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Perforation due to the presence of corrosion on the condenser surface.

",{"_44":94,"_89":95,"_91":96},"15587335-a173-4a6b-bd73-ea9fb797641e","B","

Obstruction of the fins due to the presence of foreign bodies.

",{"_44":98,"_89":99,"_91":100},"acf34f5e-6b20-4bff-9bb7-cd0855bf7d69","C","

Leaks in the input and output connectors.

",{"_44":102,"_89":103,"_91":104},"28ede724-0b8e-43bf-9651-73f6969d3ba4","D","

Lack of performance due to improper replacement of the specific condenser by an adaptable one.

",{"_44":41,"_89":106,"_91":107},"E","

A, B, and C are correct.

","solution_explanation","statement","

What are the typical failures of the condenser?

","status","pending_classification","hasRelatedVideo","relatedVideos",[116],{"_117":118,"_136":137,"_51":152,"_171":172,"_189":153},"content",{"_44":119,"_55":120,"_121":-5,"_122":123,"_124":125,"_126":-5,"_46":127,"_130":131,"_132":131,"_133":-5,"_134":135},"162087be-594f-460e-bbdd-a339ac2f10ad","Calor Latente - Parte 1","description","content_type_id","1051eee7-c62e-4b2c-9900-77a29fcec080","resource_id","f2b62fc2-7079-40e7-a5b5-c4a9769b205d","user_id",{"_128":129},"external_id","3659","created_at","2025-08-20T12:27:41.608438+00:00","updated_at","content_group_id","slug","calor-latente-parte-1","prometheusData",{"_138":139,"_145":146,"_147":148,"_149":150,"_28":151},"provider",{"_44":140,"_141":142,"_143":144},"06f120be-2194-4548-8336-7ba44ffbae14","key","grupo_q_proteus","kind","proteus","reference","bf8aacba-3de9-4b10-961c-47ada80dfe8c","state","completed","thumbnail_url","https://proteus.grupoq.io/videos/bf8aacba-3de9-4b10-961c-47ada80dfe8c/thumbnailsthumb.0000000.jpg","https://proteus.grupoq.io/videos/bf8aacba-3de9-4b10-961c-47ada80dfe8c/levels.m3u8",[153],{"_44":154,"_55":155,"_57":156,"_157":158,"_159":160,"_130":161,"_132":161,"_46":162,"_134":156,"_169":170},"96193fa0-9495-45b2-81cc-b547604354af","Física Térmica - Termologia","fisica-termica-termologia","tag_group_id","c1ce2cf2-b217-4cc7-8182-81c56bd3522d","parent_id","c8ab2a95-fd84-4d6f-ade0-835d34ba00f9","2025-04-29T03:44:27.560682+00:00",{"_163":164,"_165":166,"_167":168},"childrenCount",10,"content_count",0,"question_count",8575,"children",[],"video",{"_44":125,"_13":120,"_121":-5,"_173":174,"_175":176,"_28":-5,"_177":-5,"_138":176,"_178":179,"_149":-5,"_180":-5,"_181":-5,"_182":-5,"_183":-5,"_46":184,"_185":166,"_186":-5,"_111":187,"_130":188,"_132":188},"duration",17,"source_type","prometheus","iframe_url","provider_video_id","748a4adb-ad8f-4c5f-88a9-bc522d3b4246","format","quality","file_path","file_size",{"_128":129},"views_count","last_played_at","draft","2025-08-19T11:56:22.11908+00:00","tag","similarQuestions",[192,222,240],{"_40":193,"_42":43,"_44":194,"_85":195,"_108":210,"_109":211,"_51":212},"112831da-be9c-458e-94cb-e8292d0dba12","3c0b9441-b878-4896-8bac-fa4ca61e3f13",[196,199,202,205,208],{"_44":197,"_89":90,"_91":198},"265bd71a-6749-41f5-b291-67efd646ca64","y'' + 2y' - 3y = 0",{"_44":200,"_89":95,"_91":201},"6d3c3a1d-8e80-4ff3-b97a-d5b5bca91940","6y'' - y' - y = 0",{"_44":203,"_89":99,"_91":204},"4168ac67-64fd-46ed-a69c-a01dbfcde7ea","y'' - 2y' + y = 0",{"_44":206,"_89":103,"_91":207},"cc7bc8df-6995-4264-ac5a-32ea9b4ed7db","9y'' + 6y' + y = 0",{"_44":193,"_89":106,"_91":209},"y'' - 2y' + 6y = 0","Somente em y''−2y'+6y=0 o polinômio característico r²−2r+6=0 tem Δ<0, gerando raízes complexas conjugadas (1±i√5) e, portanto, solução em termos de exponencial modulando seno e cosseno. Nos demais itens (a–d) o discriminante é ≥0, produzindo raízes reais (distintas ou repetidas).","

Resolva as seguintes EDOs determinando a solução geral e, quando houver condições iniciais do PVI, a solução particular.

