145,"_164":165,"_182":183},"content",{"_43":112,"_57":113,"_114":-5,"_115":116,"_117":118,"_119":-5,"_45":120,"_123":124,"_125":124,"_126":-5,"_127":128},"162087be-594f-460e-bbdd-a339ac2f10ad","Calor Latente - Parte 1","description","content_type_id","1051eee7-c62e-4b2c-9900-77a29fcec080","resource_id","f2b62fc2-7079-40e7-a5b5-c4a9769b205d","user_id",{"_121":122},"external_id","3659","created_at","2025-08-20T12:27:41.608438+00:00","updated_at","content_group_id","slug","calor-latente-parte-1","prometheusData",{"_131":132,"_138":139,"_140":141,"_142":143,"_28":144},"provider",{"_43":133,"_134":135,"_136":137},"06f120be-2194-4548-8336-7ba44ffbae14","key","grupo_q_proteus","kind","proteus","reference","bf8aacba-3de9-4b10-961c-47ada80dfe8c","state","completed","thumbnail_url","https://proteus.grupoq.io/videos/bf8aacba-3de9-4b10-961c-47ada80dfe8c/thumbnailsthumb.0000000.jpg","https://proteus.grupoq.io/videos/bf8aacba-3de9-4b10-961c-47ada80dfe8c/levels.m3u8",[146],{"_43":147,"_57":148,"_59":149,"_150":151,"_152":153,"_123":154,"_125":154,"_45":155,"_127":149,"_162":163},"96193fa0-9495-45b2-81cc-b547604354af","Física Térmica - Termologia","fisica-termica-termologia","tag_group_id","c1ce2cf2-b217-4cc7-8182-81c56bd3522d","parent_id","c8ab2a95-fd84-4d6f-ade0-835d34ba00f9","2025-04-29T03:44:27.560682+00:00",{"_156":157,"_158":159,"_160":161},"childrenCount",10,"content_count",0,"question_count",8575,"children",[],"video",{"_43":118,"_13":113,"_114":-5,"_166":167,"_168":169,"_28":-5,"_170":-5,"_131":169,"_171":172,"_142":-5,"_173":-5,"_174":-5,"_175":-5,"_176":-5,"_45":177,"_178":159,"_179":-5,"_104":180,"_123":181,"_125":181},"duration",17,"source_type","prometheus","iframe_url","provider_video_id","748a4adb-ad8f-4c5f-88a9-bc522d3b4246","format","quality","file_path","file_size",{"_121":122},"views_count","last_played_at","draft","2025-08-19T11:56:22.11908+00:00","tag",{"_43":147,"_57":148,"_59":149,"_150":151,"_152":153,"_123":154,"_125":154,"_45":184,"_127":149,"_162":185},{"_156":157,"_158":159,"_160":161},[],"similarQuestions",[188,218,238],{"_40":189,"_42":41,"_43":190,"_77":191,"_101":206,"_102":207,"_51":208},"112831da-be9c-458e-94cb-e8292d0dba12","3c0b9441-b878-4896-8bac-fa4ca61e3f13",[192,195,198,201,204],{"_43":193,"_81":82,"_83":194},"265bd71a-6749-41f5-b291-67efd646ca64","y'' + 2y' - 3y = 0",{"_43":196,"_81":87,"_83":197},"6d3c3a1d-8e80-4ff3-b97a-d5b5bca91940","6y'' - y' - y = 0",{"_43":199,"_81":91,"_83":200},"4168ac67-64fd-46ed-a69c-a01dbfcde7ea","y'' - 2y' + y = 0",{"_43":202,"_81":95,"_83":203},"cc7bc8df-6995-4264-ac5a-32ea9b4ed7db","9y'' + 6y' + y = 0",{"_43":189,"_81":99,"_83":205},"y'' - 2y' + 6y = 0","Somente em y''−2y'+6y=0 o polinômio característico r²−2r+6=0 tem Δ<0, gerando raízes complexas conjugadas (1±i√5) e, portanto, solução em termos de exponencial modulando seno e cosseno. Nos demais itens (a–d) o discriminante é ≥0, produzindo raízes reais (distintas ou repetidas).","

Resolva as seguintes EDOs determinando a solução geral e, quando houver condições iniciais do PVI, a solução particular.

