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TERMODINÂMICA","alias","a-2-termodinamica",{"_43":60,"_55":61,"_57":62},1338505,"A2 - TERMODINÂMICA - N2","a-2-termodinamica-n-2","subjects",[65],{"_43":66,"_55":67,"_57":68},669639,"Termodinâmica","termodinamica","materialId","125959844","answerCount",1,"isIndexable","mainSubject",{"_43":66,"_55":67,"_57":68},"isIndexableSEO","materialFormat","Text","studentDegreeLevel","Graduate","source","PD","externalId","125961239","options",[87,93,97,101],{"_43":88,"_89":90,"_91":92},"0db5af4c-aff5-440f-9027-a78653911d70","label","A","text","Durante um processo isocórico, o calor é constante.",{"_43":94,"_89":95,"_91":96},"1e4bca3f-2bd5-4040-be10-987a7e407e8c","B","Durante um processo isocórico, o volume é constante.",{"_43":98,"_89":99,"_91":100},"1d7430ac-dea6-475d-a636-0ea925f08ee1","C","Durante um processo isocórico, a pressão é constante.",{"_43":102,"_89":103,"_91":104},"6b852a52-3f4a-4443-afde-3b83f8d088e5","D","Durante um processo isocórico, a temperatura é constante.","solution_explanation","statement","Com base no exposto, analise um processo isocórico com base na primeira lei da termodinâmica e assinale a alternativa correta.","status","pending_classification","hasRelatedVideo","relatedVideos",[113],{"_114":115,"_133":134,"_51":149,"_168":169,"_186":150},"content",{"_43":116,"_55":117,"_118":-5,"_119":120,"_121":122,"_123":-5,"_45":124,"_127":128,"_129":128,"_130":-5,"_131":132},"162087be-594f-460e-bbdd-a339ac2f10ad","Calor Latente - 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3y = 0",{"_43":197,"_89":95,"_91":198},"6d3c3a1d-8e80-4ff3-b97a-d5b5bca91940","6y'' - y' - y = 0",{"_43":200,"_89":99,"_91":201},"4168ac67-64fd-46ed-a69c-a01dbfcde7ea","y'' - 2y' + y = 0",{"_43":203,"_89":103,"_91":204},"cc7bc8df-6995-4264-ac5a-32ea9b4ed7db","9y'' + 6y' + y = 0",{"_43":190,"_89":206,"_91":207},"E","y'' - 2y' + 6y = 0","Somente em y''−2y'+6y=0 o polinômio característico r²−2r+6=0 tem Δ<0, gerando raízes complexas conjugadas (1±i√5) e, portanto, solução em termos de exponencial modulando seno e cosseno. Nos demais itens (a–d) o discriminante é ≥0, produzindo raízes reais (distintas ou repetidas).","

Resolva as seguintes EDOs determinando a solução geral e, quando houver condições iniciais do PVI, a solução particular.

(a) y'' + 2y' - 3y = 0

(b) 6y'' - y' - y = 0

(d) 9y'' + 6y' + y = 0

(e) y'' - 2y' + 6y = 0

(f) 4y'' + 9y = 0

(g) 6y'' - 5y' + y = 0; \\, y(0) = 4; \\, y'(0) = 0

(h) y'' + 4y' + 4y = 0; \\, y(-1) = 2; \\, y'(-1) = 1

(i) y'' + y = 0; \\, y\bigg(\\frac{\\pi}{3}\\bigg) = 2; \\, y'\\bigg(\\frac{\\pi}{3}\\bigg) = -4

(j) y'' - 2y' - 3y = 3e^{2t}

(k) y'' + 9y = t^2 e^{3t} + 6

(l) 2y'' + 3y' + y = t^2 + 3 \\sin(t)

