[{"_1":2,"_253":-5,"_254":-5},"loaderData",{"_3":4,"_31":32},"root",{"_5":6,"_28":29,"_30":-5},"registerModalConfig",{"_7":8,"_15":16},"blockedConfig",{"_9":10,"_15":16,"_17":18,"_21":22,"_24":25},"answerQuestion",{"_11":12,"_13":14},"subtitle","Crie sua conta gratuita e utilize todos os nossos recursos de questões disponiveis","title","Para responder, cadastre-se gratuitamente","customBlockedUI",true,"defaultRegister",{"_11":19,"_13":20},"Crie sua conta gratuita e utilize todos os nossos recursos disponíveis","Cadastre-se gratuitamente","imageSearch",{"_11":19,"_13":23},"Para buscar por imagem, cadastre-se gratuitamente","questionAnswer",{"_11":26,"_13":27},"Crie sua conta gratuita e utilize todos os nossos recursos disponíveis para responder","Para ver a resposta, cadastre-se gratuitamente","url","https://prouniversitario.com/exercicios/f98d57d5-9ff1-4e76-b3ab-a9dc9cd5a695?video=true","user","pages/questions/show/index",{"_33":34,"_35":36,"_37":36,"_38":39,"_103":104,"_203":204,"_52":243,"_247":248,"_249":250,"_251":252},"comments",[],"hasVideoHash",false,"isAiGenerated","question",{"_40":41,"_42":43,"_44":45,"_46":47,"_78":79,"_97":43,"_98":99,"_100":101,"_102":16},"correctOptionId","81683011-48b7-4475-ae98-8ab8e739af5b","difficulty","","id","f98d57d5-9ff1-4e76-b3ab-a9dc9cd5a695","metadata",{"_48":49,"_74":75,"_76":77},"pd",{"_50":51,"_52":53,"_54":55,"_62":63,"_64":65,"_66":16,"_67":68,"_69":16,"_70":71,"_72":73},"area","Outros","tags",[],"subjects",[56],{"_44":57,"_58":59,"_60":61},147389057,"name","Eletrônicos","alias","eletronicos","materialId","139333846","answerCount",1,"isIndexable","mainSubject",{"_44":57,"_58":59,"_60":61},"isIndexableSEO","materialFormat","Text","studentDegreeLevel","Graduate","source","PD","externalId","139383002","options",[80,86,90,93],{"_44":81,"_82":83,"_84":85},"eccb55a3-be10-459a-8263-1c08dbc6a432","label","A","text","Diversity is boring",{"_44":87,"_82":88,"_84":89},"fcff49ab-db6e-4405-8aa3-458b06df498d","B","People can’t be different",{"_44":41,"_82":91,"_84":92},"C","What is diversity?",{"_44":94,"_82":95,"_84":96},"998b32f8-40bd-4588-8bd7-f662a1d9a644","D","How uninteresting the world is!","solution_explanation","statement","

Assinale a alternativa que apresenta um título adequado para o texto:

