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Resolva as seguintes EDOs determinando a solução geral e, quando houver condições iniciais do PVI, a solução particular.

(a) y'' + 2y' - 3y = 0

(b) 6y'' - y' - y = 0

(d) 9y'' + 6y' + y = 0

(e) y'' - 2y' + 6y = 0

(f) 4y'' + 9y = 0

(g) 6y'' - 5y' + y = 0; \\, y(0) = 4; \\, y'(0) = 0

(h) y'' + 4y' + 4y = 0; \\, y(-1) = 2; \\, y'(-1) = 1

(i) y'' + y = 0; \\, y\bigg(\\frac{\\pi}{3}\\bigg) = 2; \\, y'\\bigg(\\frac{\\pi}{3}\\bigg) = -4

(j) y'' - 2y' - 3y = 3e^{2t}

(k) y'' + 9y = t^2 e^{3t} + 6

(l) 2y'' + 3y' + y = t^2 + 3 \\sin(t)

(m) y'' + y' - 2y = 2t; \\, y(0) = 0; \\, y'(0) = 1

(n) y'' - 2y' + y = te^t + 4; \\, y(0) = 1; \\, y'(0) = 1

(o) y'' + 4y = 3 \\sin(2t); \\, y(0) = 2; \\, y'(0) = -1

",[186],{"_21":187,"_35":188,"_37":189,"_129":130,"_131":190,"_102":191,"_104":191,"_23":192,"_106":189},"6516bbbd-f2a3-4710-8382-702240b17836","Mecânica na Engenharia de Petróleo","mecanica-na-engenharia-de-petroleo","b787e438-0ab3-454c-ab43-5d3d14c2720d","2025-04-29T03:44:35.328997+00:00",{"_135":193,"_137":138,"_139":194},4,12302,{"_18":196,"_20":19,"_21":197,"_56":198,"_80":210,"_81":211,"_29":212},"6831a9b9-c9a4-4a76-bd7a-2ce98bfea875","93a32dd4-5fc6-4ccb-a76f-4724bf113742",[199,202,205,207],{"_21":200,"_60":61,"_62":201},"13e3f476-a0a5-421f-b47e-0969e8e9a7e0","

Verdadeiro, verdadeiro, falso

",{"_21":203,"_60":66,"_62":204},"c9a20855-d84b-4860-8b35-9784818282cf","

Falso, verdadeiro, verdadeiro

",{"_21":196,"_60":70,"_62":206},"

Verdadeiro, falso, verdadeiro

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Falso, falso, falso

","85,5 % decomposto → 14,5 % restante.\nN/N0 = 0,145 ⇒ t = ln(1/0,145)/(ln2/5730) ≈ 1,6×10⁴ anos.\nItens prováveis: (1) resta 14,5 % do C-14 (V); (2) idade ≈ 1,2×10⁴ anos ou 3 meias-vidas (F); (3) t½ do C-14 = 5730 anos (V). Sequência: V-F-V, correspondendo à alternativa c.","

Qual é a idade da madeira na qual 85,5\\% do C-14 se decompos?

