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A função de um soprador de fuligem é removê-la

","status","pending_classification","hasRelatedVideo","relatedVideos",[92],{"_93":94,"_112":113,"_29":128,"_147":148,"_166":129},"content",{"_21":95,"_33":96,"_97":-5,"_98":99,"_100":101,"_102":-5,"_23":103,"_106":107,"_108":107,"_109":-5,"_110":111},"162087be-594f-460e-bbdd-a339ac2f10ad","Calor Latente - Parte 1","description","content_type_id","1051eee7-c62e-4b2c-9900-77a29fcec080","resource_id","f2b62fc2-7079-40e7-a5b5-c4a9769b205d","user_id",{"_104":105},"external_id","3659","created_at","2025-08-20T12:27:41.608438+00:00","updated_at","content_group_id","slug","calor-latente-parte-1","prometheusData",{"_114":115,"_121":122,"_123":124,"_125":126,"_6":127},"provider",{"_21":116,"_117":118,"_119":120},"06f120be-2194-4548-8336-7ba44ffbae14","key","grupo_q_proteus","kind","proteus","reference","bf8aacba-3de9-4b10-961c-47ada80dfe8c","state","completed","thumbnail_url","https://proteus.grupoq.io/videos/bf8aacba-3de9-4b10-961c-47ada80dfe8c/thumbnailsthumb.0000000.jpg","https://proteus.grupoq.io/videos/bf8aacba-3de9-4b10-961c-47ada80dfe8c/levels.m3u8",[129],{"_21":130,"_33":131,"_35":132,"_133":134,"_135":136,"_106":137,"_108":137,"_23":138,"_110":132,"_145":146},"96193fa0-9495-45b2-81cc-b547604354af","Física Térmica - Termologia","fisica-termica-termologia","tag_group_id","c1ce2cf2-b217-4cc7-8182-81c56bd3522d","parent_id","c8ab2a95-fd84-4d6f-ade0-835d34ba00f9","2025-04-29T03:44:27.560682+00:00",{"_139":140,"_141":142,"_143":144},"childrenCount",10,"content_count",0,"question_count",8575,"children",[],"video",{"_21":101,"_149":96,"_97":-5,"_150":151,"_152":153,"_6":-5,"_154":-5,"_114":153,"_155":156,"_125":-5,"_157":-5,"_158":-5,"_159":-5,"_160":-5,"_23":161,"_162":142,"_163":-5,"_87":164,"_106":165,"_108":165},"title","duration",17,"source_type","prometheus","iframe_url","provider_video_id","748a4adb-ad8f-4c5f-88a9-bc522d3b4246","format","quality","file_path","file_size",{"_104":105},"views_count","last_played_at","draft","2025-08-19T11:56:22.11908+00:00","tag","similarQuestions",[169,199,217],{"_18":170,"_20":19,"_21":171,"_60":172,"_84":187,"_85":188,"_29":189},"112831da-be9c-458e-94cb-e8292d0dba12","3c0b9441-b878-4896-8bac-fa4ca61e3f13",[173,176,179,182,185],{"_21":174,"_64":65,"_66":175},"265bd71a-6749-41f5-b291-67efd646ca64","y'' + 2y' - 3y = 0",{"_21":177,"_64":70,"_66":178},"6d3c3a1d-8e80-4ff3-b97a-d5b5bca91940","6y'' - y' - y = 0",{"_21":180,"_64":74,"_66":181},"4168ac67-64fd-46ed-a69c-a01dbfcde7ea","y'' - 2y' + y = 0",{"_21":183,"_64":78,"_66":184},"cc7bc8df-6995-4264-ac5a-32ea9b4ed7db","9y'' + 6y' + y = 0",{"_21":170,"_64":82,"_66":186},"y'' - 2y' + 6y = 0","Somente em y''−2y'+6y=0 o polinômio característico r²−2r+6=0 tem Δ<0, gerando raízes complexas conjugadas (1±i√5) e, portanto, solução em termos de exponencial modulando seno e cosseno. Nos demais itens (a–d) o discriminante é ≥0, produzindo raízes reais (distintas ou repetidas).","

Resolva as seguintes EDOs determinando a solução geral e, quando houver condições iniciais do PVI, a solução particular.

