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É a substância que se encontra como líquido à temperatura e pressão de saturação, ou seja, está na condição de temperatura e pressão correspondente ao processo de ebulição.

","solution_explanation","statement","

O que é líquido saturado?

","status","pending_classification","hasRelatedVideo","relatedVideos",[93],{"_94":95,"_113":114,"_52":129,"_148":149,"_166":130},"content",{"_44":96,"_58":97,"_98":-5,"_99":100,"_101":102,"_103":-5,"_46":104,"_107":108,"_109":108,"_110":-5,"_111":112},"162087be-594f-460e-bbdd-a339ac2f10ad","Calor Latente - Parte 1","description","content_type_id","1051eee7-c62e-4b2c-9900-77a29fcec080","resource_id","f2b62fc2-7079-40e7-a5b5-c4a9769b205d","user_id",{"_105":106},"external_id","3659","created_at","2025-08-20T12:27:41.608438+00:00","updated_at","content_group_id","slug","calor-latente-parte-1","prometheusData",{"_115":116,"_122":123,"_124":125,"_126":127,"_28":128},"provider",{"_44":117,"_118":119,"_120":121},"06f120be-2194-4548-8336-7ba44ffbae14","key","grupo_q_proteus","kind","proteus","reference","bf8aacba-3de9-4b10-961c-47ada80dfe8c","state","completed","thumbnail_url","https://proteus.grupoq.io/videos/bf8aacba-3de9-4b10-961c-47ada80dfe8c/thumbnailsthumb.0000000.jpg","https://proteus.grupoq.io/videos/bf8aacba-3de9-4b10-961c-47ada80dfe8c/levels.m3u8",[130],{"_44":131,"_58":132,"_60":133,"_134":135,"_136":137,"_107":138,"_109":138,"_46":139,"_111":133,"_146":147},"96193fa0-9495-45b2-81cc-b547604354af","Física Térmica - Termologia","fisica-termica-termologia","tag_group_id","c1ce2cf2-b217-4cc7-8182-81c56bd3522d","parent_id","c8ab2a95-fd84-4d6f-ade0-835d34ba00f9","2025-04-29T03:44:27.560682+00:00",{"_140":141,"_142":143,"_144":145},"childrenCount",10,"content_count",0,"question_count",8575,"children",[],"video",{"_44":102,"_13":97,"_98":-5,"_150":151,"_152":153,"_28":-5,"_154":-5,"_115":153,"_155":156,"_126":-5,"_157":-5,"_158":-5,"_159":-5,"_160":-5,"_46":161,"_162":143,"_163":-5,"_88":164,"_107":165,"_109":165},"duration",17,"source_type","prometheus","iframe_url","provider_video_id","748a4adb-ad8f-4c5f-88a9-bc522d3b4246","format","quality","file_path","file_size",{"_105":106},"views_count","last_played_at","draft","2025-08-19T11:56:22.11908+00:00","tag","similarQuestions",[169,203,221],{"_40":170,"_42":43,"_44":171,"_78":172,"_85":191,"_86":192,"_52":193},"112831da-be9c-458e-94cb-e8292d0dba12","3c0b9441-b878-4896-8bac-fa4ca61e3f13",[173,176,180,184,188],{"_44":174,"_81":82,"_83":175},"265bd71a-6749-41f5-b291-67efd646ca64","y'' + 2y' - 3y = 0",{"_44":177,"_81":178,"_83":179},"6d3c3a1d-8e80-4ff3-b97a-d5b5bca91940","B","6y'' - y' - y = 0",{"_44":181,"_81":182,"_83":183},"4168ac67-64fd-46ed-a69c-a01dbfcde7ea","C","y'' - 2y' + y = 0",{"_44":185,"_81":186,"_83":187},"cc7bc8df-6995-4264-ac5a-32ea9b4ed7db","D","9y'' + 6y' + y = 0",{"_44":170,"_81":189,"_83":190},"E","y'' - 2y' + 6y = 0","Somente em y''−2y'+6y=0 o polinômio característico r²−2r+6=0 tem Δ<0, gerando raízes complexas conjugadas (1±i√5) e, portanto, solução em termos de exponencial modulando seno e cosseno. Nos demais itens (a–d) o discriminante é ≥0, produzindo raízes reais (distintas ou repetidas).","

Resolva as seguintes EDOs determinando a solução geral e, quando houver condições iniciais do PVI, a solução particular.

