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É a quantidade de vapor existente na mistura líquido-vapor em condição de saturação.

",{"_22":66,"_61":67,"_63":68},"c961b0be-4a13-4641-a942-796db7d665a7","B","

É o vapor na temperatura e na pressão de saturação.

",{"_22":19,"_61":70,"_63":71},"C","

É o vapor altamente superaquecido e com estado de equilíbrio longe do de saturação.

","solution_explanation","statement","

Qual definição abaixo descreve o vapor superaquecido:

","status","pending_classification","hasRelatedVideo","relatedVideos",[80],{"_81":82,"_100":101,"_30":116,"_135":136,"_154":155},"content",{"_22":83,"_36":84,"_85":-5,"_86":87,"_88":89,"_90":-5,"_24":91,"_94":95,"_96":95,"_97":-5,"_98":99},"162087be-594f-460e-bbdd-a339ac2f10ad","Calor Latente - Parte 1","description","content_type_id","1051eee7-c62e-4b2c-9900-77a29fcec080","resource_id","f2b62fc2-7079-40e7-a5b5-c4a9769b205d","user_id",{"_92":93},"external_id","3659","created_at","2025-08-20T12:27:41.608438+00:00","updated_at","content_group_id","slug","calor-latente-parte-1","prometheusData",{"_102":103,"_109":110,"_111":112,"_113":114,"_6":115},"provider",{"_22":104,"_105":106,"_107":108},"06f120be-2194-4548-8336-7ba44ffbae14","key","grupo_q_proteus","kind","proteus","reference","bf8aacba-3de9-4b10-961c-47ada80dfe8c","state","completed","thumbnail_url","https://proteus.grupoq.io/videos/bf8aacba-3de9-4b10-961c-47ada80dfe8c/thumbnailsthumb.0000000.jpg","https://proteus.grupoq.io/videos/bf8aacba-3de9-4b10-961c-47ada80dfe8c/levels.m3u8",[117],{"_22":118,"_36":119,"_38":120,"_121":122,"_123":124,"_94":125,"_96":125,"_24":126,"_98":120,"_133":134},"96193fa0-9495-45b2-81cc-b547604354af","Física Térmica - Termologia","fisica-termica-termologia","tag_group_id","c1ce2cf2-b217-4cc7-8182-81c56bd3522d","parent_id","c8ab2a95-fd84-4d6f-ade0-835d34ba00f9","2025-04-29T03:44:27.560682+00:00",{"_127":128,"_129":130,"_131":132},"childrenCount",10,"content_count",0,"question_count",8575,"children",[],"video",{"_22":89,"_137":84,"_85":-5,"_138":139,"_140":141,"_6":-5,"_142":-5,"_102":141,"_143":144,"_113":-5,"_145":-5,"_146":-5,"_147":-5,"_148":-5,"_24":149,"_150":130,"_151":-5,"_75":152,"_94":153,"_96":153},"title","duration",17,"source_type","prometheus","iframe_url","provider_video_id","748a4adb-ad8f-4c5f-88a9-bc522d3b4246","format","quality","file_path","file_size",{"_92":93},"views_count","last_played_at","draft","2025-08-19T11:56:22.11908+00:00","tag",{"_22":118,"_36":119,"_38":120,"_121":122,"_123":124,"_94":125,"_96":125,"_24":156,"_98":120,"_133":157},{"_127":128,"_129":130,"_131":132},[],"similarQuestions",[160,192,212],{"_18":161,"_20":21,"_22":162,"_57":163,"_72":180,"_73":181,"_30":182},"112831da-be9c-458e-94cb-e8292d0dba12","3c0b9441-b878-4896-8bac-fa4ca61e3f13",[164,167,170,173,177],{"_22":165,"_61":62,"_63":166},"265bd71a-6749-41f5-b291-67efd646ca64","y'' + 2y' - 3y = 0",{"_22":168,"_61":67,"_63":169},"6d3c3a1d-8e80-4ff3-b97a-d5b5bca91940","6y'' - y' - y = 0",{"_22":171,"_61":70,"_63":172},"4168ac67-64fd-46ed-a69c-a01dbfcde7ea","y'' - 2y' + y = 0",{"_22":174,"_61":175,"_63":176},"cc7bc8df-6995-4264-ac5a-32ea9b4ed7db","D","9y'' + 6y' + y = 0",{"_22":161,"_61":178,"_63":179},"E","y'' - 2y' + 6y = 0","Somente em y''−2y'+6y=0 o polinômio característico r²−2r+6=0 tem Δ<0, gerando raízes complexas conjugadas (1±i√5) e, portanto, solução em termos de exponencial modulando seno e cosseno. Nos demais itens (a–d) o discriminante é ≥0, produzindo raízes reais (distintas ou repetidas).","

Resolva as seguintes EDOs determinando a solução geral e, quando houver condições iniciais do PVI, a solução particular.

