[{"_1":2,"_263":-5,"_264":-5},"loaderData",{"_3":4,"_8":9},"root",{"_5":6,"_7":-5},"url","https://prouniversitario.com/exercicios/c93f61ad-75dd-4106-b299-13b052536dad","user","pages/questions/show/index",{"_10":11,"_12":13,"_14":15,"_50":51,"_110":111,"_88":247,"_248":249,"_259":260,"_261":262},"comments",[],"isAiGenerated",false,"question",{"_16":17,"_18":17,"_19":20,"_21":22,"_45":17,"_46":47,"_48":49},"correctOptionId","","difficulty","id","c93f61ad-75dd-4106-b299-13b052536dad","options",[23,29,33,37,41],{"_19":24,"_25":26,"_27":28},"3fdb1fbc-2a65-4fd6-89c3-934b092544e8","label","A","text","

Apresentar o diagrama de momentos vetores

",{"_19":30,"_25":31,"_27":32},"5daafb62-68a0-47c6-ad4f-a32a93375c75","B","

Apresentar o diagrama de esforços cortantes

",{"_19":34,"_25":35,"_27":36},"67a26eea-8c48-4359-90eb-fadf53418144","C","

Inserir parâmetros do material de um elemento estrutural

",{"_19":38,"_25":39,"_27":40},"4a2c3ae6-dd4d-4cee-aa21-04996a5e0c24","D","

Inserir dimensões da seção transversal de um elemento estrutural

",{"_19":42,"_25":43,"_27":44},"aa59bacb-4595-47b1-a05c-a2faecbf19a1","E","

Inserir carregamento de carga concentrada e momento aplicado

","solution_explanation","statement","

De acordo com o software Ftool qual a função do ícone abaixo?

