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A água é o fluido que, separado, fica submetido a maior pressão. Este fenômeno deve-se à sua maior:","status","pending_classification","hasRelatedVideo","relatedVideos",[109],{"_110":111,"_129":130,"_51":145,"_171":172,"_189":190},"content",{"_43":112,"_57":113,"_114":-5,"_115":116,"_117":118,"_119":-5,"_45":120,"_123":124,"_125":124,"_126":-5,"_127":128},"468e3e62-35e0-47be-a15f-68dd43bb32bb","Óptica Geométrica - Parte 1","description","content_type_id","1051eee7-c62e-4b2c-9900-77a29fcec080","resource_id","fa6aaf42-4cc4-4d76-8915-7a67081f7e9a","user_id",{"_121":122},"external_id","4963","created_at","2025-08-20T12:27:41.608438+00:00","updated_at","content_group_id","slug","optica-geometrica-parte-1","prometheusData",{"_131":132,"_138":139,"_140":141,"_142":143,"_28":144},"provider",{"_43":133,"_134":135,"_136":137},"06f120be-2194-4548-8336-7ba44ffbae14","key","grupo_q_proteus","kind","proteus","reference","d80487a0-0f98-42c8-99bb-551165ba3068","state","completed","thumbnail_url","https://proteus.grupoq.io/videos/d80487a0-0f98-42c8-99bb-551165ba3068/thumbnailsthumb.0000000.jpg","https://proteus.grupoq.io/videos/d80487a0-0f98-42c8-99bb-551165ba3068/levels.m3u8",[146],{"_43":147,"_57":148,"_59":149,"_150":151,"_152":-5,"_123":153,"_125":153,"_45":154,"_127":149,"_161":162},"9772e958-72c6-4499-ad47-877cf94d670d","Exatas","exatas","tag_group_id","c1ce2cf2-b217-4cc7-8182-81c56bd3522d","parent_id","2025-04-29T01:56:45.284172+00:00",{"_155":156,"_157":158,"_159":160},"childrenCount",18,"content_count",0,"question_count",135489,"children",[163],{"_43":164,"_57":58,"_59":60,"_150":151,"_152":147,"_123":165,"_125":165,"_45":166,"_127":169,"_161":170},"ca6fee0e-79c6-4f1c-b500-ee081a071949","2025-04-29T02:19:12.828432+00:00",{"_155":167,"_157":158,"_159":168},10,19948,"mecanica-2",[],"video",{"_43":118,"_13":113,"_114":-5,"_173":174,"_175":176,"_28":-5,"_177":-5,"_131":176,"_178":179,"_142":-5,"_180":-5,"_181":-5,"_182":-5,"_183":-5,"_45":184,"_185":158,"_186":-5,"_104":187,"_123":188,"_125":188},"duration",20,"source_type","prometheus","iframe_url","provider_video_id","1cd3d633-d690-4f4b-9995-9b0e44994e35","format","quality","file_path","file_size",{"_121":122},"views_count","last_played_at","draft","2025-08-19T11:56:20.758718+00:00","tag",{"_43":147,"_57":148,"_59":149,"_150":151,"_152":-5,"_123":153,"_125":153,"_45":191,"_127":149,"_161":192},{"_155":156,"_157":158,"_159":160},[193],{"_43":164,"_57":58,"_59":60,"_150":151,"_152":147,"_123":165,"_125":165,"_45":194,"_127":169,"_161":195},{"_155":167,"_157":158,"_159":168},[],"similarQuestions",[198,228,248],{"_40":199,"_42":41,"_43":200,"_77":201,"_101":216,"_102":217,"_51":218},"112831da-be9c-458e-94cb-e8292d0dba12","3c0b9441-b878-4896-8bac-fa4ca61e3f13",[202,205,208,211,214],{"_43":203,"_81":82,"_83":204},"265bd71a-6749-41f5-b291-67efd646ca64","y'' + 2y' - 3y = 0",{"_43":206,"_81":87,"_83":207},"6d3c3a1d-8e80-4ff3-b97a-d5b5bca91940","6y'' - y' - y = 0",{"_43":209,"_81":91,"_83":210},"4168ac67-64fd-46ed-a69c-a01dbfcde7ea","y'' - 2y' + y = 0",{"_43":212,"_81":95,"_83":213},"cc7bc8df-6995-4264-ac5a-32ea9b4ed7db","9y'' + 6y' + y = 0",{"_43":199,"_81":99,"_83":215},"y'' - 2y' + 6y = 0","Somente em y''−2y'+6y=0 o polinômio característico r²−2r+6=0 tem Δ<0, gerando raízes complexas conjugadas (1±i√5) e, portanto, solução em termos de exponencial modulando seno e cosseno. Nos demais itens (a–d) o discriminante é ≥0, produzindo raízes reais (distintas ou repetidas).","

Resolva as seguintes EDOs determinando a solução geral e, quando houver condições iniciais do PVI, a solução particular.