(a) y'' + 2y' - 3y = 0

(b) 6y'' - y' - y = 0

(d) 9y'' + 6y' + y = 0

(e) y'' - 2y' + 6y = 0

(f) 4y'' + 9y = 0

(g) 6y'' - 5y' + y = 0; \\, y(0) = 4; \\, y'(0) = 0

(h) y'' + 4y' + 4y = 0; \\, y(-1) = 2; \\, y'(-1) = 1

(i) y'' + y = 0; \\, y\bigg(\\frac{\\pi}{3}\\bigg) = 2; \\, y'\\bigg(\\frac{\\pi}{3}\\bigg) = -4

(j) y'' - 2y' - 3y = 3e^{2t}

(k) y'' + 9y = t^2 e^{3t} + 6

(l) 2y'' + 3y' + y = t^2 + 3 \\sin(t)

(m) y'' + y' - 2y = 2t; \\, y(0) = 0; \\, y'(0) = 1

(n) y'' - 2y' + y = te^t + 4; \\, y(0) = 1; \\, y'(0) = 1

(o) y'' + 4y = 3 \\sin(2t); \\, y(0) = 2; \\, y'(0) = -1

",[213],{"_44":214,"_55":215,"_57":216,"_157":158,"_159":217,"_130":218,"_132":218,"_46":219,"_134":216},"6516bbbd-f2a3-4710-8382-702240b17836","Mecânica na Engenharia de Petróleo","mecanica-na-engenharia-de-petroleo","b787e438-0ab3-454c-ab43-5d3d14c2720d","2025-04-29T03:44:35.328997+00:00",{"_163":220,"_165":166,"_167":221},4,12302,{"_40":223,"_42":43,"_44":224,"_85":225,"_108":237,"_109":238,"_51":239},"6831a9b9-c9a4-4a76-bd7a-2ce98bfea875","93a32dd4-5fc6-4ccb-a76f-4724bf113742",[226,229,232,234],{"_44":227,"_89":90,"_91":228},"13e3f476-a0a5-421f-b47e-0969e8e9a7e0","

Verdadeiro, verdadeiro, falso

",{"_44":230,"_89":95,"_91":231},"c9a20855-d84b-4860-8b35-9784818282cf","

Falso, verdadeiro, verdadeiro

",{"_44":223,"_89":99,"_91":233},"

Verdadeiro, falso, verdadeiro

",{"_44":235,"_89":103,"_91":236},"3c98539b-1af9-4d44-aecd-c266754a2075","

Falso, falso, falso

","85,5 % decomposto → 14,5 % restante.\nN/N0 = 0,145 ⇒ t = ln(1/0,145)/(ln2/5730) ≈ 1,6×10⁴ anos.\nItens prováveis: (1) resta 14,5 % do C-14 (V); (2) idade ≈ 1,2×10⁴ anos ou 3 meias-vidas (F); (3) t½ do C-14 = 5730 anos (V). Sequência: V-F-V, correspondendo à alternativa c.","

Qual é a idade da madeira na qual 85,5\\% do C-14 se decompos?