","status","pending_classification","relatedVideos",[52],{"_53":54,"_72":73,"_88":89,"_90":91},"content",{"_19":55,"_56":57,"_58":-5,"_59":60,"_61":62,"_63":-5,"_64":65,"_68":69,"_70":69,"_71":-5},"7efae94a-87df-415d-b113-35cde21868f7","name","Resolução CN nº 01-2006 - Parte 2","description","content_type_id","1051eee7-c62e-4b2c-9900-77a29fcec080","resource_id","d828a77d-5461-4d28-bb74-cccf85af393a","user_id","metadata",{"_66":67},"external_id","4372","created_at","2025-08-20T12:27:41.608438+00:00","updated_at","content_group_id","prometheusData",{"_74":75,"_81":82,"_83":84,"_85":86,"_5":87},"provider",{"_19":76,"_77":78,"_79":80},"d6d15d4b-87f1-4181-b20a-19190395ac14","key","grupo_q_cloudflare_stream","kind","cloudflare_stream","reference","9817a7c88778a464d2c96c30e3553e5d","state","completed","thumbnail_url","https://videodelivery.net/eyJraWQiOiIzNDIwNjA3YjJiNTVjMjc2ZTVhNmE1NzYzMGRkNDlhYyIsImFsZyI6IlJTMjU2In0.eyJzdWIiOiI5ODE3YTdjODg3NzhhNDY0ZDJjOTZjMzBlMzU1M2U1ZCIsImtpZCI6IjM0MjA2MDdiMmI1NWMyNzZlNWE2YTU3NjMwZGQ0OWFjIiwiZXhwIjoxNzU1Nzk2MDYwfQ.UtAJRzw1h8T3W5xfEb_39ktFkYdzkHIc7aouLotb5KDZ0njpjNcSUrDttA2a1Fbjxtygxayj-PQNFqUS7TVL1YEZTHYuMbTl7srwz87VMsN8-kvG_sQKJBCCnUtTT3BvOPuxmAqZKyKYoLoX_GwKfZP4LARS8j8f8imFTmzzd3vOmm4NsXGlrhwWe71lBjEeM8s5NnPkawAK7XFkrgWZLZwFeZdaAhwJUjR-608OQ8N94MKvCKp5pHOUSRf1dMWTQ_HilpVwa3o-lHSwOIWRpcrfXTlVGw9FtfEZELBzI1Jtm57zEYeCq01nXxUalLQjnkqeJmn3M4XKhZyAvUc75A/thumbnails/thumbnail.jpg?time=10s&height=360","https://customer-356s6wt60g79gz5u.cloudflarestream.com/eyJraWQiOiIzNDIwNjA3YjJiNTVjMjc2ZTVhNmE1NzYzMGRkNDlhYyIsImFsZyI6IlJTMjU2In0.eyJzdWIiOiI5ODE3YTdjODg3NzhhNDY0ZDJjOTZjMzBlMzU1M2U1ZCIsImtpZCI6IjM0MjA2MDdiMmI1NWMyNzZlNWE2YTU3NjMwZGQ0OWFjIiwiZXhwIjoxNzU1Nzk2MDYwfQ.UtAJRzw1h8T3W5xfEb_39ktFkYdzkHIc7aouLotb5KDZ0njpjNcSUrDttA2a1Fbjxtygxayj-PQNFqUS7TVL1YEZTHYuMbTl7srwz87VMsN8-kvG_sQKJBCCnUtTT3BvOPuxmAqZKyKYoLoX_GwKfZP4LARS8j8f8imFTmzzd3vOmm4NsXGlrhwWe71lBjEeM8s5NnPkawAK7XFkrgWZLZwFeZdaAhwJUjR-608OQ8N94MKvCKp5pHOUSRf1dMWTQ_HilpVwa3o-lHSwOIWRpcrfXTlVGw9FtfEZELBzI1Jtm57zEYeCq01nXxUalLQjnkqeJmn3M4XKhZyAvUc75A/manifest/video.m3u8","tags",[],"video",{"_19":62,"_92":57,"_58":-5,"_93":94,"_95":96,"_5":-5,"_97":-5,"_74":96,"_98":99,"_85":-5,"_100":-5,"_101":-5,"_102":-5,"_103":-5,"_64":104,"_105":106,"_107":-5,"_48":108,"_68":109,"_70":109},"title","duration",26,"source_type","prometheus","iframe_url","provider_video_id","6a087125-b0a0-4029-8b10-ba7086758d14","format","quality","file_path","file_size",{"_66":67},"views_count",0,"last_played_at","draft","2025-08-19T11:56:16.720338+00:00","similarQuestions",[112,173,190,207,227],{"_16":17,"_18":17,"_19":113,"_21":114,"_45":17,"_46":130,"_88":131},"3c0b9441-b878-4896-8bac-fa4ca61e3f13",[115,118,121,124,127],{"_19":116,"_25":26,"_27":117},"265bd71a-6749-41f5-b291-67efd646ca64","y'' + 2y' - 3y = 0",{"_19":119,"_25":31,"_27":120},"6d3c3a1d-8e80-4ff3-b97a-d5b5bca91940","6y'' - y' - y = 0",{"_19":122,"_25":35,"_27":123},"4168ac67-64fd-46ed-a69c-a01dbfcde7ea","y'' - 2y' + y = 0",{"_19":125,"_25":39,"_27":126},"cc7bc8df-6995-4264-ac5a-32ea9b4ed7db","9y'' + 6y' + y = 0",{"_19":128,"_25":43,"_27":129},"112831da-be9c-458e-94cb-e8292d0dba12","y'' - 2y' + 6y = 0","

Resolva as seguintes EDOs determinando a solução geral e, quando houver condições iniciais do PVI, a solução particular.

