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Uma viga carregada é posicionada sobre o topo de dois prédios. Substitua o carregamento distribuído por uma força resultante equivalente e especifique sua posição na viga, medindo a partir de A.

","status","published","hasRelatedVideo","relatedVideos",[99],{"_100":101,"_119":120,"_31":135,"_170":171,"_189":190},"content",{"_23":102,"_37":103,"_104":-5,"_105":106,"_107":108,"_109":-5,"_25":110,"_113":114,"_115":114,"_116":-5,"_117":118},"468e3e62-35e0-47be-a15f-68dd43bb32bb","Óptica Geométrica - Parte 1","description","content_type_id","1051eee7-c62e-4b2c-9900-77a29fcec080","resource_id","fa6aaf42-4cc4-4d76-8915-7a67081f7e9a","user_id",{"_111":112},"external_id","4963","created_at","2025-08-20T12:27:41.608438+00:00","updated_at","content_group_id","slug","optica-geometrica-parte-1","prometheusData",{"_121":122,"_128":129,"_130":131,"_132":133,"_6":134},"provider",{"_23":123,"_124":125,"_126":127},"06f120be-2194-4548-8336-7ba44ffbae14","key","grupo_q_proteus","kind","proteus","reference","d80487a0-0f98-42c8-99bb-551165ba3068","state","completed","thumbnail_url","https://proteus.grupoq.io/videos/d80487a0-0f98-42c8-99bb-551165ba3068/thumbnailsthumb.0000000.jpg","https://proteus.grupoq.io/videos/d80487a0-0f98-42c8-99bb-551165ba3068/levels.m3u8",[136],{"_23":137,"_37":138,"_39":139,"_140":141,"_142":-5,"_113":143,"_115":143,"_25":144,"_117":139,"_151":152},"9772e958-72c6-4499-ad47-877cf94d670d","Exatas","exatas","tag_group_id","c1ce2cf2-b217-4cc7-8182-81c56bd3522d","parent_id","2025-04-29T01:56:45.284172+00:00",{"_145":146,"_147":148,"_149":150},"childrenCount",18,"content_count",0,"question_count",135489,"children",[153],{"_23":154,"_37":155,"_39":156,"_140":141,"_142":137,"_113":157,"_115":157,"_25":158,"_117":161,"_151":162},"ca6fee0e-79c6-4f1c-b500-ee081a071949","Mecânica","mecanica","2025-04-29T02:19:12.828432+00:00",{"_145":159,"_147":148,"_149":160},10,19948,"mecanica-2",[163],{"_23":164,"_37":38,"_39":40,"_140":141,"_142":154,"_113":165,"_115":165,"_25":166,"_117":168,"_151":169},"ac55bdba-154d-42e7-bc25-72dde822663d","2025-04-29T03:44:29.139762+00:00",{"_145":148,"_147":148,"_149":167},3376,"resistencia-dos-materiais-4",[],"video",{"_23":108,"_172":103,"_104":-5,"_173":174,"_175":176,"_6":-5,"_177":-5,"_121":176,"_178":179,"_132":-5,"_180":-5,"_181":-5,"_182":-5,"_183":-5,"_25":184,"_185":148,"_186":-5,"_94":187,"_113":188,"_115":188},"title","duration",20,"source_type","prometheus","iframe_url","provider_video_id","1cd3d633-d690-4f4b-9995-9b0e44994e35","format","quality","file_path","file_size",{"_111":112},"views_count","last_played_at","draft","2025-08-19T11:56:20.758718+00:00","tag",{"_23":137,"_37":138,"_39":139,"_140":141,"_142":-5,"_113":143,"_115":143,"_25":191,"_117":139,"_151":192},{"_145":146,"_147":148,"_149":150},[193],{"_23":154,"_37":155,"_39":156,"_140":141,"_142":137,"_113":157,"_115":157,"_25":194,"_117":161,"_151":195},{"_145":159,"_147":148,"_149":160},[196],{"_23":164,"_37":38,"_39":40,"_140":141,"_142":154,"_113":165,"_115":165,"_25":197,"_117":168,"_151":198},{"_145":148,"_147":148,"_149":167},[],"similarQuestions",[201,232,252],{"_19":202,"_21":22,"_23":203,"_71":204,"_90":220,"_92":221,"_31":222},"112831da-be9c-458e-94cb-e8292d0dba12","3c0b9441-b878-4896-8bac-fa4ca61e3f13",[205,208,211,214,217],{"_23":206,"_74":75,"_76":207},"265bd71a-6749-41f5-b291-67efd646ca64","y'' + 2y' - 3y = 0",{"_23":209,"_74":80,"_76":210},"6d3c3a1d-8e80-4ff3-b97a-d5b5bca91940","6y'' - y' - y = 0",{"_23":212,"_74":84,"_76":213},"4168ac67-64fd-46ed-a69c-a01dbfcde7ea","y'' - 2y' + y = 0",{"_23":215,"_74":88,"_76":216},"cc7bc8df-6995-4264-ac5a-32ea9b4ed7db","9y'' + 6y' + y = 0",{"_23":202,"_74":218,"_76":219},"E","y'' - 2y' + 6y = 0","Somente em y''−2y'+6y=0 o polinômio característico r²−2r+6=0 tem Δ<0, gerando raízes complexas conjugadas (1±i√5) e, portanto, solução em termos de exponencial modulando seno e cosseno. Nos demais itens (a–d) o discriminante é ≥0, produzindo raízes reais (distintas ou repetidas).","