(m) y'' + y' - 2y = 2t; \\, y(0) = 0; \\, y'(0) = 1

(n) y'' - 2y' + y = te^t + 4; \\, y(0) = 1; \\, y'(0) = 1

(o) y'' + 4y = 3 \\sin(2t); \\, y(0) = 2; \\, y'(0) = -1

",[211],{"_43":212,"_55":213,"_57":214,"_154":155,"_156":215,"_127":216,"_129":216,"_45":217,"_131":214},"6516bbbd-f2a3-4710-8382-702240b17836","Mecânica na Engenharia de Petróleo","mecanica-na-engenharia-de-petroleo","b787e438-0ab3-454c-ab43-5d3d14c2720d","2025-04-29T03:44:35.328997+00:00",{"_160":218,"_162":163,"_164":219},4,12302,{"_40":221,"_42":41,"_43":222,"_85":223,"_105":235,"_106":236,"_51":237},"6831a9b9-c9a4-4a76-bd7a-2ce98bfea875","93a32dd4-5fc6-4ccb-a76f-4724bf113742",[224,227,230,232],{"_43":225,"_89":90,"_91":226},"13e3f476-a0a5-421f-b47e-0969e8e9a7e0","

Verdadeiro, verdadeiro, falso

",{"_43":228,"_89":95,"_91":229},"c9a20855-d84b-4860-8b35-9784818282cf","

Falso, verdadeiro, verdadeiro

",{"_43":221,"_89":99,"_91":231},"

Verdadeiro, falso, verdadeiro

",{"_43":233,"_89":103,"_91":234},"3c98539b-1af9-4d44-aecd-c266754a2075","

Falso, falso, falso

","85,5 % decomposto → 14,5 % restante.\nN/N0 = 0,145 ⇒ t = ln(1/0,145)/(ln2/5730) ≈ 1,6×10⁴ anos.\nItens prováveis: (1) resta 14,5 % do C-14 (V); (2) idade ≈ 1,2×10⁴ anos ou 3 meias-vidas (F); (3) t½ do C-14 = 5730 anos (V). Sequência: V-F-V, correspondendo à alternativa c.","

Qual é a idade da madeira na qual 85,5\\% do C-14 se decompos?