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a) ????3 de ????4????5
b) ????2 de ????2????????2
c) ????1 de 2????????1
d) ????1 de 2????2????",[186],[186,235,242,252,259,266,267,275,281,286,292,299],{"_21":236,"_35":36,"_37":38,"_129":130,"_131":237,"_102":133,"_104":133,"_23":238,"_106":241},"6b6faf95-0e3a-4f58-abc8-e1444c48041d","92339f4f-ed20-4f4c-ad85-0c3de7e04ae0",{"_135":239,"_137":138,"_139":240},2,11846,"termodinamica-3",{"_21":243,"_35":244,"_37":245,"_129":130,"_131":246,"_102":247,"_104":247,"_23":248,"_106":251},"861ad829-750d-4a44-9569-2f18b430b4df","Engenharia Mecatrônica","engenharia-mecatronica","eb9315c5-bd04-4116-aa46-02c4fde320c0","2025-04-29T02:19:12.828432+00:00",{"_135":249,"_137":138,"_139":250},5,30614,"engenharia-mecatronica-1",{"_21":253,"_35":254,"_37":255,"_129":130,"_131":243,"_102":191,"_104":191,"_23":256,"_106":258},"88fe96b3-2a17-4198-90d5-ddda3d6f5d45","Mecânica","mecanica",{"_135":249,"_137":138,"_139":257},25741,"mecanica-3",{"_21":237,"_35":260,"_37":261,"_129":130,"_131":246,"_102":247,"_104":247,"_23":262,"_106":265},"Engenharia Mecânica","engenharia-mecanica",{"_135":263,"_137":138,"_139":264},11,36318,"engenharia-mecanica-2",{"_21":126,"_35":127,"_37":128,"_129":130,"_131":132,"_102":133,"_104":133,"_23":134,"_106":128},{"_21":268,"_35":269,"_37":270,"_129":130,"_131":-5,"_102":271,"_104":271,"_23":272,"_106":270},"9772e958-72c6-4499-ad47-877cf94d670d","Exatas","exatas","2025-04-29T01:56:45.284172+00:00",{"_135":273,"_137":138,"_139":274},18,135489,{"_21":276,"_35":36,"_37":38,"_129":130,"_131":187,"_102":277,"_104":277,"_23":278,"_106":280},"b21374de-aae5-4a4a-9bf3-0420e731797e","2025-04-29T04:00:14.680867+00:00",{"_135":138,"_137":138,"_139":279},8597,"termodinamica-5",{"_21":190,"_35":282,"_37":283,"_129":130,"_131":246,"_102":247,"_104":247,"_23":284,"_106":285},"Engenharia de Petróleo","engenharia-de-petroleo",{"_135":249,"_137":138,"_139":194},"engenharia-de-petroleo-1",{"_21":132,"_35":287,"_37":288,"_129":130,"_131":268,"_102":247,"_104":247,"_23":289,"_106":291},"Física","fisica",{"_135":263,"_137":138,"_139":290},13777,"fisica-4",{"_21":246,"_35":293,"_37":294,"_129":130,"_131":-5,"_102":295,"_104":295,"_23":296,"_106":294},"Engenharia","engenharia","2025-04-29T01:55:38.635246+00:00",{"_135":297,"_137":138,"_139":298},29,351586,{"_21":300,"_35":36,"_37":38,"_129":130,"_131":253,"_102":301,"_104":301,"_23":302,"_106":303},"f5967cbe-d751-4b40-81f2-04eb5dead2a9","2025-04-29T04:00:13.215003+00:00",{"_135":138,"_137":138,"_139":279},"termodinamica-4","tagsTree",[306,310],{"_21":268,"_35":269,"_37":270,"_129":130,"_131":-5,"_102":271,"_104":271,"_23":272,"_106":270,"_141":307},[308],{"_21":132,"_35":287,"_37":288,"_129":130,"_131":268,"_102":247,"_104":247,"_23":289,"_106":291,"_141":309},[125],{"_21":246,"_35":293,"_37":294,"_129":130,"_131":-5,"_102":295,"_104":295,"_23":296,"_106":294,"_141":311},[312,318,322],{"_21":243,"_35":244,"_37":245,"_129":130,"_131":246,"_102":247,"_104":247,"_23":248,"_106":251,"_141":313},[314],{"_21":253,"_35":254,"_37":255,"_129":130,"_131":243,"_102":191,"_104":191,"_23":256,"_106":258,"_141":315},[316],{"_21":300,"_35":36,"_37":38,"_129":130,"_131":253,"_102":301,"_104":301,"_23":302,"_106":303,"_141":317},[],{"_21":237,"_35":260,"_37":261,"_129":130,"_131":246,"_102":247,"_104":247,"_23":262,"_106":265,"_141":319},[320],{"_21":236,"_35":36,"_37":38,"_129":130,"_131":237,"_102":133,"_104":133,"_23":238,"_106":241,"_141":321},[],{"_21":190,"_35":282,"_37":283,"_129":130,"_131":246,"_102":247,"_104":247,"_23":284,"_106":285,"_141":323},[324],{"_21":187,"_35":188,"_37":189,"_129":130,"_131":190,"_102":191,"_104":191,"_23":192,"_106":189,"_141":325},[326],{"_21":276,"_35":36,"_37":38,"_129":130,"_131":187,"_102":277,"_104":277,"_23":278,"_106":280,"_141":327},[],"videoDislikes",{},"videoLikes",{},"actionData","errors"]

Comentários