","status","pending_classification","hasRelatedVideo","relatedVideos",[105],{"_106":107,"_125":126,"_52":141,"_184":185,"_202":142},"content",{"_44":108,"_58":109,"_110":-5,"_111":112,"_113":114,"_115":-5,"_46":116,"_119":120,"_121":120,"_122":-5,"_123":124},"468e3e62-35e0-47be-a15f-68dd43bb32bb","Óptica Geométrica - Parte 1","description","content_type_id","1051eee7-c62e-4b2c-9900-77a29fcec080","resource_id","fa6aaf42-4cc4-4d76-8915-7a67081f7e9a","user_id",{"_117":118},"external_id","4963","created_at","2025-08-20T12:27:41.608438+00:00","updated_at","content_group_id","slug","optica-geometrica-parte-1","prometheusData",{"_127":128,"_134":135,"_136":137,"_138":139,"_28":140},"provider",{"_44":129,"_130":131,"_132":133},"06f120be-2194-4548-8336-7ba44ffbae14","key","grupo_q_proteus","kind","proteus","reference","d80487a0-0f98-42c8-99bb-551165ba3068","state","completed","thumbnail_url","https://proteus.grupoq.io/videos/d80487a0-0f98-42c8-99bb-551165ba3068/thumbnailsthumb.0000000.jpg","https://proteus.grupoq.io/videos/d80487a0-0f98-42c8-99bb-551165ba3068/levels.m3u8",[142],{"_44":143,"_58":144,"_60":145,"_146":147,"_148":-5,"_119":149,"_121":149,"_46":150,"_123":145,"_157":158},"9772e958-72c6-4499-ad47-877cf94d670d","Exatas","exatas","tag_group_id","c1ce2cf2-b217-4cc7-8182-81c56bd3522d","parent_id","2025-04-29T01:56:45.284172+00:00",{"_151":152,"_153":154,"_155":156},"childrenCount",18,"content_count",0,"question_count",135489,"children",[159],{"_44":160,"_58":161,"_60":162,"_146":147,"_148":143,"_119":163,"_121":163,"_46":164,"_123":167,"_157":168},"94712427-655a-4d3f-a9a4-c17abbad6f90","Mecatrônica","mecatronica","2025-04-29T02:19:12.828432+00:00",{"_151":165,"_153":154,"_155":166},5,12419,"mecatronica-1",[169],{"_44":170,"_58":171,"_60":172,"_146":147,"_148":160,"_119":173,"_121":173,"_46":174,"_123":172,"_157":176},"5e92796e-abab-4cd6-903d-33ded7476005","Eletrônica em Mecatrônica","eletronica-em-mecatronica","2025-04-29T03:44:35.328997+00:00",{"_151":175,"_153":154,"_155":166},4,[177],{"_44":178,"_58":179,"_60":180,"_146":147,"_148":170,"_119":181,"_121":181,"_46":182,"_123":180,"_157":183},"65b59c47-5208-4b07-9a93-2b5eb61935bd","Equipamentos Eletrônicos","equipamentos-eletronicos","2025-04-29T04:00:14.680867+00:00",{"_151":154,"_153":154,"_155":166},[],"video",{"_44":114,"_13":109,"_110":-5,"_186":187,"_188":189,"_28":-5,"_190":-5,"_127":189,"_191":192,"_138":-5,"_193":-5,"_194":-5,"_195":-5,"_196":-5,"_46":197,"_198":154,"_199":-5,"_100":200,"_119":201,"_121":201},"duration",20,"source_type","prometheus","iframe_url","provider_video_id","1cd3d633-d690-4f4b-9995-9b0e44994e35","format","quality","file_path","file_size",{"_117":118},"views_count","last_played_at","draft","2025-08-19T11:56:20.758718+00:00","tag","similarQuestions",[205,227],{"_40":206,"_42":43,"_44":207,"_78":208,"_97":43,"_98":224,"_52":225},"47350bfb-e216-4512-8208-9013b4ef0e82","65d40c69-79b9-4d49-b7f1-60bf496e45c2",[209,212,214,217,220],{"_44":210,"_82":83,"_84":211},"92b2721e-2598-4aa3-9818-117bcc898838","

Conversor A/C.

",{"_44":206,"_82":88,"_84":213},"

Conversor D/A.

",{"_44":215,"_82":91,"_84":216},"b0a43708-2eaa-431e-9f5a-5e670c310b88","

Conversor DC/AC.

",{"_44":218,"_82":95,"_84":219},"621496f0-8bcd-4170-ac79-f029b61cf7c4","

Conversor AC/DC.

",{"_44":221,"_82":222,"_84":223},"82beb153-62b5-4492-a5b4-4b250e984761","E","

Nenhuma das respostas acima.

","

Para a conversão de sinais digitais para analógicos, necessitamos de circuitos ou chips denominados:

",[226],{"_44":170,"_58":171,"_60":172,"_146":147,"_148":160,"_119":173,"_121":173,"_46":174,"_123":172},{"_40":228,"_42":43,"_44":229,"_78":230,"_97":240,"_98":241,"_52":242},"22d7bbd3-763e-4f0a-b27b-99a913a98b51","b72f32d4-8e5c-4b78-8ca1-fffb9133beaf",[231,233,234,236,238],{"_44":232,"_82":83,"_84":83},"0d271c5e-75f4-4f80-9070-ec6e61f920b4",{"_44":228,"_82":88,"_84":88},{"_44":235,"_82":91,"_84":91},"b0005922-c0f4-41ed-b76f-782d257efeca",{"_44":237,"_82":95,"_84":95},"09ae6274-a5a4-4dd6-b758-fd3d202facb4",{"_44":239,"_82":222,"_84":222},"79575e01-cc80-4c53-8122-bc3a7a15ac9a","Segundo o gabarito oficial divulgado pela CESGRANRIO para o concurso PETROBRAS de 02/05/2010 (Engenheiro de Equipamentos Pleno – Ênfase Eletricidade), a alternativa assinalada como correta na questão 50 é a letra B.","

Qual é a resposta correta para a questão 50 do exame realizado em 02/05/2010 para o cargo de ENGENHEIRO(A) DE EQUIPAMENTOS PLENO ÊNFASE EM ELETRICIDADE, de acordo com a seguinte chave de respostas?

",[226],[226,244,245,246],{"_44":178,"_58":179,"_60":180,"_146":147,"_148":170,"_119":181,"_121":181,"_46":182,"_123":180},{"_44":160,"_58":161,"_60":162,"_146":147,"_148":143,"_119":163,"_121":163,"_46":164,"_123":167},{"_44":143,"_58":144,"_60":145,"_146":147,"_148":-5,"_119":149,"_121":149,"_46":150,"_123":145},"tagsTree",[142],"videoDislikes",{},"videoLikes",{},"actionData","errors"]

Comentários