(a) y'' + 2y' - 3y = 0

(b) 6y'' - y' - y = 0

(d) 9y'' + 6y' + y = 0

(e) y'' - 2y' + 6y = 0

(f) 4y'' + 9y = 0

(g) 6y'' - 5y' + y = 0; \\, y(0) = 4; \\, y'(0) = 0

(h) y'' + 4y' + 4y = 0; \\, y(-1) = 2; \\, y'(-1) = 1

(i) y'' + y = 0; \\, y\bigg(\\frac{\\pi}{3}\\bigg) = 2; \\, y'\\bigg(\\frac{\\pi}{3}\\bigg) = -4

(j) y'' - 2y' - 3y = 3e^{2t}

(k) y'' + 9y = t^2 e^{3t} + 6

(l) 2y'' + 3y' + y = t^2 + 3 \\sin(t)

(m) y'' + y' - 2y = 2t; \\, y(0) = 0; \\, y'(0) = 1

(n) y'' - 2y' + y = te^t + 4; \\, y(0) = 1; \\, y'(0) = 1

(o) y'' + 4y = 3 \\sin(2t); \\, y(0) = 2; \\, y'(0) = -1

",[209],{"_43":210,"_57":211,"_59":212,"_150":151,"_152":213,"_123":214,"_125":214,"_45":215,"_127":212},"6516bbbd-f2a3-4710-8382-702240b17836","Mecânica na Engenharia de Petróleo","mecanica-na-engenharia-de-petroleo","b787e438-0ab3-454c-ab43-5d3d14c2720d","2025-04-29T03:44:35.328997+00:00",{"_156":216,"_158":159,"_160":217},4,12302,{"_40":219,"_42":41,"_43":220,"_77":221,"_101":233,"_102":234,"_51":235},"6831a9b9-c9a4-4a76-bd7a-2ce98bfea875","93a32dd4-5fc6-4ccb-a76f-4724bf113742",[222,225,228,230],{"_43":223,"_81":82,"_83":224},"13e3f476-a0a5-421f-b47e-0969e8e9a7e0","

Verdadeiro, verdadeiro, falso

",{"_43":226,"_81":87,"_83":227},"c9a20855-d84b-4860-8b35-9784818282cf","

Falso, verdadeiro, verdadeiro

",{"_43":219,"_81":91,"_83":229},"

Verdadeiro, falso, verdadeiro

",{"_43":231,"_81":95,"_83":232},"3c98539b-1af9-4d44-aecd-c266754a2075","

Falso, falso, falso

","85,5 % decomposto → 14,5 % restante.\nN/N0 = 0,145 ⇒ t = ln(1/0,145)/(ln2/5730) ≈ 1,6×10⁴ anos.\nItens prováveis: (1) resta 14,5 % do C-14 (V); (2) idade ≈ 1,2×10⁴ anos ou 3 meias-vidas (F); (3) t½ do C-14 = 5730 anos (V). Sequência: V-F-V, correspondendo à alternativa c.","

Qual é a idade da madeira na qual 85,5\\% do C-14 se decompos?