(a) y'' + 2y' - 3y = 0

(b) 6y'' - y' - y = 0

(d) 9y'' + 6y' + y = 0

(e) y'' - 2y' + 6y = 0

(f) 4y'' + 9y = 0

(g) 6y'' - 5y' + y = 0; \\, y(0) = 4; \\, y'(0) = 0

(h) y'' + 4y' + 4y = 0; \\, y(-1) = 2; \\, y'(-1) = 1

(i) y'' + y = 0; \\, y\bigg(\\frac{\\pi}{3}\\bigg) = 2; \\, y'\\bigg(\\frac{\\pi}{3}\\bigg) = -4

(j) y'' - 2y' - 3y = 3e^{2t}

(k) y'' + 9y = t^2 e^{3t} + 6

(l) 2y'' + 3y' + y = t^2 + 3 \\sin(t)

(m) y'' + y' - 2y = 2t; \\, y(0) = 0; \\, y'(0) = 1

(n) y'' - 2y' + y = te^t + 4; \\, y(0) = 1; \\, y'(0) = 1

(o) y'' + 4y = 3 \\sin(2t); \\, y(0) = 2; \\, y'(0) = -1

",[194],{"_44":195,"_58":196,"_60":197,"_134":135,"_136":198,"_107":199,"_109":199,"_46":200,"_111":197},"6516bbbd-f2a3-4710-8382-702240b17836","Mecânica na Engenharia de Petróleo","mecanica-na-engenharia-de-petroleo","b787e438-0ab3-454c-ab43-5d3d14c2720d","2025-04-29T03:44:35.328997+00:00",{"_140":201,"_142":143,"_144":202},4,12302,{"_40":204,"_42":43,"_44":205,"_78":206,"_85":218,"_86":219,"_52":220},"6831a9b9-c9a4-4a76-bd7a-2ce98bfea875","93a32dd4-5fc6-4ccb-a76f-4724bf113742",[207,210,213,215],{"_44":208,"_81":82,"_83":209},"13e3f476-a0a5-421f-b47e-0969e8e9a7e0","

Verdadeiro, verdadeiro, falso

",{"_44":211,"_81":178,"_83":212},"c9a20855-d84b-4860-8b35-9784818282cf","

Falso, verdadeiro, verdadeiro

",{"_44":204,"_81":182,"_83":214},"

Verdadeiro, falso, verdadeiro

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Falso, falso, falso

","85,5 % decomposto → 14,5 % restante.\nN/N0 = 0,145 ⇒ t = ln(1/0,145)/(ln2/5730) ≈ 1,6×10⁴ anos.\nItens prováveis: (1) resta 14,5 % do C-14 (V); (2) idade ≈ 1,2×10⁴ anos ou 3 meias-vidas (F); (3) t½ do C-14 = 5730 anos (V). Sequência: V-F-V, correspondendo à alternativa c.","

Qual é a idade da madeira na qual 85,5\\% do C-14 se decompos?

