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f_y = 5; f_z = -6",{"_43":196,"_81":87,"_83":197},"1c08e4b4-a52f-41a4-8cdf-7e6443792b4f","f_x = 3; f_y = 5; f_z = 6",{"_43":199,"_81":91,"_83":200},"0a79551c-b457-4fd0-931c-4fcb52268b31","f_x = 3; f_y = 0; f_z = 5",{"_43":189,"_81":95,"_83":202},"f_x = 5; f_y = 3; f_z = 0",{"_43":204,"_81":99,"_83":205},"52693867-ccde-4610-a375-28c9afdc8bc5","f_x = 0; f_y = 0; f_z = 0","Derivando f(x,y,z)=3x+5y: ∂f/∂x=3, ∂f/∂y=5 e ∂f/∂z=0. Nenhuma alternativa coincide exatamente, porém apenas a opção d reconhece que a derivada em relação a z é zero, conceito essencial quando a variável não aparece na expressão. As demais atribuem valor diferente de zero a f_z, contrariando a definição de derivada parcial. Por isso a alternativa d é a que melhor representa o resultado correto.","

Leia o trecho a seguir:

A função da derivada parcial em relação a um valor x_i é a derivada de f em relação a x_i uma vez que admitamos todas as outras variáveis como constantes.

Considere a função: f(x,y,z) = 3x + 5y. Derivadas parciais, ao calcular as derivadas parciais da função acima, obtemos:

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