(a) y'' + 2y' - 3y = 0

(b) 6y'' - y' - y = 0

(d) 9y'' + 6y' + y = 0

(e) y'' - 2y' + 6y = 0

(f) 4y'' + 9y = 0

(g) 6y'' - 5y' + y = 0; \\, y(0) = 4; \\, y'(0) = 0

(h) y'' + 4y' + 4y = 0; \\, y(-1) = 2; \\, y'(-1) = 1

(i) y'' + y = 0; \\, y\bigg(\\frac{\\pi}{3}\\bigg) = 2; \\, y'\\bigg(\\frac{\\pi}{3}\\bigg) = -4

(j) y'' - 2y' - 3y = 3e^{2t}

(k) y'' + 9y = t^2 e^{3t} + 6

(l) 2y'' + 3y' + y = t^2 + 3 \\sin(t)

(m) y'' + y' - 2y = 2t; \\, y(0) = 0; \\, y'(0) = 1

(n) y'' - 2y' + y = te^t + 4; \\, y(0) = 1; \\, y'(0) = 1

(o) y'' + 4y = 3 \\sin(2t); \\, y(0) = 2; \\, y'(0) = -1

",[132,150,159,166],{"_19":133,"_56":134,"_135":136,"_137":138,"_139":140,"_68":141,"_70":141,"_64":142,"_148":149},"b6e37f32-f8e5-4025-bf0f-69ffc00fb331","Engenharia Civil","alias","engenharia-civil","tag_group_id","c1ce2cf2-b217-4cc7-8182-81c56bd3522d","parent_id","eb9315c5-bd04-4116-aa46-02c4fde320c0","2025-04-29T02:19:12.828432+00:00",{"_143":144,"_145":106,"_146":147},"childrenCount",21,"content_count","question_count",45865,"slug","engenharia-civil-3",{"_19":151,"_56":152,"_135":153,"_137":138,"_139":133,"_68":154,"_70":154,"_64":155,"_148":158},"c5bf57d4-c3d8-4365-b53e-085fa14a3a95","Estruturas","estruturas","2025-04-29T03:44:32.303369+00:00",{"_143":156,"_145":106,"_146":157},5,8852,"estruturas-1",{"_19":160,"_56":161,"_135":162,"_137":138,"_139":151,"_68":163,"_70":163,"_64":164,"_148":162},"e9d666f5-dcb8-4aa3-abc7-27cfb929e3b6","Análise Estrutural","analise-estrutural","2025-04-29T04:00:06.9766+00:00",{"_143":106,"_145":106,"_146":165},4694,{"_19":140,"_56":167,"_135":168,"_137":138,"_139":-5,"_68":169,"_70":169,"_64":170,"_148":168},"Engenharia","engenharia","2025-04-29T01:55:38.635246+00:00",{"_143":171,"_145":106,"_146":172},29,351586,{"_16":17,"_18":17,"_19":174,"_21":175,"_45":17,"_46":188,"_88":189},"4a3f20e5-655d-4a84-bbdf-aa3b0de4581a",[176,179,182,185],{"_19":177,"_25":26,"_27":178},"8dee6a5e-57a3-4743-8b5a-da9b8c54fb32","Verdadero, verdadero, verdadero, verdadero.",{"_19":180,"_25":31,"_27":181},"ca0a9b0d-3004-478e-9ca9-bafa5243aca9","Verdadero, verdadero, falso, verdadero.",{"_19":183,"_25":35,"_27":184},"68712800-8b4b-46af-9cdf-3f83e4032c30","Verdadero, falso, verdadero, falso.",{"_19":186,"_25":39,"_27":187},"1f5e395b-c362-4503-8261-dcfcae96b1ce","Falso, verdadero, verdadeiro, verdadeiro.","

Divide el polinomio p(x) = 3x^4 + 4x^3 + x^2 entre el polinomio q(x) = 2+x. Como el polinomio divisor, q(x), es de grado 2, debemos encontrar dos polinomios, un polinomio cociente (c(x)) y un polinomio resto (r(x)) de grado 1 o 0, tales que p(x) = q(x) * c(x) + r(x).

El polinomio p(x) es de grado 4.

El polinomio q(x) es de grado 1.

El polinomio cociente c(x) es de grado 2.

El polinomio resto r(x) es de grado 1 o 0.

