[{"_1":2,"_201":-5,"_202":-5},"loaderData",{"_3":4,"_9":10},"root",{"_5":-5,"_6":7,"_8":-5},"registerModalConfig","url","https://prouniversitario.com/exercicios/fa69f84e-1f41-401a-95f6-7ee1577f6a5a","user","pages/questions/show/index",{"_11":12,"_13":14,"_15":14,"_16":17,"_78":79,"_80":81,"_29":164,"_186":187,"_197":198,"_199":200},"comments",[],"hasVideoHash",false,"isAiGenerated","question",{"_18":19,"_20":19,"_21":22,"_23":24,"_56":57,"_72":19,"_73":74,"_75":76,"_77":14},"correctOptionId","","difficulty","id","fa69f84e-1f41-401a-95f6-7ee1577f6a5a","metadata",{"_25":26,"_52":53,"_54":55},"pd",{"_27":28,"_29":30,"_31":32,"_39":40,"_41":42,"_43":44,"_45":46,"_47":14,"_48":49,"_50":51},"area","Outros","tags",[],"subjects",[33],{"_21":34,"_35":36,"_37":38},678643,"name","Análise Estrutural","alias","analise-estrutural","materialId","129668246","answerCount",1,"isIndexable",true,"mainSubject",{"_21":34,"_35":36,"_37":38},"isIndexableSEO","materialFormat","Text","studentDegreeLevel","Graduate","source","PD","externalId","129668318","options",[58,64,68],{"_21":59,"_60":61,"_62":63},"72db1c73-8f7d-4b89-a72b-54fb202822b6","label","A","text","

Develop critical thinking skills in relation to artistic languages;

",{"_21":65,"_60":66,"_62":67},"1266bbb8-c956-479c-9745-355e30ae3ef8","B","

Develop creative thinking skills in relation to artistic languages;

",{"_21":69,"_60":70,"_62":71},"0b8ede96-6cf0-467e-8b7b-f4650586a88b","C","

Develop critical and creative thinking skills in relation to artistic languages, and understand the elements of different artistic languages, such as theater, music, and dance.

","solution_explanation","statement","

What is the objective of the following curriculum unit?

","status","pending_classification","hasRelatedVideo","relatedVideos",[],"similarQuestions",[82,125,143],{"_18":83,"_20":19,"_21":84,"_56":85,"_72":102,"_73":103,"_29":104},"112831da-be9c-458e-94cb-e8292d0dba12","3c0b9441-b878-4896-8bac-fa4ca61e3f13",[86,89,92,95,99],{"_21":87,"_60":61,"_62":88},"265bd71a-6749-41f5-b291-67efd646ca64","y'' + 2y' - 3y = 0",{"_21":90,"_60":66,"_62":91},"6d3c3a1d-8e80-4ff3-b97a-d5b5bca91940","6y'' - y' - y = 0",{"_21":93,"_60":70,"_62":94},"4168ac67-64fd-46ed-a69c-a01dbfcde7ea","y'' - 2y' + y = 0",{"_21":96,"_60":97,"_62":98},"cc7bc8df-6995-4264-ac5a-32ea9b4ed7db","D","9y'' + 6y' + y = 0",{"_21":83,"_60":100,"_62":101},"E","y'' - 2y' + 6y = 0","Somente em y''−2y'+6y=0 o polinômio característico r²−2r+6=0 tem Δ<0, gerando raízes complexas conjugadas (1±i√5) e, portanto, solução em termos de exponencial modulando seno e cosseno. Nos demais itens (a–d) o discriminante é ≥0, produzindo raízes reais (distintas ou repetidas).","

Resolva as seguintes EDOs determinando a solução geral e, quando houver condições iniciais do PVI, a solução particular.

(a) y'' + 2y' - 3y = 0

(b) 6y'' - y' - y = 0

(d) 9y'' + 6y' + y = 0

(e) y'' - 2y' + 6y = 0

(f) 4y'' + 9y = 0

(g) 6y'' - 5y' + y = 0; \\, y(0) = 4; \\, y'(0) = 0

(h) y'' + 4y' + 4y = 0; \\, y(-1) = 2; \\, y'(-1) = 1

(i) y'' + y = 0; \\, y\bigg(\\frac{\\pi}{3}\\bigg) = 2; \\, y'\\bigg(\\frac{\\pi}{3}\\bigg) = -4

(j) y'' - 2y' - 3y = 3e^{2t}

(k) y'' + 9y = t^2 e^{3t} + 6

(l) 2y'' + 3y' + y = t^2 + 3 \\sin(t)