(a) y'' + 2y' - 3y = 0

(b) 6y'' - y' - y = 0

(d) 9y'' + 6y' + y = 0

(e) y'' - 2y' + 6y = 0

(f) 4y'' + 9y = 0

(g) 6y'' - 5y' + y = 0; \\, y(0) = 4; \\, y'(0) = 0

(h) y'' + 4y' + 4y = 0; \\, y(-1) = 2; \\, y'(-1) = 1

(i) y'' + y = 0; \\, y\bigg(\\frac{\\pi}{3}\\bigg) = 2; \\, y'\\bigg(\\frac{\\pi}{3}\\bigg) = -4

(j) y'' - 2y' - 3y = 3e^{2t}

(k) y'' + 9y = t^2 e^{3t} + 6

(l) 2y'' + 3y' + y = t^2 + 3 \\sin(t)

(m) y'' + y' - 2y = 2t; \\, y(0) = 0; \\, y'(0) = 1

(n) y'' - 2y' + y = te^t + 4; \\, y(0) = 1; \\, y'(0) = 1

(o) y'' + 4y = 3 \\sin(2t); \\, y(0) = 2; \\, y'(0) = -1

",[183],{"_22":184,"_36":185,"_38":186,"_121":122,"_123":187,"_94":188,"_96":188,"_24":189,"_98":186},"6516bbbd-f2a3-4710-8382-702240b17836","Mecânica na Engenharia de Petróleo","mecanica-na-engenharia-de-petroleo","b787e438-0ab3-454c-ab43-5d3d14c2720d","2025-04-29T03:44:35.328997+00:00",{"_127":190,"_129":130,"_131":191},4,12302,{"_18":193,"_20":21,"_22":194,"_57":195,"_72":207,"_73":208,"_30":209},"6831a9b9-c9a4-4a76-bd7a-2ce98bfea875","93a32dd4-5fc6-4ccb-a76f-4724bf113742",[196,199,202,204],{"_22":197,"_61":62,"_63":198},"13e3f476-a0a5-421f-b47e-0969e8e9a7e0","

Verdadeiro, verdadeiro, falso

",{"_22":200,"_61":67,"_63":201},"c9a20855-d84b-4860-8b35-9784818282cf","

Falso, verdadeiro, verdadeiro

",{"_22":193,"_61":70,"_63":203},"

Verdadeiro, falso, verdadeiro

",{"_22":205,"_61":175,"_63":206},"3c98539b-1af9-4d44-aecd-c266754a2075","

Falso, falso, falso

","85,5 % decomposto → 14,5 % restante.\nN/N0 = 0,145 ⇒ t = ln(1/0,145)/(ln2/5730) ≈ 1,6×10⁴ anos.\nItens prováveis: (1) resta 14,5 % do C-14 (V); (2) idade ≈ 1,2×10⁴ anos ou 3 meias-vidas (F); (3) t½ do C-14 = 5730 anos (V). Sequência: V-F-V, correspondendo à alternativa c.","

Qual é a idade da madeira na qual 85,5\\% do C-14 se decompos?