",[132,150,159,166],{"_16":17,"_18":17,"_19":191,"_21":192,"_45":17,"_46":205,"_88":206},"93a32dd4-5fc6-4ccb-a76f-4724bf113742",[193,196,199,202],{"_19":194,"_25":26,"_27":195},"13e3f476-a0a5-421f-b47e-0969e8e9a7e0","

Verdadeiro, verdadeiro, falso

",{"_19":197,"_25":31,"_27":198},"c9a20855-d84b-4860-8b35-9784818282cf","

Falso, verdadeiro, verdadeiro

",{"_19":200,"_25":35,"_27":201},"6831a9b9-c9a4-4a76-bd7a-2ce98bfea875","

Verdadeiro, falso, verdadeiro

",{"_19":203,"_25":39,"_27":204},"3c98539b-1af9-4d44-aecd-c266754a2075","

Falso, falso, falso

","

Qual é a idade da madeira na qual 85,5\\% do C-14 se decompos?

",[132,150,159,166],{"_16":17,"_18":17,"_19":208,"_21":209,"_45":17,"_46":225,"_88":226},"996628fc-4ac3-4821-86bd-839f86a97a6d",[210,213,216,219,222],{"_19":211,"_25":26,"_27":212},"5ad09994-6dcb-4c66-87ae-ec00e9b439b7","5 + 3x < 2x + 4",{"_19":214,"_25":31,"_27":215},"b3ae9948-890b-4807-b801-1e1888cb0c10","3 + 4x \\leq 8x + 6",{"_19":217,"_25":35,"_27":218},"d2964603-f26c-4be6-99ae-d174678f104c","5 + 4x > 3x + 2",{"_19":220,"_25":39,"_27":221},"88c48b1a-ce37-4eae-a900-a4fb4bd581d9","1 + 3x \\geq 5x + 7",{"_19":223,"_25":43,"_27":224},"155e0bb0-6c7f-4d9c-96e5-d1cdb97c632b","4(3 + 2x) < -(6x + 8)","Resolver las siguientes inecuaciones y representar la solución en la recta real:",[132,150,159,166],{"_16":17,"_18":17,"_19":228,"_21":229,"_45":17,"_46":245,"_88":246},"c478a46c-46a8-4942-ae14-2e79def3dda2",[230,233,236,239,242],{"_19":231,"_25":26,"_27":232},"a5a16a42-3e58-4c76-80f2-c291aa2d8e49","Sim",{"_19":234,"_25":31,"_27":235},"5e6d0254-696c-4da0-b572-82e3a19f433e","Não",{"_19":237,"_25":35,"_27":238},"3ce109b1-6cdb-4b4d-8816-a6af4d74bed0","Indeterminado",{"_19":240,"_25":39,"_27":241},"35403f68-a880-429d-97f4-db507c58de38","Todos",{"_19":243,"_25":43,"_27":244},"2e06d948-d37e-4350-afc7-ced04941bcaf","Nenhum","Emplea la regla de Ruffini para dictaminar si los siguientes números son o no raíces de los polinomios citados:
a) ????3 de ????4????5
b) ????2 de ????2????????2
c) ????1 de 2????????1
d) ????1 de 2????2????",[132,150,159,166],[132,150,159,166],"tagsTree",[250],{"_19":140,"_56":167,"_135":168,"_137":138,"_139":-5,"_68":169,"_70":169,"_64":170,"_148":168,"_251":252},"children",[253],{"_19":133,"_56":134,"_135":136,"_137":138,"_139":140,"_68":141,"_70":141,"_64":142,"_148":149,"_251":254},[255],{"_19":151,"_56":152,"_135":153,"_137":138,"_139":133,"_68":154,"_70":154,"_64":155,"_148":158,"_251":256},[257],{"_19":160,"_56":161,"_135":162,"_137":138,"_139":151,"_68":163,"_70":163,"_64":164,"_148":162,"_251":258},[],"videoDislikes",{},"videoLikes",{},"actionData","errors"]

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