(m) y'' + y' - 2y = 2t; \\, y(0) = 0; \\, y'(0) = 1

(n) y'' - 2y' + y = te^t + 4; \\, y(0) = 1; \\, y'(0) = 1

(o) y'' + 4y = 3 \\sin(2t); \\, y(0) = 2; \\, y'(0) = -1

",[105],{"_21":106,"_35":107,"_37":108,"_109":110,"_111":112,"_113":114,"_115":114,"_23":116,"_123":124},"b6e37f32-f8e5-4025-bf0f-69ffc00fb331","Engenharia Civil","engenharia-civil","tag_group_id","c1ce2cf2-b217-4cc7-8182-81c56bd3522d","parent_id","eb9315c5-bd04-4116-aa46-02c4fde320c0","created_at","2025-04-29T02:19:12.828432+00:00","updated_at",{"_117":118,"_119":120,"_121":122},"childrenCount",21,"content_count",0,"question_count",45865,"slug","engenharia-civil-3",{"_18":126,"_20":19,"_21":127,"_56":128,"_72":140,"_73":141,"_29":142},"6831a9b9-c9a4-4a76-bd7a-2ce98bfea875","93a32dd4-5fc6-4ccb-a76f-4724bf113742",[129,132,135,137],{"_21":130,"_60":61,"_62":131},"13e3f476-a0a5-421f-b47e-0969e8e9a7e0","

Verdadeiro, verdadeiro, falso

",{"_21":133,"_60":66,"_62":134},"c9a20855-d84b-4860-8b35-9784818282cf","

Falso, verdadeiro, verdadeiro

",{"_21":126,"_60":70,"_62":136},"

Verdadeiro, falso, verdadeiro

",{"_21":138,"_60":97,"_62":139},"3c98539b-1af9-4d44-aecd-c266754a2075","

Falso, falso, falso

","85,5 % decomposto → 14,5 % restante.\nN/N0 = 0,145 ⇒ t = ln(1/0,145)/(ln2/5730) ≈ 1,6×10⁴ anos.\nItens prováveis: (1) resta 14,5 % do C-14 (V); (2) idade ≈ 1,2×10⁴ anos ou 3 meias-vidas (F); (3) t½ do C-14 = 5730 anos (V). Sequência: V-F-V, correspondendo à alternativa c.","

Qual é a idade da madeira na qual 85,5\\% do C-14 se decompos?

",[105],{"_18":144,"_20":19,"_21":145,"_56":146,"_72":161,"_73":162,"_29":163},"3ce109b1-6cdb-4b4d-8816-a6af4d74bed0","c478a46c-46a8-4942-ae14-2e79def3dda2",[147,150,153,155,158],{"_21":148,"_60":61,"_62":149},"a5a16a42-3e58-4c76-80f2-c291aa2d8e49","Sim",{"_21":151,"_60":66,"_62":152},"5e6d0254-696c-4da0-b572-82e3a19f433e","Não",{"_21":144,"_60":70,"_62":154},"Indeterminado",{"_21":156,"_60":97,"_62":157},"35403f68-a880-429d-97f4-db507c58de38","Todos",{"_21":159,"_60":100,"_62":160},"2e06d948-d37e-4350-afc7-ced04941bcaf","Nenhum","Os polinômios e números fornecidos estão corrompidos (símbolos “????”), impossibilitando aplicar Ruffini e concluir se são raízes. Sem dados completos, o problema é indeterminado.","Emplea la regla de Ruffini para dictaminar si los siguientes números son o no raíces de los polinomios citados:
a) ????3 de ????4????5
b) ????2 de ????2????????2
c) ????1 de 2????????1
d) ????1 de 2????2????",[105],[105,165,174,179],{"_21":166,"_35":167,"_37":168,"_109":110,"_111":106,"_113":169,"_115":169,"_23":170,"_123":173},"c5bf57d4-c3d8-4365-b53e-085fa14a3a95","Estruturas","estruturas","2025-04-29T03:44:32.303369+00:00",{"_117":171,"_119":120,"_121":172},5,8852,"estruturas-1",{"_21":175,"_35":36,"_37":38,"_109":110,"_111":166,"_113":176,"_115":176,"_23":177,"_123":38},"e9d666f5-dcb8-4aa3-abc7-27cfb929e3b6","2025-04-29T04:00:06.9766+00:00",{"_117":120,"_119":120,"_121":178},4694,{"_21":112,"_35":180,"_37":181,"_109":110,"_111":-5,"_113":182,"_115":182,"_23":183,"_123":181},"Engenharia","engenharia","2025-04-29T01:55:38.635246+00:00",{"_117":184,"_119":120,"_121":185},29,351586,"tagsTree",[188],{"_21":112,"_35":180,"_37":181,"_109":110,"_111":-5,"_113":182,"_115":182,"_23":183,"_123":181,"_189":190},"children",[191],{"_21":106,"_35":107,"_37":108,"_109":110,"_111":112,"_113":114,"_115":114,"_23":116,"_123":124,"_189":192},[193],{"_21":166,"_35":167,"_37":168,"_109":110,"_111":106,"_113":169,"_115":169,"_23":170,"_123":173,"_189":194},[195],{"_21":175,"_35":36,"_37":38,"_109":110,"_111":166,"_113":176,"_115":176,"_23":177,"_123":38,"_189":196},[],"videoDislikes",{},"videoLikes",{},"actionData","errors"]

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