Resolva as seguintes EDOs determinando a solução geral e, quando houver condições iniciais do PVI, a solução particular.

(a) y'' + 2y' - 3y = 0

(b) 6y'' - y' - y = 0

(d) 9y'' + 6y' + y = 0

(e) y'' - 2y' + 6y = 0

(f) 4y'' + 9y = 0

(g) 6y'' - 5y' + y = 0; \\, y(0) = 4; \\, y'(0) = 0

(h) y'' + 4y' + 4y = 0; \\, y(-1) = 2; \\, y'(-1) = 1

(i) y'' + y = 0; \\, y\bigg(\\frac{\\pi}{3}\\bigg) = 2; \\, y'\\bigg(\\frac{\\pi}{3}\\bigg) = -4

(j) y'' - 2y' - 3y = 3e^{2t}

(k) y'' + 9y = t^2 e^{3t} + 6

(l) 2y'' + 3y' + y = t^2 + 3 \\sin(t)

(m) y'' + y' - 2y = 2t; \\, y(0) = 0; \\, y'(0) = 1

(n) y'' - 2y' + y = te^t + 4; \\, y(0) = 1; \\, y'(0) = 1

(o) y'' + 4y = 3 \\sin(2t); \\, y(0) = 2; \\, y'(0) = -1

",[223],{"_23":224,"_37":225,"_39":226,"_140":141,"_142":227,"_113":228,"_115":228,"_25":229,"_117":226},"6516bbbd-f2a3-4710-8382-702240b17836","Mecânica na Engenharia de Petróleo","mecanica-na-engenharia-de-petroleo","b787e438-0ab3-454c-ab43-5d3d14c2720d","2025-04-29T03:44:35.328997+00:00",{"_145":230,"_147":148,"_149":231},4,12302,{"_19":233,"_21":22,"_23":234,"_71":235,"_90":247,"_92":248,"_31":249},"6831a9b9-c9a4-4a76-bd7a-2ce98bfea875","93a32dd4-5fc6-4ccb-a76f-4724bf113742",[236,239,242,244],{"_23":237,"_74":75,"_76":238},"13e3f476-a0a5-421f-b47e-0969e8e9a7e0","

Verdadeiro, verdadeiro, falso

",{"_23":240,"_74":80,"_76":241},"c9a20855-d84b-4860-8b35-9784818282cf","

Falso, verdadeiro, verdadeiro

",{"_23":233,"_74":84,"_76":243},"

Verdadeiro, falso, verdadeiro

",{"_23":245,"_74":88,"_76":246},"3c98539b-1af9-4d44-aecd-c266754a2075","

Falso, falso, falso

","85,5 % decomposto → 14,5 % restante.\nN/N0 = 0,145 ⇒ t = ln(1/0,145)/(ln2/5730) ≈ 1,6×10⁴ anos.\nItens prováveis: (1) resta 14,5 % do C-14 (V); (2) idade ≈ 1,2×10⁴ anos ou 3 meias-vidas (F); (3) t½ do C-14 = 5730 anos (V). Sequência: V-F-V, correspondendo à alternativa c.","

Qual é a idade da madeira na qual 85,5\\% do C-14 se decompos?

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a) ????3 de ????4????5
b) ????2 de ????2????????2
c) ????1 de 2????????1
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Comentários