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a) ????3 de ????4????5
b) ????2 de ????2????????2
c) ????1 de 2????????1
d) ????1 de 2????2????",[259],{"_43":210,"_57":211,"_59":212,"_150":151,"_152":213,"_123":214,"_125":214,"_45":260,"_127":212},{"_156":216,"_158":159,"_160":217},[262,264,271,281,288,295,297,305,311,316,322,329],{"_43":210,"_57":211,"_59":212,"_150":151,"_152":213,"_123":214,"_125":214,"_45":263,"_127":212},{"_156":216,"_158":159,"_160":217},{"_43":265,"_57":58,"_59":60,"_150":151,"_152":266,"_123":154,"_125":154,"_45":267,"_127":270},"6b6faf95-0e3a-4f58-abc8-e1444c48041d","92339f4f-ed20-4f4c-ad85-0c3de7e04ae0",{"_156":268,"_158":159,"_160":269},2,11846,"termodinamica-3",{"_43":272,"_57":273,"_59":274,"_150":151,"_152":275,"_123":276,"_125":276,"_45":277,"_127":280},"861ad829-750d-4a44-9569-2f18b430b4df","Engenharia Mecatrônica","engenharia-mecatronica","eb9315c5-bd04-4116-aa46-02c4fde320c0","2025-04-29T02:19:12.828432+00:00",{"_156":278,"_158":159,"_160":279},5,30614,"engenharia-mecatronica-1",{"_43":282,"_57":283,"_59":284,"_150":151,"_152":272,"_123":214,"_125":214,"_45":285,"_127":287},"88fe96b3-2a17-4198-90d5-ddda3d6f5d45","Mecânica","mecanica",{"_156":278,"_158":159,"_160":286},25741,"mecanica-3",{"_43":266,"_57":289,"_59":290,"_150":151,"_152":275,"_123":276,"_125":276,"_45":291,"_127":294},"Engenharia Mecânica","engenharia-mecanica",{"_156":292,"_158":159,"_160":293},11,36318,"engenharia-mecanica-2",{"_43":147,"_57":148,"_59":149,"_150":151,"_152":153,"_123":154,"_125":154,"_45":296,"_127":149},{"_156":157,"_158":159,"_160":161},{"_43":298,"_57":299,"_59":300,"_150":151,"_152":-5,"_123":301,"_125":301,"_45":302,"_127":300},"9772e958-72c6-4499-ad47-877cf94d670d","Exatas","exatas","2025-04-29T01:56:45.284172+00:00",{"_156":303,"_158":159,"_160":304},18,135489,{"_43":306,"_57":58,"_59":60,"_150":151,"_152":210,"_123":307,"_125":307,"_45":308,"_127":310},"b21374de-aae5-4a4a-9bf3-0420e731797e","2025-04-29T04:00:14.680867+00:00",{"_156":159,"_158":159,"_160":309},8597,"termodinamica-5",{"_43":213,"_57":312,"_59":313,"_150":151,"_152":275,"_123":276,"_125":276,"_45":314,"_127":315},"Engenharia de Petróleo","engenharia-de-petroleo",{"_156":278,"_158":159,"_160":217},"engenharia-de-petroleo-1",{"_43":153,"_57":317,"_59":318,"_150":151,"_152":298,"_123":276,"_125":276,"_45":319,"_127":321},"Física","fisica",{"_156":292,"_158":159,"_160":320},13777,"fisica-4",{"_43":275,"_57":323,"_59":324,"_150":151,"_152":-5,"_123":325,"_125":325,"_45":326,"_127":324},"Engenharia","engenharia","2025-04-29T01:55:38.635246+00:00",{"_156":327,"_158":159,"_160":328},29,351586,{"_43":330,"_57":58,"_59":60,"_150":151,"_152":282,"_123":331,"_125":331,"_45":332,"_127":333},"f5967cbe-d751-4b40-81f2-04eb5dead2a9","2025-04-29T04:00:13.215003+00:00",{"_156":159,"_158":159,"_160":309},"termodinamica-4","tagsTree",[336,345],{"_43":298,"_57":299,"_59":300,"_150":151,"_152":-5,"_123":301,"_125":301,"_45":337,"_127":300,"_162":338},{"_156":303,"_158":159,"_160":304},[339],{"_43":153,"_57":317,"_59":318,"_150":151,"_152":298,"_123":276,"_125":276,"_45":340,"_127":321,"_162":341},{"_156":292,"_158":159,"_160":320},[342],{"_43":147,"_57":148,"_59":149,"_150":151,"_152":153,"_123":154,"_125":154,"_45":343,"_127":149,"_162":344},{"_156":157,"_158":159,"_160":161},[],{"_43":275,"_57":323,"_59":324,"_150":151,"_152":-5,"_123":325,"_125":325,"_45":346,"_127":324,"_162":347},{"_156":327,"_158":159,"_160":328},[348,357,363],{"_43":272,"_57":273,"_59":274,"_150":151,"_152":275,"_123":276,"_125":276,"_45":349,"_127":280,"_162":350},{"_156":278,"_158":159,"_160":279},[351],{"_43":282,"_57":283,"_59":284,"_150":151,"_152":272,"_123":214,"_125":214,"_45":352,"_127":287,"_162":353},{"_156":278,"_158":159,"_160":286},[354],{"_43":330,"_57":58,"_59":60,"_150":151,"_152":282,"_123":331,"_125":331,"_45":355,"_127":333,"_162":356},{"_156":159,"_158":159,"_160":309},[],{"_43":266,"_57":289,"_59":290,"_150":151,"_152":275,"_123":276,"_125":276,"_45":358,"_127":294,"_162":359},{"_156":292,"_158":159,"_160":293},[360],{"_43":265,"_57":58,"_59":60,"_150":151,"_152":266,"_123":154,"_125":154,"_45":361,"_127":270,"_162":362},{"_156":268,"_158":159,"_160":269},[],{"_43":213,"_57":312,"_59":313,"_150":151,"_152":275,"_123":276,"_125":276,"_45":364,"_127":315,"_162":365},{"_156":278,"_158":159,"_160":217},[366],{"_43":210,"_57":211,"_59":212,"_150":151,"_152":213,"_123":214,"_125":214,"_45":367,"_127":212,"_162":368},{"_156":216,"_158":159,"_160":217},[369],{"_43":306,"_57":58,"_59":60,"_150":151,"_152":210,"_123":307,"_125":307,"_45":370,"_127":310,"_162":371},{"_156":159,"_158":159,"_160":309},[],"videoDislikes",{},"videoLikes",{},"actionData","errors"]

Comentários