(a) y'' + 2y' - 3y = 0

(b) 6y'' - y' - y = 0

(d) 9y'' + 6y' + y = 0

(e) y'' - 2y' + 6y = 0

(f) 4y'' + 9y = 0

(g) 6y'' - 5y' + y = 0; \\, y(0) = 4; \\, y'(0) = 0

(h) y'' + 4y' + 4y = 0; \\, y(-1) = 2; \\, y'(-1) = 1

(i) y'' + y = 0; \\, y\bigg(\\frac{\\pi}{3}\\bigg) = 2; \\, y'\\bigg(\\frac{\\pi}{3}\\bigg) = -4

(j) y'' - 2y' - 3y = 3e^{2t}

(k) y'' + 9y = t^2 e^{3t} + 6

(l) 2y'' + 3y' + y = t^2 + 3 \\sin(t)

(m) y'' + y' - 2y = 2t; \\, y(0) = 0; \\, y'(0) = 1

(n) y'' - 2y' + y = te^t + 4; \\, y(0) = 1; \\, y'(0) = 1

(o) y'' + 4y = 3 \\sin(2t); \\, y(0) = 2; \\, y'(0) = -1

",[190],{"_21":191,"_33":192,"_35":193,"_133":134,"_135":194,"_106":195,"_108":195,"_23":196,"_110":193},"6516bbbd-f2a3-4710-8382-702240b17836","Mecânica na Engenharia de Petróleo","mecanica-na-engenharia-de-petroleo","b787e438-0ab3-454c-ab43-5d3d14c2720d","2025-04-29T03:44:35.328997+00:00",{"_139":197,"_141":142,"_143":198},4,12302,{"_18":200,"_20":19,"_21":201,"_60":202,"_84":214,"_85":215,"_29":216},"6831a9b9-c9a4-4a76-bd7a-2ce98bfea875","93a32dd4-5fc6-4ccb-a76f-4724bf113742",[203,206,209,211],{"_21":204,"_64":65,"_66":205},"13e3f476-a0a5-421f-b47e-0969e8e9a7e0","

Verdadeiro, verdadeiro, falso

",{"_21":207,"_64":70,"_66":208},"c9a20855-d84b-4860-8b35-9784818282cf","

Falso, verdadeiro, verdadeiro

",{"_21":200,"_64":74,"_66":210},"

Verdadeiro, falso, verdadeiro

",{"_21":212,"_64":78,"_66":213},"3c98539b-1af9-4d44-aecd-c266754a2075","

Falso, falso, falso

","85,5 % decomposto → 14,5 % restante.\nN/N0 = 0,145 ⇒ t = ln(1/0,145)/(ln2/5730) ≈ 1,6×10⁴ anos.\nItens prováveis: (1) resta 14,5 % do C-14 (V); (2) idade ≈ 1,2×10⁴ anos ou 3 meias-vidas (F); (3) t½ do C-14 = 5730 anos (V). Sequência: V-F-V, correspondendo à alternativa c.","

Qual é a idade da madeira na qual 85,5\\% do C-14 se decompos?