",[211],{"_40":239,"_42":41,"_43":240,"_85":241,"_105":256,"_106":257,"_51":258},"3ce109b1-6cdb-4b4d-8816-a6af4d74bed0","c478a46c-46a8-4942-ae14-2e79def3dda2",[242,245,248,250,253],{"_43":243,"_89":90,"_91":244},"a5a16a42-3e58-4c76-80f2-c291aa2d8e49","Sim",{"_43":246,"_89":95,"_91":247},"5e6d0254-696c-4da0-b572-82e3a19f433e","Não",{"_43":239,"_89":99,"_91":249},"Indeterminado",{"_43":251,"_89":103,"_91":252},"35403f68-a880-429d-97f4-db507c58de38","Todos",{"_43":254,"_89":206,"_91":255},"2e06d948-d37e-4350-afc7-ced04941bcaf","Nenhum","Os polinômios e números fornecidos estão corrompidos (símbolos “????”), impossibilitando aplicar Ruffini e concluir se são raízes. Sem dados completos, o problema é indeterminado.","Emplea la regla de Ruffini para dictaminar si los siguientes números son o no raíces de los polinomios citados:
a) ????3 de ????4????5
b) ????2 de ????2????????2
c) ????1 de 2????????1
d) ????1 de 2????2????",[211],[211,260,267,277,284,291,292,300,306,311,317,324],{"_43":261,"_55":67,"_57":68,"_154":155,"_156":262,"_127":158,"_129":158,"_45":263,"_131":266},"6b6faf95-0e3a-4f58-abc8-e1444c48041d","92339f4f-ed20-4f4c-ad85-0c3de7e04ae0",{"_160":264,"_162":163,"_164":265},2,11846,"termodinamica-3",{"_43":268,"_55":269,"_57":270,"_154":155,"_156":271,"_127":272,"_129":272,"_45":273,"_131":276},"861ad829-750d-4a44-9569-2f18b430b4df","Engenharia Mecatrônica","engenharia-mecatronica","eb9315c5-bd04-4116-aa46-02c4fde320c0","2025-04-29T02:19:12.828432+00:00",{"_160":274,"_162":163,"_164":275},5,30614,"engenharia-mecatronica-1",{"_43":278,"_55":279,"_57":280,"_154":155,"_156":268,"_127":216,"_129":216,"_45":281,"_131":283},"88fe96b3-2a17-4198-90d5-ddda3d6f5d45","Mecânica","mecanica",{"_160":274,"_162":163,"_164":282},25741,"mecanica-3",{"_43":262,"_55":285,"_57":286,"_154":155,"_156":271,"_127":272,"_129":272,"_45":287,"_131":290},"Engenharia Mecânica","engenharia-mecanica",{"_160":288,"_162":163,"_164":289},11,36318,"engenharia-mecanica-2",{"_43":151,"_55":152,"_57":153,"_154":155,"_156":157,"_127":158,"_129":158,"_45":159,"_131":153},{"_43":293,"_55":294,"_57":295,"_154":155,"_156":-5,"_127":296,"_129":296,"_45":297,"_131":295},"9772e958-72c6-4499-ad47-877cf94d670d","Exatas","exatas","2025-04-29T01:56:45.284172+00:00",{"_160":298,"_162":163,"_164":299},18,135489,{"_43":301,"_55":67,"_57":68,"_154":155,"_156":212,"_127":302,"_129":302,"_45":303,"_131":305},"b21374de-aae5-4a4a-9bf3-0420e731797e","2025-04-29T04:00:14.680867+00:00",{"_160":163,"_162":163,"_164":304},8597,"termodinamica-5",{"_43":215,"_55":307,"_57":308,"_154":155,"_156":271,"_127":272,"_129":272,"_45":309,"_131":310},"Engenharia de Petróleo","engenharia-de-petroleo",{"_160":274,"_162":163,"_164":219},"engenharia-de-petroleo-1",{"_43":157,"_55":312,"_57":313,"_154":155,"_156":293,"_127":272,"_129":272,"_45":314,"_131":316},"Física","fisica",{"_160":288,"_162":163,"_164":315},13777,"fisica-4",{"_43":271,"_55":318,"_57":319,"_154":155,"_156":-5,"_127":320,"_129":320,"_45":321,"_131":319},"Engenharia","engenharia","2025-04-29T01:55:38.635246+00:00",{"_160":322,"_162":163,"_164":323},29,351586,{"_43":325,"_55":67,"_57":68,"_154":155,"_156":278,"_127":326,"_129":326,"_45":327,"_131":328},"f5967cbe-d751-4b40-81f2-04eb5dead2a9","2025-04-29T04:00:13.215003+00:00",{"_160":163,"_162":163,"_164":304},"termodinamica-4","tagsTree",[331,335],{"_43":293,"_55":294,"_57":295,"_154":155,"_156":-5,"_127":296,"_129":296,"_45":297,"_131":295,"_166":332},[333],{"_43":157,"_55":312,"_57":313,"_154":155,"_156":293,"_127":272,"_129":272,"_45":314,"_131":316,"_166":334},[150],{"_43":271,"_55":318,"_57":319,"_154":155,"_156":-5,"_127":320,"_129":320,"_45":321,"_131":319,"_166":336},[337,343,347],{"_43":268,"_55":269,"_57":270,"_154":155,"_156":271,"_127":272,"_129":272,"_45":273,"_131":276,"_166":338},[339],{"_43":278,"_55":279,"_57":280,"_154":155,"_156":268,"_127":216,"_129":216,"_45":281,"_131":283,"_166":340},[341],{"_43":325,"_55":67,"_57":68,"_154":155,"_156":278,"_127":326,"_129":326,"_45":327,"_131":328,"_166":342},[],{"_43":262,"_55":285,"_57":286,"_154":155,"_156":271,"_127":272,"_129":272,"_45":287,"_131":290,"_166":344},[345],{"_43":261,"_55":67,"_57":68,"_154":155,"_156":262,"_127":158,"_129":158,"_45":263,"_131":266,"_166":346},[],{"_43":215,"_55":307,"_57":308,"_154":155,"_156":271,"_127":272,"_129":272,"_45":309,"_131":310,"_166":348},[349],{"_43":212,"_55":213,"_57":214,"_154":155,"_156":215,"_127":216,"_129":216,"_45":217,"_131":214,"_166":350},[351],{"_43":301,"_55":67,"_57":68,"_154":155,"_156":212,"_127":302,"_129":302,"_45":303,"_131":305,"_166":352},[],"videoDislikes",{},"videoLikes",{},"actionData","errors"]

Comentários