",[194],{"_40":222,"_42":43,"_44":223,"_78":224,"_85":239,"_86":240,"_52":241},"3ce109b1-6cdb-4b4d-8816-a6af4d74bed0","c478a46c-46a8-4942-ae14-2e79def3dda2",[225,228,231,233,236],{"_44":226,"_81":82,"_83":227},"a5a16a42-3e58-4c76-80f2-c291aa2d8e49","Sim",{"_44":229,"_81":178,"_83":230},"5e6d0254-696c-4da0-b572-82e3a19f433e","Não",{"_44":222,"_81":182,"_83":232},"Indeterminado",{"_44":234,"_81":186,"_83":235},"35403f68-a880-429d-97f4-db507c58de38","Todos",{"_44":237,"_81":189,"_83":238},"2e06d948-d37e-4350-afc7-ced04941bcaf","Nenhum","Os polinômios e números fornecidos estão corrompidos (símbolos “????”), impossibilitando aplicar Ruffini e concluir se são raízes. Sem dados completos, o problema é indeterminado.","Emplea la regla de Ruffini para dictaminar si los siguientes números son o no raíces de los polinomios citados:
a) ????3 de ????4????5
b) ????2 de ????2????????2
c) ????1 de 2????????1
d) ????1 de 2????2????",[194],[194,243,250,260,267,274,275,283,289,294,300,307],{"_44":244,"_58":59,"_60":61,"_134":135,"_136":245,"_107":138,"_109":138,"_46":246,"_111":249},"6b6faf95-0e3a-4f58-abc8-e1444c48041d","92339f4f-ed20-4f4c-ad85-0c3de7e04ae0",{"_140":247,"_142":143,"_144":248},2,11846,"termodinamica-3",{"_44":251,"_58":252,"_60":253,"_134":135,"_136":254,"_107":255,"_109":255,"_46":256,"_111":259},"861ad829-750d-4a44-9569-2f18b430b4df","Engenharia Mecatrônica","engenharia-mecatronica","eb9315c5-bd04-4116-aa46-02c4fde320c0","2025-04-29T02:19:12.828432+00:00",{"_140":257,"_142":143,"_144":258},5,30614,"engenharia-mecatronica-1",{"_44":261,"_58":262,"_60":263,"_134":135,"_136":251,"_107":199,"_109":199,"_46":264,"_111":266},"88fe96b3-2a17-4198-90d5-ddda3d6f5d45","Mecânica","mecanica",{"_140":257,"_142":143,"_144":265},25741,"mecanica-3",{"_44":245,"_58":268,"_60":269,"_134":135,"_136":254,"_107":255,"_109":255,"_46":270,"_111":273},"Engenharia Mecânica","engenharia-mecanica",{"_140":271,"_142":143,"_144":272},11,36318,"engenharia-mecanica-2",{"_44":131,"_58":132,"_60":133,"_134":135,"_136":137,"_107":138,"_109":138,"_46":139,"_111":133},{"_44":276,"_58":277,"_60":278,"_134":135,"_136":-5,"_107":279,"_109":279,"_46":280,"_111":278},"9772e958-72c6-4499-ad47-877cf94d670d","Exatas","exatas","2025-04-29T01:56:45.284172+00:00",{"_140":281,"_142":143,"_144":282},18,135489,{"_44":284,"_58":59,"_60":61,"_134":135,"_136":195,"_107":285,"_109":285,"_46":286,"_111":288},"b21374de-aae5-4a4a-9bf3-0420e731797e","2025-04-29T04:00:14.680867+00:00",{"_140":143,"_142":143,"_144":287},8597,"termodinamica-5",{"_44":198,"_58":290,"_60":291,"_134":135,"_136":254,"_107":255,"_109":255,"_46":292,"_111":293},"Engenharia de Petróleo","engenharia-de-petroleo",{"_140":257,"_142":143,"_144":202},"engenharia-de-petroleo-1",{"_44":137,"_58":295,"_60":296,"_134":135,"_136":276,"_107":255,"_109":255,"_46":297,"_111":299},"Física","fisica",{"_140":271,"_142":143,"_144":298},13777,"fisica-4",{"_44":254,"_58":301,"_60":302,"_134":135,"_136":-5,"_107":303,"_109":303,"_46":304,"_111":302},"Engenharia","engenharia","2025-04-29T01:55:38.635246+00:00",{"_140":305,"_142":143,"_144":306},29,351586,{"_44":308,"_58":59,"_60":61,"_134":135,"_136":261,"_107":309,"_109":309,"_46":310,"_111":311},"f5967cbe-d751-4b40-81f2-04eb5dead2a9","2025-04-29T04:00:13.215003+00:00",{"_140":143,"_142":143,"_144":287},"termodinamica-4","tagsTree",[314,318],{"_44":276,"_58":277,"_60":278,"_134":135,"_136":-5,"_107":279,"_109":279,"_46":280,"_111":278,"_146":315},[316],{"_44":137,"_58":295,"_60":296,"_134":135,"_136":276,"_107":255,"_109":255,"_46":297,"_111":299,"_146":317},[130],{"_44":254,"_58":301,"_60":302,"_134":135,"_136":-5,"_107":303,"_109":303,"_46":304,"_111":302,"_146":319},[320,326,330],{"_44":251,"_58":252,"_60":253,"_134":135,"_136":254,"_107":255,"_109":255,"_46":256,"_111":259,"_146":321},[322],{"_44":261,"_58":262,"_60":263,"_134":135,"_136":251,"_107":199,"_109":199,"_46":264,"_111":266,"_146":323},[324],{"_44":308,"_58":59,"_60":61,"_134":135,"_136":261,"_107":309,"_109":309,"_46":310,"_111":311,"_146":325},[],{"_44":245,"_58":268,"_60":269,"_134":135,"_136":254,"_107":255,"_109":255,"_46":270,"_111":273,"_146":327},[328],{"_44":244,"_58":59,"_60":61,"_134":135,"_136":245,"_107":138,"_109":138,"_46":246,"_111":249,"_146":329},[],{"_44":198,"_58":290,"_60":291,"_134":135,"_136":254,"_107":255,"_109":255,"_46":292,"_111":293,"_146":331},[332],{"_44":195,"_58":196,"_60":197,"_134":135,"_136":198,"_107":199,"_109":199,"_46":200,"_111":197,"_146":333},[334],{"_44":284,"_58":59,"_60":61,"_134":135,"_136":195,"_107":285,"_109":285,"_46":286,"_111":288,"_146":335},[],"videoDislikes",{},"videoLikes",{},"actionData","errors"]

Comentários