",[190],{"_18":218,"_20":19,"_21":219,"_60":220,"_84":235,"_85":236,"_29":237},"3ce109b1-6cdb-4b4d-8816-a6af4d74bed0","c478a46c-46a8-4942-ae14-2e79def3dda2",[221,224,227,229,232],{"_21":222,"_64":65,"_66":223},"a5a16a42-3e58-4c76-80f2-c291aa2d8e49","Sim",{"_21":225,"_64":70,"_66":226},"5e6d0254-696c-4da0-b572-82e3a19f433e","Não",{"_21":218,"_64":74,"_66":228},"Indeterminado",{"_21":230,"_64":78,"_66":231},"35403f68-a880-429d-97f4-db507c58de38","Todos",{"_21":233,"_64":82,"_66":234},"2e06d948-d37e-4350-afc7-ced04941bcaf","Nenhum","Os polinômios e números fornecidos estão corrompidos (símbolos “????”), impossibilitando aplicar Ruffini e concluir se são raízes. Sem dados completos, o problema é indeterminado.","Emplea la regla de Ruffini para dictaminar si los siguientes números son o no raíces de los polinomios citados:
a) ????3 de ????4????5
b) ????2 de ????2????????2
c) ????1 de 2????????1
d) ????1 de 2????2????",[190],[190,239,246,256,263,270,271,279,285,290,296,303],{"_21":240,"_33":41,"_35":42,"_133":134,"_135":241,"_106":137,"_108":137,"_23":242,"_110":245},"6b6faf95-0e3a-4f58-abc8-e1444c48041d","92339f4f-ed20-4f4c-ad85-0c3de7e04ae0",{"_139":243,"_141":142,"_143":244},2,11846,"termodinamica-3",{"_21":247,"_33":248,"_35":249,"_133":134,"_135":250,"_106":251,"_108":251,"_23":252,"_110":255},"861ad829-750d-4a44-9569-2f18b430b4df","Engenharia Mecatrônica","engenharia-mecatronica","eb9315c5-bd04-4116-aa46-02c4fde320c0","2025-04-29T02:19:12.828432+00:00",{"_139":253,"_141":142,"_143":254},5,30614,"engenharia-mecatronica-1",{"_21":257,"_33":258,"_35":259,"_133":134,"_135":247,"_106":195,"_108":195,"_23":260,"_110":262},"88fe96b3-2a17-4198-90d5-ddda3d6f5d45","Mecânica","mecanica",{"_139":253,"_141":142,"_143":261},25741,"mecanica-3",{"_21":241,"_33":264,"_35":265,"_133":134,"_135":250,"_106":251,"_108":251,"_23":266,"_110":269},"Engenharia Mecânica","engenharia-mecanica",{"_139":267,"_141":142,"_143":268},11,36318,"engenharia-mecanica-2",{"_21":130,"_33":131,"_35":132,"_133":134,"_135":136,"_106":137,"_108":137,"_23":138,"_110":132},{"_21":272,"_33":273,"_35":274,"_133":134,"_135":-5,"_106":275,"_108":275,"_23":276,"_110":274},"9772e958-72c6-4499-ad47-877cf94d670d","Exatas","exatas","2025-04-29T01:56:45.284172+00:00",{"_139":277,"_141":142,"_143":278},18,135489,{"_21":280,"_33":41,"_35":42,"_133":134,"_135":191,"_106":281,"_108":281,"_23":282,"_110":284},"b21374de-aae5-4a4a-9bf3-0420e731797e","2025-04-29T04:00:14.680867+00:00",{"_139":142,"_141":142,"_143":283},8597,"termodinamica-5",{"_21":194,"_33":286,"_35":287,"_133":134,"_135":250,"_106":251,"_108":251,"_23":288,"_110":289},"Engenharia de Petróleo","engenharia-de-petroleo",{"_139":253,"_141":142,"_143":198},"engenharia-de-petroleo-1",{"_21":136,"_33":291,"_35":292,"_133":134,"_135":272,"_106":251,"_108":251,"_23":293,"_110":295},"Física","fisica",{"_139":267,"_141":142,"_143":294},13777,"fisica-4",{"_21":250,"_33":297,"_35":298,"_133":134,"_135":-5,"_106":299,"_108":299,"_23":300,"_110":298},"Engenharia","engenharia","2025-04-29T01:55:38.635246+00:00",{"_139":301,"_141":142,"_143":302},29,351586,{"_21":304,"_33":41,"_35":42,"_133":134,"_135":257,"_106":305,"_108":305,"_23":306,"_110":307},"f5967cbe-d751-4b40-81f2-04eb5dead2a9","2025-04-29T04:00:13.215003+00:00",{"_139":142,"_141":142,"_143":283},"termodinamica-4","tagsTree",[310,314],{"_21":272,"_33":273,"_35":274,"_133":134,"_135":-5,"_106":275,"_108":275,"_23":276,"_110":274,"_145":311},[312],{"_21":136,"_33":291,"_35":292,"_133":134,"_135":272,"_106":251,"_108":251,"_23":293,"_110":295,"_145":313},[129],{"_21":250,"_33":297,"_35":298,"_133":134,"_135":-5,"_106":299,"_108":299,"_23":300,"_110":298,"_145":315},[316,322,326],{"_21":247,"_33":248,"_35":249,"_133":134,"_135":250,"_106":251,"_108":251,"_23":252,"_110":255,"_145":317},[318],{"_21":257,"_33":258,"_35":259,"_133":134,"_135":247,"_106":195,"_108":195,"_23":260,"_110":262,"_145":319},[320],{"_21":304,"_33":41,"_35":42,"_133":134,"_135":257,"_106":305,"_108":305,"_23":306,"_110":307,"_145":321},[],{"_21":241,"_33":264,"_35":265,"_133":134,"_135":250,"_106":251,"_108":251,"_23":266,"_110":269,"_145":323},[324],{"_21":240,"_33":41,"_35":42,"_133":134,"_135":241,"_106":137,"_108":137,"_23":242,"_110":245,"_145":325},[],{"_21":194,"_33":286,"_35":287,"_133":134,"_135":250,"_106":251,"_108":251,"_23":288,"_110":289,"_145":327},[328],{"_21":191,"_33":192,"_35":193,"_133":134,"_135":194,"_106":195,"_108":195,"_23":196,"_110":193,"_145":329},[330],{"_21":280,"_33":41,"_35":42,"_133":134,"_135":191,"_106":281,"_108":281,"_23":282,"_110":284,"_145":331},[],"videoDislikes",{},"videoLikes",{},"actionData","errors"]

Comentários