(a) y'' + 2y' - 3y = 0

(b) 6y'' - y' - y = 0

(d) 9y'' + 6y' + y = 0

(e) y'' - 2y' + 6y = 0

(f) 4y'' + 9y = 0

(g) 6y'' - 5y' + y = 0; \\, y(0) = 4; \\, y'(0) = 0

(h) y'' + 4y' + 4y = 0; \\, y(-1) = 2; \\, y'(-1) = 1

(i) y'' + y = 0; \\, y\bigg(\\frac{\\pi}{3}\\bigg) = 2; \\, y'\\bigg(\\frac{\\pi}{3}\\bigg) = -4

(j) y'' - 2y' - 3y = 3e^{2t}

(k) y'' + 9y = t^2 e^{3t} + 6

(l) 2y'' + 3y' + y = t^2 + 3 \\sin(t)

(m) y'' + y' - 2y = 2t; \\, y(0) = 0; \\, y'(0) = 1

(n) y'' - 2y' + y = te^t + 4; \\, y(0) = 1; \\, y'(0) = 1

(o) y'' + 4y = 3 \\sin(2t); \\, y(0) = 2; \\, y'(0) = -1

",[219],{"_43":220,"_57":221,"_59":222,"_150":151,"_152":223,"_123":165,"_125":165,"_45":224,"_127":227},"861ad829-750d-4a44-9569-2f18b430b4df","Engenharia Mecatrônica","engenharia-mecatronica","eb9315c5-bd04-4116-aa46-02c4fde320c0",{"_155":225,"_157":158,"_159":226},5,30614,"engenharia-mecatronica-1",{"_40":229,"_42":41,"_43":230,"_77":231,"_101":243,"_102":244,"_51":245},"6831a9b9-c9a4-4a76-bd7a-2ce98bfea875","93a32dd4-5fc6-4ccb-a76f-4724bf113742",[232,235,238,240],{"_43":233,"_81":82,"_83":234},"13e3f476-a0a5-421f-b47e-0969e8e9a7e0","

Verdadeiro, verdadeiro, falso

",{"_43":236,"_81":87,"_83":237},"c9a20855-d84b-4860-8b35-9784818282cf","

Falso, verdadeiro, verdadeiro

",{"_43":229,"_81":91,"_83":239},"

Verdadeiro, falso, verdadeiro

",{"_43":241,"_81":95,"_83":242},"3c98539b-1af9-4d44-aecd-c266754a2075","

Falso, falso, falso

","85,5 % decomposto → 14,5 % restante.\nN/N0 = 0,145 ⇒ t = ln(1/0,145)/(ln2/5730) ≈ 1,6×10⁴ anos.\nItens prováveis: (1) resta 14,5 % do C-14 (V); (2) idade ≈ 1,2×10⁴ anos ou 3 meias-vidas (F); (3) t½ do C-14 = 5730 anos (V). Sequência: V-F-V, correspondendo à alternativa c.","

Qual é a idade da madeira na qual 85,5\\% do C-14 se decompos?

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a) ????3 de ????4????5
b) ????2 de ????2????????2
c) ????1 de 2????????1
d) ????1 de 2????2????",[269],{"_43":220,"_57":221,"_59":222,"_150":151,"_152":223,"_123":165,"_125":165,"_45":270,"_127":227},{"_155":225,"_157":158,"_159":226},[272,274,280,282,284],{"_43":220,"_57":221,"_59":222,"_150":151,"_152":223,"_123":165,"_125":165,"_45":273,"_127":227},{"_155":225,"_157":158,"_159":226},{"_43":275,"_57":58,"_59":60,"_150":151,"_152":220,"_123":276,"_125":276,"_45":277,"_127":279},"88fe96b3-2a17-4198-90d5-ddda3d6f5d45","2025-04-29T03:44:35.328997+00:00",{"_155":225,"_157":158,"_159":278},25741,"mecanica-3",{"_43":147,"_57":148,"_59":149,"_150":151,"_152":-5,"_123":153,"_125":153,"_45":281,"_127":149},{"_155":156,"_157":158,"_159":160},{"_43":164,"_57":58,"_59":60,"_150":151,"_152":147,"_123":165,"_125":165,"_45":283,"_127":169},{"_155":167,"_157":158,"_159":168},{"_43":223,"_57":285,"_59":286,"_150":151,"_152":-5,"_123":287,"_125":287,"_45":288,"_127":286},"Engenharia","engenharia","2025-04-29T01:55:38.635246+00:00",{"_155":289,"_157":158,"_159":290},29,351586,"tagsTree",[293,299],{"_43":147,"_57":148,"_59":149,"_150":151,"_152":-5,"_123":153,"_125":153,"_45":294,"_127":149,"_161":295},{"_155":156,"_157":158,"_159":160},[296],{"_43":164,"_57":58,"_59":60,"_150":151,"_152":147,"_123":165,"_125":165,"_45":297,"_127":169,"_161":298},{"_155":167,"_157":158,"_159":168},[],{"_43":223,"_57":285,"_59":286,"_150":151,"_152":-5,"_123":287,"_125":287,"_45":300,"_127":286,"_161":301},{"_155":289,"_157":158,"_159":290},[302],{"_43":220,"_57":221,"_59":222,"_150":151,"_152":223,"_123":165,"_125":165,"_45":303,"_127":227,"_161":304},{"_155":225,"_157":158,"_159":226},[305],{"_43":275,"_57":58,"_59":60,"_150":151,"_152":220,"_123":276,"_125":276,"_45":306,"_127":279,"_161":307},{"_155":225,"_157":158,"_159":278},[],"videoDislikes",{},"videoLikes",{},"actionData","errors"]

Comentários