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a) ????3 de ????4????5
b) ????2 de ????2????????2
c) ????1 de 2????????1
d) ????1 de 2????2????",[233],{"_22":184,"_36":185,"_38":186,"_121":122,"_123":187,"_94":188,"_96":188,"_24":234,"_98":186},{"_127":190,"_129":130,"_131":191},[236,238,245,255,262,269,271,279,285,290,296,303],{"_22":184,"_36":185,"_38":186,"_121":122,"_123":187,"_94":188,"_96":188,"_24":237,"_98":186},{"_127":190,"_129":130,"_131":191},{"_22":239,"_36":37,"_38":39,"_121":122,"_123":240,"_94":125,"_96":125,"_24":241,"_98":244},"6b6faf95-0e3a-4f58-abc8-e1444c48041d","92339f4f-ed20-4f4c-ad85-0c3de7e04ae0",{"_127":242,"_129":130,"_131":243},2,11846,"termodinamica-3",{"_22":246,"_36":247,"_38":248,"_121":122,"_123":249,"_94":250,"_96":250,"_24":251,"_98":254},"861ad829-750d-4a44-9569-2f18b430b4df","Engenharia Mecatrônica","engenharia-mecatronica","eb9315c5-bd04-4116-aa46-02c4fde320c0","2025-04-29T02:19:12.828432+00:00",{"_127":252,"_129":130,"_131":253},5,30614,"engenharia-mecatronica-1",{"_22":256,"_36":257,"_38":258,"_121":122,"_123":246,"_94":188,"_96":188,"_24":259,"_98":261},"88fe96b3-2a17-4198-90d5-ddda3d6f5d45","Mecânica","mecanica",{"_127":252,"_129":130,"_131":260},25741,"mecanica-3",{"_22":240,"_36":263,"_38":264,"_121":122,"_123":249,"_94":250,"_96":250,"_24":265,"_98":268},"Engenharia Mecânica","engenharia-mecanica",{"_127":266,"_129":130,"_131":267},11,36318,"engenharia-mecanica-2",{"_22":118,"_36":119,"_38":120,"_121":122,"_123":124,"_94":125,"_96":125,"_24":270,"_98":120},{"_127":128,"_129":130,"_131":132},{"_22":272,"_36":273,"_38":274,"_121":122,"_123":-5,"_94":275,"_96":275,"_24":276,"_98":274},"9772e958-72c6-4499-ad47-877cf94d670d","Exatas","exatas","2025-04-29T01:56:45.284172+00:00",{"_127":277,"_129":130,"_131":278},18,135489,{"_22":280,"_36":37,"_38":39,"_121":122,"_123":184,"_94":281,"_96":281,"_24":282,"_98":284},"b21374de-aae5-4a4a-9bf3-0420e731797e","2025-04-29T04:00:14.680867+00:00",{"_127":130,"_129":130,"_131":283},8597,"termodinamica-5",{"_22":187,"_36":286,"_38":287,"_121":122,"_123":249,"_94":250,"_96":250,"_24":288,"_98":289},"Engenharia de Petróleo","engenharia-de-petroleo",{"_127":252,"_129":130,"_131":191},"engenharia-de-petroleo-1",{"_22":124,"_36":291,"_38":292,"_121":122,"_123":272,"_94":250,"_96":250,"_24":293,"_98":295},"Física","fisica",{"_127":266,"_129":130,"_131":294},13777,"fisica-4",{"_22":249,"_36":297,"_38":298,"_121":122,"_123":-5,"_94":299,"_96":299,"_24":300,"_98":298},"Engenharia","engenharia","2025-04-29T01:55:38.635246+00:00",{"_127":301,"_129":130,"_131":302},29,351586,{"_22":304,"_36":37,"_38":39,"_121":122,"_123":256,"_94":305,"_96":305,"_24":306,"_98":307},"f5967cbe-d751-4b40-81f2-04eb5dead2a9","2025-04-29T04:00:13.215003+00:00",{"_127":130,"_129":130,"_131":283},"termodinamica-4","tagsTree",[310,319],{"_22":272,"_36":273,"_38":274,"_121":122,"_123":-5,"_94":275,"_96":275,"_24":311,"_98":274,"_133":312},{"_127":277,"_129":130,"_131":278},[313],{"_22":124,"_36":291,"_38":292,"_121":122,"_123":272,"_94":250,"_96":250,"_24":314,"_98":295,"_133":315},{"_127":266,"_129":130,"_131":294},[316],{"_22":118,"_36":119,"_38":120,"_121":122,"_123":124,"_94":125,"_96":125,"_24":317,"_98":120,"_133":318},{"_127":128,"_129":130,"_131":132},[],{"_22":249,"_36":297,"_38":298,"_121":122,"_123":-5,"_94":299,"_96":299,"_24":320,"_98":298,"_133":321},{"_127":301,"_129":130,"_131":302},[322,331,337],{"_22":246,"_36":247,"_38":248,"_121":122,"_123":249,"_94":250,"_96":250,"_24":323,"_98":254,"_133":324},{"_127":252,"_129":130,"_131":253},[325],{"_22":256,"_36":257,"_38":258,"_121":122,"_123":246,"_94":188,"_96":188,"_24":326,"_98":261,"_133":327},{"_127":252,"_129":130,"_131":260},[328],{"_22":304,"_36":37,"_38":39,"_121":122,"_123":256,"_94":305,"_96":305,"_24":329,"_98":307,"_133":330},{"_127":130,"_129":130,"_131":283},[],{"_22":240,"_36":263,"_38":264,"_121":122,"_123":249,"_94":250,"_96":250,"_24":332,"_98":268,"_133":333},{"_127":266,"_129":130,"_131":267},[334],{"_22":239,"_36":37,"_38":39,"_121":122,"_123":240,"_94":125,"_96":125,"_24":335,"_98":244,"_133":336},{"_127":242,"_129":130,"_131":243},[],{"_22":187,"_36":286,"_38":287,"_121":122,"_123":249,"_94":250,"_96":250,"_24":338,"_98":289,"_133":339},{"_127":252,"_129":130,"_131":191},[340],{"_22":184,"_36":185,"_38":186,"_121":122,"_123":187,"_94":188,"_96":188,"_24":341,"_98":186,"_133":342},{"_127":190,"_129":130,"_131":191},[343],{"_22":280,"_36":37,"_38":39,"_121":122,"_123":184,"_94":281,"_96":281,"_24":344,"_98":284,"_133":345},{"_127":130,"_129":130,"_131":283},[],"videoDislikes",{},"videoLikes",{},"actionData","errors"]

Comentários