",[213],{"_40":241,"_42":43,"_44":242,"_85":243,"_108":258,"_109":259,"_51":260},"3ce109b1-6cdb-4b4d-8816-a6af4d74bed0","c478a46c-46a8-4942-ae14-2e79def3dda2",[244,247,250,252,255],{"_44":245,"_89":90,"_91":246},"a5a16a42-3e58-4c76-80f2-c291aa2d8e49","Sim",{"_44":248,"_89":95,"_91":249},"5e6d0254-696c-4da0-b572-82e3a19f433e","Não",{"_44":241,"_89":99,"_91":251},"Indeterminado",{"_44":253,"_89":103,"_91":254},"35403f68-a880-429d-97f4-db507c58de38","Todos",{"_44":256,"_89":106,"_91":257},"2e06d948-d37e-4350-afc7-ced04941bcaf","Nenhum","Os polinômios e números fornecidos estão corrompidos (símbolos “????”), impossibilitando aplicar Ruffini e concluir se são raízes. Sem dados completos, o problema é indeterminado.","Emplea la regla de Ruffini para dictaminar si los siguientes números son o no raíces de los polinomios citados:
a) ????3 de ????4????5
b) ????2 de ????2????????2
c) ????1 de 2????????1
d) ????1 de 2????2????",[213],[213,262,269,279,286,293,294,302,308,313,319,326],{"_44":263,"_55":67,"_57":68,"_157":158,"_159":264,"_130":161,"_132":161,"_46":265,"_134":268},"6b6faf95-0e3a-4f58-abc8-e1444c48041d","92339f4f-ed20-4f4c-ad85-0c3de7e04ae0",{"_163":266,"_165":166,"_167":267},2,11846,"termodinamica-3",{"_44":270,"_55":271,"_57":272,"_157":158,"_159":273,"_130":274,"_132":274,"_46":275,"_134":278},"861ad829-750d-4a44-9569-2f18b430b4df","Engenharia Mecatrônica","engenharia-mecatronica","eb9315c5-bd04-4116-aa46-02c4fde320c0","2025-04-29T02:19:12.828432+00:00",{"_163":276,"_165":166,"_167":277},5,30614,"engenharia-mecatronica-1",{"_44":280,"_55":281,"_57":282,"_157":158,"_159":270,"_130":218,"_132":218,"_46":283,"_134":285},"88fe96b3-2a17-4198-90d5-ddda3d6f5d45","Mecânica","mecanica",{"_163":276,"_165":166,"_167":284},25741,"mecanica-3",{"_44":264,"_55":287,"_57":288,"_157":158,"_159":273,"_130":274,"_132":274,"_46":289,"_134":292},"Engenharia Mecânica","engenharia-mecanica",{"_163":290,"_165":166,"_167":291},11,36318,"engenharia-mecanica-2",{"_44":154,"_55":155,"_57":156,"_157":158,"_159":160,"_130":161,"_132":161,"_46":162,"_134":156},{"_44":295,"_55":296,"_57":297,"_157":158,"_159":-5,"_130":298,"_132":298,"_46":299,"_134":297},"9772e958-72c6-4499-ad47-877cf94d670d","Exatas","exatas","2025-04-29T01:56:45.284172+00:00",{"_163":300,"_165":166,"_167":301},18,135489,{"_44":303,"_55":67,"_57":68,"_157":158,"_159":214,"_130":304,"_132":304,"_46":305,"_134":307},"b21374de-aae5-4a4a-9bf3-0420e731797e","2025-04-29T04:00:14.680867+00:00",{"_163":166,"_165":166,"_167":306},8597,"termodinamica-5",{"_44":217,"_55":309,"_57":310,"_157":158,"_159":273,"_130":274,"_132":274,"_46":311,"_134":312},"Engenharia de Petróleo","engenharia-de-petroleo",{"_163":276,"_165":166,"_167":221},"engenharia-de-petroleo-1",{"_44":160,"_55":314,"_57":315,"_157":158,"_159":295,"_130":274,"_132":274,"_46":316,"_134":318},"Física","fisica",{"_163":290,"_165":166,"_167":317},13777,"fisica-4",{"_44":273,"_55":320,"_57":321,"_157":158,"_159":-5,"_130":322,"_132":322,"_46":323,"_134":321},"Engenharia","engenharia","2025-04-29T01:55:38.635246+00:00",{"_163":324,"_165":166,"_167":325},29,351586,{"_44":327,"_55":67,"_57":68,"_157":158,"_159":280,"_130":328,"_132":328,"_46":329,"_134":330},"f5967cbe-d751-4b40-81f2-04eb5dead2a9","2025-04-29T04:00:13.215003+00:00",{"_163":166,"_165":166,"_167":306},"termodinamica-4","tagsTree",[333,337],{"_44":295,"_55":296,"_57":297,"_157":158,"_159":-5,"_130":298,"_132":298,"_46":299,"_134":297,"_169":334},[335],{"_44":160,"_55":314,"_57":315,"_157":158,"_159":295,"_130":274,"_132":274,"_46":316,"_134":318,"_169":336},[153],{"_44":273,"_55":320,"_57":321,"_157":158,"_159":-5,"_130":322,"_132":322,"_46":323,"_134":321,"_169":338},[339,345,349],{"_44":270,"_55":271,"_57":272,"_157":158,"_159":273,"_130":274,"_132":274,"_46":275,"_134":278,"_169":340},[341],{"_44":280,"_55":281,"_57":282,"_157":158,"_159":270,"_130":218,"_132":218,"_46":283,"_134":285,"_169":342},[343],{"_44":327,"_55":67,"_57":68,"_157":158,"_159":280,"_130":328,"_132":328,"_46":329,"_134":330,"_169":344},[],{"_44":264,"_55":287,"_57":288,"_157":158,"_159":273,"_130":274,"_132":274,"_46":289,"_134":292,"_169":346},[347],{"_44":263,"_55":67,"_57":68,"_157":158,"_159":264,"_130":161,"_132":161,"_46":265,"_134":268,"_169":348},[],{"_44":217,"_55":309,"_57":310,"_157":158,"_159":273,"_130":274,"_132":274,"_46":311,"_134":312,"_169":350},[351],{"_44":214,"_55":215,"_57":216,"_157":158,"_159":217,"_130":218,"_132":218,"_46":219,"_134":216,"_169":352},[353],{"_44":303,"_55":67,"_57":68,"_157":158,"_159":214,"_130":304,"_132":304,"_46":305,"_134":307,"_169":354},[],"videoDislikes",{},"videoLikes",{},"actionData","errors"]

Comentários